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When 4 is subtracted from a number and the result is multiplied by the same number, the product is 77. What is the positive number?

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Answer and explanation

Correct answer: 11

Let the number be \(x\). According to the question, \(x(x-4)=77\), so \(x^2-4x-77=0\). Factoring gives \((x-11)(x+7)=0\), hence \(x=11\) or \(x=-7\). The positive number is 11; the close distractor 7 is incorrect because \(7(7-4)=21\), not 77. Exam tip: Translate the wording into a quadratic equation first, then select the solution that satisfies the stated condition.

Related tags

Quadratic-EquationsWord-ProblemsPositive-IntegerFactorisation

Frequently asked questions

What is the correct answer to this question?

11

Why is this the correct answer?

Let the number be \(x\). According to the question, \(x(x-4)=77\), so \(x^2-4x-77=0\). Factoring gives \((x-11)(x+7)=0\), hence \(x=11\) or \(x=-7\). The positive number is 11; the close distractor 7 is incorrect because \(7(7-4)=21\), not 77. Exam tip: Translate the wording into a quadratic equation first, then select the solution that satisfies the stated condition.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Word Problems and Applications.

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