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3 results found for "number-31104" in Class 10.

Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

किस संख्या का अभाज्य गुणनखंडन \(2^7\times3^5\) है?

Which number has prime factorisation \(2^7\times3^5\)?

Explanation opens after your attempt
Correct Answer

A. 31104

Step 1

Concept

Calculate \(2^7=128\) and \(3^5=243\).

Step 2

Why this answer is correct

\(128\times243=31104\).

Step 3

Exam Tip

Simplifying both powers first is the correct method. चरण 1: \(2^7=128\) और \(3^5=243\) निकालें। चरण 2: \(128\times243=31104\)। चरण 3: दोनों घातों को पहले सरल करना सही तरीका है।

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Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

यदि \(31104=2^7\times3^b\), तो (b) का मान क्या है?

If \(31104=2^7\times3^b\), what is the value of (b)?

Explanation opens after your attempt
Correct Answer

A. 5

Step 1

Concept

Write \(31104=128\times243\).

Step 2

Why this answer is correct

\(128=2^7\) and \(243=3^5\), so \(31104=2^7\times3^5\).

Step 3

Exam Tip

Comparing with the given form gives (b=5). चरण 1: \(31104=128\times243\) लिखें। चरण 2: \(128=2^7\) और \(243=3^5\), इसलिए \(31104=2^7\times3^5\)। चरण 3: दिए गए रूप से तुलना करने पर (b=5) है।

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Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 31104 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 31104?

Explanation opens after your attempt
Correct Answer

A. \(2^7\times3^5\)

Step 1

Concept

Write \(31104=128\times243\).

Step 2

Why this answer is correct

\(128=2^7\) and \(243=3^5\), so \(31104=2^7\times3^5\).

Step 3

Exam Tip

128 and 243 are composite, so keep prime bases. चरण 1: \(31104=128\times243\) लिखें। चरण 2: \(128=2^7\) और \(243=3^5\), इसलिए \(31104=2^7\times3^5\)। चरण 3: 128 और 243 संयुक्त हैं, इसलिए अभाज्य आधार रखें।

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