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Which option correctly gives the zeroes of (x^2-2\sqrt{3}x-1)?
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Answer and explanation
Correct answer: (\sqrt{3}\pm2)
Using the formula, (x=\frac{2\sqrt{3}\pm\sqrt{12+4}}{2}=\sqrt{3}\pm2). Simplify (\sqrt{16}=4) carefully.
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What is the correct answer to this question?
(\sqrt{3}\pm2)
Why is this the correct answer?
Using the formula, (x=\frac{2\sqrt{3}\pm\sqrt{12+4}}{2}=\sqrt{3}\pm2). Simplify (\sqrt{16}=4) carefully.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.
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