यदि \(x^2+bx+12\) के शून्यक \(2+\sqrt{7}\) और \(2-\sqrt{7}\) हैं, तो त्रुटि क्या है?
If the zeroes of \(x^2+bx+12\) are \(2+\sqrt{7}\) and \(2-\sqrt{7}\), what is the error?
Explanation opens after your attempt
Correct Answer
B. गुणनफल (-3) है, इसलिए स्थिर पद (12) नहीं हो सकताProduct is (-3), so constant term cannot be (12)
Concept
The product of these zeroes is (4-7=-3). In a monic polynomial, the constant term must equal the product.
Why this answer is correct
The correct answer is B. गुणनफल (-3) है, इसलिए स्थिर पद (12) नहीं हो सकता / Product is (-3), so constant term cannot be (12). The product of these zeroes is (4-7=-3). In a monic polynomial, the constant term must equal the product.
Exam Tip
इन शून्यकों का गुणनफल (4-7=-3) है। एकक बहुपद में स्थिर पद गुणनफल के बराबर होना चाहिए।
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