What are the roots of (x^2-19x+56=0) by quadratic formula?

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Answer and explanation

Correct answer: (x=\frac{19\pm\sqrt{137}}{2})

Here (D=(-19)^2-4(1)(56)=137), so (x=\frac{19\pm\sqrt{137}}{2}). In exams, finding (D) correctly is important.

What is the correct answer to this question?

(x=\frac{19\pm\sqrt{137}}{2})

Why is this the correct answer?

Here (D=(-19)^2-4(1)(56)=137), so (x=\frac{19\pm\sqrt{137}}{2}). In exams, finding (D) correctly is important.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.

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