Concept-wise Practice

quadratic-formula MCQ Questions for Class 10

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Practice Questions

34 questions tagged with quadratic-formula.

यदि (p(x)=x-2-4x-6) है, तो शून्यकों का सही युग्म कौन सा है?

If (p(x)=x-2-4x-6), which is the correct pair of zeroes?

Explanation opens after your attempt
Correct Answer

A. \(2\pm\sqrt{10}\)

Step 1

Concept

By the formula, \(x=\frac{4\pm\sqrt{16+24}}{2}=2\pm\sqrt{10}\). Remember \(\sqrt{40}=2\sqrt{10}\) while simplifying (D).

Step 2

Why this answer is correct

The correct answer is A. \(2\pm\sqrt{10}\). By the formula, \(x=\frac{4\pm\sqrt{16+24}}{2}=2\pm\sqrt{10}\). Remember \(\sqrt{40}=2\sqrt{10}\) while simplifying (D).

Step 3

Exam Tip

सूत्र से \(x=\frac{4\pm\sqrt{16+24}}{2}=2\pm\sqrt{10}\) है। (D) को सरल करने में \(\sqrt{40}=2\sqrt{10}\) याद रखें।

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यदि (p(x)=2x-2-4x-1) है, तो इसके शून्यकों का सही रूप कौन सा है?

If (p(x)=2x-2-4x-1), which is the correct form of its zeroes?

Explanation opens after your attempt
Correct Answer

A. \(1\pm\frac{\sqrt{6}}{2}\)

Step 1

Concept

By the formula, \(x=\frac{4\pm\sqrt{16+8}}{4}=1\pm\frac{\sqrt{6}}{2}\). Divide the whole expression carefully while simplifying.

Step 2

Why this answer is correct

The correct answer is A. \(1\pm\frac{\sqrt{6}}{2}\). By the formula, \(x=\frac{4\pm\sqrt{16+8}}{4}=1\pm\frac{\sqrt{6}}{2}\). Divide the whole expression carefully while simplifying.

Step 3

Exam Tip

सूत्र से \(x=\frac{4\pm\sqrt{16+8}}{4}=1\pm\frac{\sqrt{6}}{2}\) है। हर को सरल करते समय पूरा पद विभाजित करें।

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यदि (p(x)=x-2+2x-1) है, तो इसके शून्यक कौन से हैं?

If (p(x)=x-2+2x-1), what are its zeroes?

Explanation opens after your attempt
Correct Answer

A. \(-1+\sqrt{2}\) और \(-1-\sqrt{2}\)\(-1+\sqrt{2}\) and \(-1-\sqrt{2}\)

Step 1

Concept

By the formula, \(x=\frac{-2\pm\sqrt{4+4}}{2}=-1\pm\sqrt{2}\). Pay special attention to signs.

Step 2

Why this answer is correct

The correct answer is A. \(-1+\sqrt{2}\) और \(-1-\sqrt{2}\) / \(-1+\sqrt{2}\) and \(-1-\sqrt{2}\). By the formula, \(x=\frac{-2\pm\sqrt{4+4}}{2}=-1\pm\sqrt{2}\). Pay special attention to signs.

Step 3

Exam Tip

सूत्र से \(x=\frac{-2\pm\sqrt{4+4}}{2}=-1\pm\sqrt{2}\)। चिह्नों पर विशेष ध्यान दें।

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यदि (p(x)=x-2-8x+10) है, तो इसके शून्यक कौन से हैं?

If (p(x)=x-2-8x+10), what are its zeroes?

Explanation opens after your attempt
Correct Answer

A. \(4+\sqrt{6}\) और \(4-\sqrt{6}\)\(4+\sqrt{6}\) and \(4-\sqrt{6}\)

Step 1

Concept

By the formula, the zeroes are \(\frac{8\pm\sqrt{64-40}}{2}=4\pm\sqrt{6}\). Simplify the discriminant first.

Step 2

Why this answer is correct

The correct answer is A. \(4+\sqrt{6}\) और \(4-\sqrt{6}\) / \(4+\sqrt{6}\) and \(4-\sqrt{6}\). By the formula, the zeroes are \(\frac{8\pm\sqrt{64-40}}{2}=4\pm\sqrt{6}\). Simplify the discriminant first.

Step 3

Exam Tip

सूत्र से शून्यक \(\frac{8\pm\sqrt{64-40}}{2}=4\pm\sqrt{6}\) हैं। पहले विविक्तकर सरल करें।

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