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6 results found for "number-50" in Class 10.
Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3^2\times5\times7\) है?
Which number has prime factorisation \(2^4\times3^2\times5\times7\)?
#evaluate-factorisation
#number-5040
#hard
A 5040
B 2520
C 10080
D 7560
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(3^2=9\).
Step 2
Why this answer is correct
\(16\times9\times5\times7=5040\).
Step 3
Exam Tip
First do \(16\times9=144\), then multiply the rest. चरण 1: \(2^4=16\) और \(3^2=9\) निकालें। चरण 2: \(16\times9\times5\times7=5040\)। चरण 3: पहले \(16\times9=144\) करें, फिर बाकी गुणा करें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
संख्या 5040 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 5040?
#prime-factorisation
#number-5040
#hard
A \(2^4\times3^2\times5\times7\)
B \(2^3\times3^2\times5\times7\)
C \(16\times315\)
D \(2^4\times9\times35\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times3^2\times5\times7\)
Step 1
Concept
Write \(5040=16\times315\).
Step 2
Why this answer is correct
\(16=2^4\) and \(315=3^2\times5\times7\), so \(5040=2^4\times3^2\times5\times7\).
Step 3
Exam Tip
Give 315 its complete prime form. चरण 1: \(5040=16\times315\) लिखें। चरण 2: \(16=2^4\) और \(315=3^2\times5\times7\), इसलिए \(5040=2^4\times3^2\times5\times7\)। चरण 3: 315 को पूरा अभाज्य रूप दें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times7\) है?
Which number has prime factorisation \(2^3\times3^2\times7\)?
#evaluate-factorisation
#number-504
#medium
A 504
B 252
C 1008
D 756
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(3^2=9\).
Step 2
Why this answer is correct
\(8\times9\times7=504\).
Step 3
Exam Tip
Evaluate prime powers first, then multiply. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times7=504\)। चरण 3: अभाज्य घातों का मान पहले निकालें, फिर गुणा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
संख्या 504 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 504?
#prime-factorisation
#number-504
#medium
A \(2^3\times3^2\times7\)
B \(2^2\times3^3\times7\)
C \(8\times63\)
D \(2^3\times9\times7\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3^2\times7\)
Step 1
Concept
Write \(504=8\times63\).
Step 2
Why this answer is correct
\(8=2^3\) and \(63=3^2\times7\), so \(504=2^3\times3^2\times7\).
Step 3
Exam Tip
Do not leave composite forms like 8 and 63 in the final answer. चरण 1: \(504=8\times63\) लिखें। चरण 2: \(8=2^3\) और \(63=3^2\times7\), इसलिए \(504=2^3\times3^2\times7\)। चरण 3: 8 और 63 जैसे संयुक्त रूपों को अंतिम उत्तर में न छोड़ें।
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Question
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि किसी संख्या का अभाज्य गुणनखंडन \(2\times5^2\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2\times5^2\), which number is it?
#evaluate-factorisation
#number-50
#easy
A 50
B 25
C 40
D 100
Explanation opens after your attempt
Step 1
Concept
\(5^2=25\).
Step 2
Why this answer is correct
\(2\times25=50\).
Step 3
Exam Tip
Find the value of the power and then multiply. चरण 1: \(5^2=25\) है। चरण 2: \(2\times25=50\)। चरण 3: घात का मान निकालकर फिर गुणा करें।
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Question
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
संख्या 50 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 50?
#prime-factorisation
#number-50
#easy
A \(2\times5^2\)
B \(2^2\times5\)
C \(10\times5\)
D \(25\times2\)
Explanation opens after your attempt
Correct Answer
A. \(2\times5^2\)
Step 1
Concept
Write \(50=2\times25\).
Step 2
Why this answer is correct
Since \(25=5^2\), \(50=2\times5^2\).
Step 3
Exam Tip
25 is composite, so write \(5^2\) in the final form. चरण 1: \(50=2\times25\) लिखें। चरण 2: \(25=5^2\), इसलिए \(50=2\times5^2\)। चरण 3: 25 संयुक्त है, इसलिए अंतिम रूप में \(5^2\) लिखें।
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