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The difference between the square of a positive number and 20 times the number is 621. What is the number?

Answer and explanation

Correct answer: \(10+\sqrt{721}\)

Let the number be \(x\). Then \(x^2-20x=621\), so \(x^2-20x-621=0\). Using the quadratic formula, \(x=\frac{20\pm\sqrt{400+2484}}{2}=10\pm\sqrt{721}\). Since the number is positive and \(10-\sqrt{721}<0\), the required value is \(10+\sqrt{721}\). Exam tip: translate the word statement into a quadratic equation first, then use the given condition, such as positivity, to select the valid root.

Related tags

Quadratic EquationsWord ProblemsQuadratic FormulaPositive RootsNumber ProblemsWord Problems And ApplicationsMathematicsClass 10 Mcq

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