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What is the correct prime factorisation of 31104?
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Answer and explanation
Correct answer: (2^7\times3^5)
Step 1: Write (31104=128\times243). Step 2: (128=2^7) and (243=3^5), so (31104=2^7\times3^5). Step 3: 128 and 243 are composite, so keep prime bases.
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What is the correct answer to this question?
(2^7\times3^5)
Why is this the correct answer?
Step 1: Write (31104=128\times243). Step 2: (128=2^7) and (243=3^5), so (31104=2^7\times3^5). Step 3: 128 and 243 are composite, so keep prime bases.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Prime Factorisation.
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