100 results found for "missing-constant-term" in Class 10.
यदि (p(x)=x-2 +ax+4) का स्थिर पद (4) है, तो स्थिर पद कौन-सा है?
If the constant term of (p(x)=x-2 +ax+4) is (4), which term is the constant term?
#constant_term
#parameter
#polynomials
A \(x^2\)
B (ax)
C (4)
D (a)
Explanation opens after your attempt
Step 1
Concept
The constant term does not contain (x). So (4) is the constant term.
Step 2
Why this answer is correct
The correct answer is C. (4). The constant term does not contain (x). So (4) is the constant term.
Step 3
Exam Tip
स्थिर पद में (x) नहीं होता। इसलिए (4) स्थिर पद है।
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(p(x)=7x-2 ) में नियत पद क्या है?
What is the constant term in (p(x)=7x-2 )?
#polynomials
#constant-term
#easy
#missing-term
A (7)
B (2)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
There is no separate constant term, so the constant term is (0). Do not treat a term containing (x) as constant.
Step 2
Why this answer is correct
The correct answer is C. (0). There is no separate constant term, so the constant term is (0). Do not treat a term containing (x) as constant.
Step 3
Exam Tip
कोई अलग नियत पद नहीं है, इसलिए नियत पद (0) है। केवल (x) वाले पद को नियत पद न मानें।
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किस विकल्प में स्थिर पद अनुपस्थित है लेकिन समीकरण द्विघात है?
In which option is the constant term absent but the equation is quadratic?
#quadratic-equations
#missing-constant-term
#identify
#medium
A \(2x^2+7x=0\)
B (2x+7=0)
C \(2x^3+7x=0\)
D \(\frac{2}{x^2}+7x=0\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2+7x=0\)
Step 1
Concept
In \(2x^2+7x=0\), the \(x^2\) term is present and the constant term is absent. An equation can be quadratic even without a constant term.
Step 2
Why this answer is correct
The correct answer is A. \(2x^2+7x=0\). In \(2x^2+7x=0\), the \(x^2\) term is present and the constant term is absent. An equation can be quadratic even without a constant term.
Step 3
Exam Tip
\(2x^2+7x=0\) में \(x^2\) पद है और स्थिर पद अनुपस्थित है। स्थिर पद न होने पर भी समीकरण द्विघात हो सकता है।
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कौन सा विकल्प \(6x^2+x-8=0\) में स्थिर पद है?
Which option is the constant term in \(6x^2+x-8=0\)?
#quadratic equations
#constant term
#term identification
A \(6x^2\)
B (x)
C (-8)
D (0)
Explanation opens after your attempt
Step 1
Concept
The constant term has no variable. Here the constant term is (-8).
Step 2
Why this answer is correct
The correct answer is C. (-8). The constant term has no variable. Here the constant term is (-8).
Step 3
Exam Tip
स्थिर पद में चर नहीं होता। यहां स्थिर पद (-8) है।
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कौन सा विकल्प \(2x^2+3x+1=0\) में स्थिर पद है?
Which option is the constant term in \(2x^2+3x+1=0\)?
#quadratic equations
#constant term
#term identification
A \(2x^2\)
B (3x)
C (1)
D (0)
Explanation opens after your attempt
Step 1
Concept
The constant term does not contain (x). Hence (1) is the constant term.
Step 2
Why this answer is correct
The correct answer is C. (1). The constant term does not contain (x). Hence (1) is the constant term.
Step 3
Exam Tip
स्थिर पद में (x) नहीं होता। इसलिए (1) स्थिर पद है।
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((4x+3)\(x^2-2x+5\)) में अचर पद क्या है?
What is the constant term in ((4x+3)\(x^2-2x+5\))?
#constant term
#multiplication
#polynomial
A (3)
B (5)
C (8)
D (15)
Explanation opens after your attempt
Step 1
Concept
The constant term comes only from \(3\cdot5=15\). For the constant term, multiply the constant parts.
Step 2
Why this answer is correct
The correct answer is D. (15). The constant term comes only from \(3\cdot5=15\). For the constant term, multiply the constant parts.
