व्यंजक \(3x^2+\sqrt{2x-1}\) बहुपद क्यों नहीं है?

Why is \(3x^2+\sqrt{2x-1}\) not a polynomial?

Explanation opens after your attempt
Correct Answer

C. क्योंकि (2x-1) मूल चिह्न के अंदर हैBecause (2x-1) is inside a radical sign

Step 1

Concept

\(\sqrt{2x-1}\) is not a term with valid polynomial powers. Therefore the whole expression is not a polynomial.

Step 2

Why this answer is correct

The correct answer is C. क्योंकि (2x-1) मूल चिह्न के अंदर है / Because (2x-1) is inside a radical sign. \(\sqrt{2x-1}\) is not a term with valid polynomial powers. Therefore the whole expression is not a polynomial.

Step 3

Exam Tip

\(\sqrt{2x-1}\) बहुपद की मान्य घातों वाला पद नहीं है। इसलिए पूरा व्यंजक बहुपद नहीं है।

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Mathematics Answer, Explanation and Revision Hints

व्यंजक \(3x^2+\sqrt{2x-1}\) बहुपद क्यों नहीं है? / Why is \(3x^2+\sqrt{2x-1}\) not a polynomial?

Correct Answer: C. क्योंकि (2x-1) मूल चिह्न के अंदर है / Because (2x-1) is inside a radical sign. Explanation: \(\sqrt{2x-1}\) बहुपद की मान्य घातों वाला पद नहीं है। इसलिए पूरा व्यंजक बहुपद नहीं है। / \(\sqrt{2x-1}\) is not a term with valid polynomial powers. Therefore the whole expression is not a polynomial.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{2x-1}\) is not a term with valid polynomial powers. Therefore the whole expression is not a polynomial.

What exam hint can help solve this Mathematics question?

\(\sqrt{2x-1}\) बहुपद की मान्य घातों वाला पद नहीं है। इसलिए पूरा व्यंजक बहुपद नहीं है।