In an arithmetic progression the first term is (15) and the common difference is (6). What is the sum of the first (28) terms?
Answer and explanation
Correct answer: 2688
The sum of the first \(n\) terms of an AP is \(S_n=\frac{n}{2}[2a+(n-1)d]\). Here, \(a=15\), \(d=6\), and \(n=28\). Thus, \(S_{28}=\frac{28}{2}[2(15)+27(6)]=14(30+162)=14\times192=2688\). Therefore, option C is correct. Using \(28\) instead of \(27\) would be incorrect because the common difference is added only \(n-1\) times. Exam tip: write \(n-1\) separately before substituting values in the formula.
Frequently asked questions
What is the correct answer to this question?
2688
Why is this the correct answer?
The sum of the first \(n\) terms of an AP is \(S_n=\frac{n}{2}[2a+(n-1)d]\). Here, \(a=15\), \(d=6\), and \(n=28\). Thus, \(S_{28}=\frac{28}{2}[2(15)+27(6)]=14(30+162)=14\times192=2688\). Therefore, option C is correct. Using \(28\) instead of \(27\) would be incorrect because the common difference is added only \(n-1\) times. Exam tip: write \(n-1\) separately before substituting values in the formula.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the sum of the first $n$ terms of an AP.
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