\(5x^2-10x-3=0\) के मूलों का सही रूप क्या है?

What is the correct form of the roots of \(5x^2-10x-3=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=1\pm\frac{2\sqrt{10}}{5}\)

Step 1

Concept

The formula gives \(x=\frac{10\pm\sqrt{160}}{10}=1\pm\frac{2\sqrt{10}}{5}\). In exams, simplify \(\sqrt{160}=4\sqrt{10}\).

Step 2

Why this answer is correct

The correct answer is A. \(x=1\pm\frac{2\sqrt{10}}{5}\). The formula gives \(x=\frac{10\pm\sqrt{160}}{10}=1\pm\frac{2\sqrt{10}}{5}\). In exams, simplify \(\sqrt{160}=4\sqrt{10}\).

Step 3

Exam Tip

सूत्र से \(x=\frac{10\pm\sqrt{160}}{10}=1\pm\frac{2\sqrt{10}}{5}\) मिलता है। परीक्षा में \(\sqrt{160}=4\sqrt{10}\) सरल करें।

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Mathematics Answer, Explanation and Revision Hints

\(5x^2-10x-3=0\) के मूलों का सही रूप क्या है? / What is the correct form of the roots of \(5x^2-10x-3=0\)?

Correct Answer: A. \(x=1\pm\frac{2\sqrt{10}}{5}\). Explanation: सूत्र से \(x=\frac{10\pm\sqrt{160}}{10}=1\pm\frac{2\sqrt{10}}{5}\) मिलता है। परीक्षा में \(\sqrt{160}=4\sqrt{10}\) सरल करें। / The formula gives \(x=\frac{10\pm\sqrt{160}}{10}=1\pm\frac{2\sqrt{10}}{5}\). In exams, simplify \(\sqrt{160}=4\sqrt{10}\).

Which concept should I revise for this Mathematics MCQ?

The formula gives \(x=\frac{10\pm\sqrt{160}}{10}=1\pm\frac{2\sqrt{10}}{5}\). In exams, simplify \(\sqrt{160}=4\sqrt{10}\).

What exam hint can help solve this Mathematics question?

सूत्र से \(x=\frac{10\pm\sqrt{160}}{10}=1\pm\frac{2\sqrt{10}}{5}\) मिलता है। परीक्षा में \(\sqrt{160}=4\sqrt{10}\) सरल करें।