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5 results found for "number-36" in Class 10.

Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

संख्या 36300 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 36300?

Explanation opens after your attempt
Correct Answer

A. \(2^2\times3\times5^2\times11^2\)

Step 1

Concept

Write \(36300=300\times121\).

Step 2

Why this answer is correct

\(300=2^2\times3\times5^2\) and \(121=11^2\), so \(36300=2^2\times3\times5^2\times11^2\).

Step 3

Exam Tip

Convert 300 and 121 into prime powers. चरण 1: \(36300=300\times121\) लिखें। चरण 2: \(300=2^2\times3\times5^2\) और \(121=11^2\), इसलिए \(36300=2^2\times3\times5^2\times11^2\)। चरण 3: 300 और 121 को अभाज्य घातों में बदलें।

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Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

संख्या 3645 का अभाज्य गुणनखंडन कौन सा है?

Which is the prime factorisation of 3645?

Explanation opens after your attempt
Correct Answer

A. \(3^6\times5\)

Step 1

Concept

Write \(3645=729\times5\).

Step 2

Why this answer is correct

Since \(729=3^6\), \(3645=3^6\times5\).

Step 3

Exam Tip

729 should not be left in the final form. चरण 1: \(3645=729\times5\) लिखें। चरण 2: \(729=3^6\), इसलिए \(3645=3^6\times5\)। चरण 3: 729 को अंतिम रूप में नहीं छोड़ना चाहिए।

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Question Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 360 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 360?

Explanation opens after your attempt
Correct Answer

A. \(2^3\times3^2\times5\)

Step 1

Concept

Write \(360=36\times10\).

Step 2

Why this answer is correct

\(36=2^2\times3^2\) and \(10=2\times5\), so \(360=2^3\times3^2\times5\).

Step 3

Exam Tip

Be careful while counting the total power of 2. चरण 1: \(360=36\times10\) लिखें। चरण 2: \(36=2^2\times3^2\) और \(10=2\times5\), इसलिए \(360=2^3\times3^2\times5\)। चरण 3: 2 की कुल घात गिनते समय सावधानी रखें।

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Question Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^2\times3^2\) है, तो वह संख्या कौन सी है?

If the prime factorisation of a number is \(2^2\times3^2\), which number is it?

Explanation opens after your attempt
Correct Answer

A. 36

Step 1

Concept

Calculate \(2^2=4\) and \(3^2=9\).

Step 2

Why this answer is correct

\(4\times9=36\).

Step 3

Exam Tip

Multiply to get the number from prime factorisation. चरण 1: \(2^2=4\) और \(3^2=9\) निकालें। चरण 2: \(4\times9=36\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए गुणा करें।

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Question Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

संख्या 36 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 36?

Explanation opens after your attempt
Correct Answer

A. \(2^2\times3^2\)

Step 1

Concept

Write \(36=4\times9\).

Step 2

Why this answer is correct

\(4=2^2\) and \(9=3^2\), so \(36=2^2\times3^2\).

Step 3

Exam Tip

In complete prime form, keep only prime bases. चरण 1: \(36=4\times9\) लिखें। चरण 2: \(4=2^2\) और \(9=3^2\), इसलिए \(36=2^2\times3^2\)। चरण 3: पूर्ण अभाज्य रूप में केवल अभाज्य आधार रखें।

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