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What are the roots of (x^2-14x+13=0) by quadratic formula?(x^2-14x+13=0) के मूल द्विघात सूत्र से क्या हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x=1,13)(x=1,13)
(D=(-14)^2-4(1)(13)=144), so (x=\frac{14\pm12}{2}) gives (1) and (13). In exams, if (D) is a perfect square, simplify quickly.(D=(-14)^2-4(1)(13)=144), इसलिए (x=\frac{14\pm12}{2}) से (1) और (13) मिलते हैं। परीक्षा में (D) पूर्ण वर्ग हो तो उत्तर जल्दी सरल करें।
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