What are the roots of (x^2-16x+37=0) by quadratic formula?

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Answer and explanation

Correct answer: (x=8\pm3\sqrt{3})

Here (D=(-16)^2-4(1)(37)=108), so (x=\frac{16\pm6\sqrt{3}}{2}=8\pm3\sqrt{3}). In exams, simplify (D) correctly.

What is the correct answer to this question?

(x=8\pm3\sqrt{3})

Why is this the correct answer?

Here (D=(-16)^2-4(1)(37)=108), so (x=\frac{16\pm6\sqrt{3}}{2}=8\pm3\sqrt{3}). In exams, simplify (D) correctly.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.

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