Step 3
Exam Tip
अचर पद केवल \(3\cdot5=15\) से आता है। अचर पद के लिए अचर भागों का गुणन देखें।
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((3x-2)\(x^2+5x-1\)) में अचर पद क्या है?
What is the constant term in ((3x-2)\(x^2+5x-1\))?
#constant term
#multiplication
#polynomial
A (-3)
B (-2)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
The constant term comes only from ((-2)(-1)=2). For the constant term, multiply the constant parts.
Step 2
Why this answer is correct
The correct answer is C. (2). The constant term comes only from ((-2)(-1)=2). For the constant term, multiply the constant parts.
Step 3
Exam Tip
अचर पद केवल ((-2)(-1)=2) से आता है। अचर पद के लिए अचर भागों का गुणन देखें।
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((2x-3)\(x^2+x+1\)) में अचर पद क्या है?
What is the constant term in ((2x-3)\(x^2+x+1\))?
#constant term
#multiplication
#polynomial
A (-3)
B (-1)
C (1)
D (2)
Explanation opens after your attempt
Step 1
Concept
The constant term comes only from ((-3)\cdot1=-3). For the constant term, multiply the constant parts.
Step 2
Why this answer is correct
The correct answer is A. (-3). The constant term comes only from ((-3)\cdot1=-3). For the constant term, multiply the constant parts.
Step 3
Exam Tip
अचर पद केवल ((-3)\cdot1=-3) से आता है। अचर पद के लिए अचर पदों का गुणन देखें।
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(p(x)=3x-3 -7x-2 +2x-11) में \(x^2\) के गुणांक और अचर पद का योग क्या है?
In (p(x)=3x-3 -7x-2 +2x-11), what is the sum of the coefficient of \(x^2\) and the constant term?
#coefficient
#constant term
#signs
A (-18)
B (-11)
C (-7)
D (4)
Explanation opens after your attempt
Step 1
Concept
The coefficient of \(x^2\) is (-7) and the constant term is (-11), so the sum is (-18). Do not forget to add with signs.
Step 2
Why this answer is correct
The correct answer is A. (-18). The coefficient of \(x^2\) is (-7) and the constant term is (-11), so the sum is (-18). Do not forget to add with signs.
Step 3
Exam Tip
\(x^2\) का गुणांक (-7) और अचर पद (-11) है, इसलिए योग (-18) है। संकेत सहित जोड़ना न भूलें।
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बहुपद (p(t)=4t-5 -6t-2 +t+15) में अचर पद कौन सा है?
Which is the constant term in the polynomial (p(t)=4t-5 -6t-2 +t+15)?
#constant term
#polynomial
#basic
A (4)
B (-6)
C (1)
D (15)
Explanation opens after your attempt
Step 1
Concept
The term without (t) is the constant term. Here the constant term is (15).
Step 2
Why this answer is correct
The correct answer is D. (15). The term without (t) is the constant term. Here the constant term is (15).
Step 3
Exam Tip
जिस पद में (t) नहीं है वह अचर पद है। यहां अचर पद (15) है।
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कौन सा विकल्प \(2x^3-5x^2+x-4\) की घात और नियत पद को सही बताता है?
Which option correctly gives the degree and constant term of \(2x^3-5x^2+x-4\)?
#degree
#constant-term
#cubic-polynomial
A घात (3), नियत पद (-4) / Degree (3), constant term (-4)
B घात (2), नियत पद (1) / Degree (2), constant term (1)
C घात (1), नियत पद (-5) / Degree (1), constant term (-5)
D घात (4), नियत पद (2) / Degree (4), constant term (2)
Explanation opens after your attempt
Correct Answer
A. घात (3), नियत पद (-4) / Degree (3), constant term (-4)
Step 1
Concept
The highest power is (3) and the term without (x) is (-4). So the correct pair is degree (3), constant term (-4).
Step 2
Why this answer is correct
The correct answer is A. घात (3), नियत पद (-4) / Degree (3), constant term (-4). The highest power is (3) and the term without (x) is (-4). So the correct pair is degree (3), constant term (-4).
