The sums of the first (n) terms of the arithmetic progressions (10,14,18,\ldots) and (22,24,26,\ldots) are equal. What is the positive value of (n)?
Answer and explanation
Correct answer: (13)
Equating both sums gives (4n+16=2n+42), so (n=13). Exam tip: when (n) is common, cancel (\frac{n}{2}).
Frequently asked questions
What is the correct answer to this question?
(13)
Why is this the correct answer?
Equating both sums gives (4n+16=2n+42), so (n=13). Exam tip: when (n) is common, cancel (\frac{n}{2}).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the sum of the first $n$ terms of an AP.
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