कौन सा निष्कर्ष \(x^0+\sqrt{2}x^5-\frac{4x^2}{9}\) के लिए सही है?

Which conclusion is correct for \(x^0+\sqrt{2}x^5-\frac{4x^2}{9}\)?

Explanation opens after your attempt
Correct Answer

B. यह बहुपद है और डिग्री (5) हैIt is a polynomial and degree is (5)

Step 1

Concept

\(\sqrt{2}\) and \(-\frac{4}{9}\) are real coefficients. The powers of (x) are (0), (5), and (2).

Step 2

Why this answer is correct

The correct answer is B. यह बहुपद है और डिग्री (5) है / It is a polynomial and degree is (5). \(\sqrt{2}\) and \(-\frac{4}{9}\) are real coefficients. The powers of (x) are (0), (5), and (2).

Step 3

Exam Tip

\(\sqrt{2}\) और \(-\frac{4}{9}\) वास्तविक गुणांक हैं। (x) की घातें (0), (5), और (2) हैं।

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Mathematics Answer, Explanation and Revision Hints

कौन सा निष्कर्ष \(x^0+\sqrt{2}x^5-\frac{4x^2}{9}\) के लिए सही है? / Which conclusion is correct for \(x^0+\sqrt{2}x^5-\frac{4x^2}{9}\)?

Correct Answer: B. यह बहुपद है और डिग्री (5) है / It is a polynomial and degree is (5). Explanation: \(\sqrt{2}\) और \(-\frac{4}{9}\) वास्तविक गुणांक हैं। (x) की घातें (0), (5), और (2) हैं। / \(\sqrt{2}\) and \(-\frac{4}{9}\) are real coefficients. The powers of (x) are (0), (5), and (2).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{2}\) and \(-\frac{4}{9}\) are real coefficients. The powers of (x) are (0), (5), and (2).

What exam hint can help solve this Mathematics question?

\(\sqrt{2}\) और \(-\frac{4}{9}\) वास्तविक गुणांक हैं। (x) की घातें (0), (5), और (2) हैं।