The discriminant is (100-76=24), so the zeroes are \(\frac{10\pm\sqrt{24}}{2}=5\pm\sqrt{6}\). Simplify \(\sqrt{24}=2\sqrt{6}\) in exams.
Step 2
Why this answer is correct
The correct answer is A. \(5+\sqrt{6},5-\sqrt{6}\). The discriminant is (100-76=24), so the zeroes are \(\frac{10\pm\sqrt{24}}{2}=5\pm\sqrt{6}\). Simplify \(\sqrt{24}=2\sqrt{6}\) in exams.
Step 3
Exam Tip
विविक्तकर (100-76=24) है, इसलिए शून्यक \(\frac{10\pm\sqrt{24}}{2}=5\pm\sqrt{6}\) हैं। परीक्षा में \(\sqrt{24}=2\sqrt{6}\) सरल करें।
A. \(-\sqrt{7}+1\) और \(-\sqrt{7}-1\)/\(-\sqrt{7}+1\) and \(-\sqrt{7}-1\)
Step 1
Concept
Using the formula, \(x=\frac{-2\sqrt{7}\pm2}{2}=-\sqrt{7}\pm1\). Simplifying the discriminant first gives a clean answer.
Step 2
Why this answer is correct
The correct answer is A. \(-\sqrt{7}+1\) और \(-\sqrt{7}-1\) / \(-\sqrt{7}+1\) and \(-\sqrt{7}-1\). Using the formula, \(x=\frac{-2\sqrt{7}\pm2}{2}=-\sqrt{7}\pm1\). Simplifying the discriminant first gives a clean answer.
Step 3
Exam Tip
सूत्र से \(x=\frac{-2\sqrt{7}\pm2}{2}=-\sqrt{7}\pm1\)। पहले विविक्तकर सरल करने से उत्तर साफ मिलता है।
A. \(-2+\sqrt{2}\) और \(-2-\sqrt{2}\)/\(-2+\sqrt{2}\) and \(-2-\sqrt{2}\)
Step 1
Concept
By the formula, \(x=\frac{-4\pm\sqrt{16-8}}{2}=-2\pm\sqrt{2}\). Pay attention to the negative sign and denominator (2).
Step 2
Why this answer is correct
The correct answer is A. \(-2+\sqrt{2}\) और \(-2-\sqrt{2}\) / \(-2+\sqrt{2}\) and \(-2-\sqrt{2}\). By the formula, \(x=\frac{-4\pm\sqrt{16-8}}{2}=-2\pm\sqrt{2}\). Pay attention to the negative sign and denominator (2).
Step 3
Exam Tip
सूत्र से \(x=\frac{-4\pm\sqrt{16-8}}{2}=-2\pm\sqrt{2}\)। ऋण चिह्न और हर (2) दोनों पर ध्यान दें।
Using the formula, \(x=\frac{2\sqrt{3}\pm\sqrt{12+4}}{2}=\sqrt{3}\pm2\). Simplify \(\sqrt{16}=4\) carefully.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{3}\pm2\). Using the formula, \(x=\frac{2\sqrt{3}\pm\sqrt{12+4}}{2}=\sqrt{3}\pm2\). Simplify \(\sqrt{16}=4\) carefully.
Step 3
Exam Tip
सूत्र से \(x=\frac{2\sqrt{3}\pm\sqrt{12+4}}{2}=\sqrt{3}\pm2\)। \(\sqrt{16}=4\) को ध्यान से सरल करें।
By the formula, \(x=\frac{8\pm\sqrt{64-8}}{4}=2\pm\frac{\sqrt{14}}{2}\). Divide the whole numerator by the denominator carefully.
Step 2
Why this answer is correct
The correct answer is A. \(2\pm\frac{\sqrt{14}}{2}\). By the formula, \(x=\frac{8\pm\sqrt{64-8}}{4}=2\pm\frac{\sqrt{14}}{2}\). Divide the whole numerator by the denominator carefully.
Step 3
Exam Tip
सूत्र से \(x=\frac{8\pm\sqrt{64-8}}{4}=2\pm\frac{\sqrt{14}}{2}\) है। हर से भाग देते समय पूरे अंश को बाँटें।
By the formula, \(x=\frac{4\pm\sqrt{16+24}}{2}=2\pm\sqrt{10}\). Remember \(\sqrt{40}=2\sqrt{10}\) while simplifying (D).
Step 2
Why this answer is correct
The correct answer is A. \(2\pm\sqrt{10}\). By the formula, \(x=\frac{4\pm\sqrt{16+24}}{2}=2\pm\sqrt{10}\). Remember \(\sqrt{40}=2\sqrt{10}\) while simplifying (D).
Step 3
Exam Tip
सूत्र से \(x=\frac{4\pm\sqrt{16+24}}{2}=2\pm\sqrt{10}\) है। (D) को सरल करने में \(\sqrt{40}=2\sqrt{10}\) याद रखें।
By the formula, \(x=\frac{4\pm\sqrt{16+8}}{4}=1\pm\frac{\sqrt{6}}{2}\). Divide the whole expression carefully while simplifying.
Step 2
Why this answer is correct
The correct answer is A. \(1\pm\frac{\sqrt{6}}{2}\). By the formula, \(x=\frac{4\pm\sqrt{16+8}}{4}=1\pm\frac{\sqrt{6}}{2}\). Divide the whole expression carefully while simplifying.
Step 3
Exam Tip
सूत्र से \(x=\frac{4\pm\sqrt{16+8}}{4}=1\pm\frac{\sqrt{6}}{2}\) है। हर को सरल करते समय पूरा पद विभाजित करें।
A. \(-1+\sqrt{2}\) और \(-1-\sqrt{2}\)/\(-1+\sqrt{2}\) and \(-1-\sqrt{2}\)
Step 1
Concept
By the formula, \(x=\frac{-2\pm\sqrt{4+4}}{2}=-1\pm\sqrt{2}\). Pay special attention to signs.
Step 2
Why this answer is correct
The correct answer is A. \(-1+\sqrt{2}\) और \(-1-\sqrt{2}\) / \(-1+\sqrt{2}\) and \(-1-\sqrt{2}\). By the formula, \(x=\frac{-2\pm\sqrt{4+4}}{2}=-1\pm\sqrt{2}\). Pay special attention to signs.
Step 3
Exam Tip
सूत्र से \(x=\frac{-2\pm\sqrt{4+4}}{2}=-1\pm\sqrt{2}\)। चिह्नों पर विशेष ध्यान दें।
A. \(4+\sqrt{6}\) और \(4-\sqrt{6}\)/\(4+\sqrt{6}\) and \(4-\sqrt{6}\)
Step 1
Concept
By the formula, the zeroes are \(\frac{8\pm\sqrt{64-40}}{2}=4\pm\sqrt{6}\). Simplify the discriminant first.
Step 2
Why this answer is correct
The correct answer is A. \(4+\sqrt{6}\) और \(4-\sqrt{6}\) / \(4+\sqrt{6}\) and \(4-\sqrt{6}\). By the formula, the zeroes are \(\frac{8\pm\sqrt{64-40}}{2}=4\pm\sqrt{6}\). Simplify the discriminant first.
Step 3
Exam Tip
सूत्र से शून्यक \(\frac{8\pm\sqrt{64-40}}{2}=4\pm\sqrt{6}\) हैं। पहले विविक्तकर सरल करें।