Step 3
Exam Tip
सबसे बड़ी घात (3) है और बिना (x) वाला पद (-4) है। इसलिए सही जोड़ी घात (3), नियत पद (-4) है।
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यदि (p(x)=x-2 +5x+c) में नियत पद (-6) है, तो (p(0)) क्या होगा?
If the constant term in (p(x)=x-2 +5x+c) is (-6), what will (p(0)) be?
#constant-term
#p-of-zero
#polynomial-value
A (6)
B (-6)
C (0)
D (5)
Explanation opens after your attempt
Step 1
Concept
(p(0)) is always equal to the constant term. Here the constant term is (-6).
Step 2
Why this answer is correct
The correct answer is B. (-6). (p(0)) is always equal to the constant term. Here the constant term is (-6).
Step 3
Exam Tip
(p(0)) हमेशा नियत पद के बराबर होता है। यहाँ नियत पद (-6) है।
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बहुपद \(12x^2-9x+4\) में नियत पद कौन सा है?
Which is the constant term in \(12x^2-9x+4\)?
#constant-term
#polynomial-terms
#easy
A (12)
B (-9)
C (4)
D (2)
Explanation opens after your attempt
Step 1
Concept
The term without (x) is the constant term. Here the constant term is (4).
Step 2
Why this answer is correct
The correct answer is C. (4). The term without (x) is the constant term. Here the constant term is (4).
Step 3
Exam Tip
जिस पद में (x) नहीं है वह नियत पद होता है। यहाँ नियत पद (4) है।
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व्यंजक \(5x^4-8x+11\) में अचर पद कौन सा है?
Which is the constant term in \(5x^4-8x+11\)?
#constant term
#polynomial
#basic
A (5)
B (-8)
C (11)
D (4)
Explanation opens after your attempt
Step 1
Concept
The term without (x) is the constant term. Here the constant term is (11).
Step 2
Why this answer is correct
The correct answer is C. (11). The term without (x) is the constant term. Here the constant term is (11).
Step 3
Exam Tip
जिस पद में (x) नहीं होता वह अचर पद है। यहां अचर पद (11) है।
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बहुपद \(2x^2+3x-11\) में नियत पद कौन सा है?
Which is the constant term in \(2x^2+3x-11\)?
#constant-term
#polynomials
A (2)
B (3)
C (-11)
D (11x)
Explanation opens after your attempt
Step 1
Concept
The term without (x) is the constant term. Here the constant term is (-11).
Step 2
Why this answer is correct
The correct answer is C. (-11). The term without (x) is the constant term. Here the constant term is (-11).
Step 3
Exam Tip
जिस पद में (x) नहीं होता वह नियत पद होता है। यहाँ नियत पद (-11) है।
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बहुपद \(2x^2+3x+4\) में (x) का गुणांक और नियत पद क्रमशः क्या हैं?
In \(2x^2+3x+4\), what are the coefficient of (x) and the constant term respectively?
#polynomials
#coefficient
#constant-term
#easy
A (3,4)
B (2,3)
C (4,3)
D (2,4)
Explanation opens after your attempt
Step 1
Concept
The coefficient of (x) is (3), and the constant term is (4). Keep the asked order in mind.
Step 2
Why this answer is correct
The correct answer is A. (3,4). The coefficient of (x) is (3), and the constant term is (4). Keep the asked order in mind.
Step 3
Exam Tip
(x) का गुणांक (3) और नियत पद (4) है। क्रमशः पूछे गए क्रम का ध्यान रखें।
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\(6x^2-3x+10\) में नियत पद क्या है?
What is the constant term in \(6x^2-3x+10\)?
#polynomials
#constant-term
#easy
#coefficient
A (6)
B (-3)
C (10)
D (2)
Explanation opens after your attempt
Step 1
Concept
The term without (x) is the constant term. Here it is (10).
Step 2
Why this answer is correct
The correct answer is C. (10). The term without (x) is the constant term. Here it is (10).
Step 3
Exam Tip
जिस पद में (x) नहीं है वह नियत पद होता है। यहाँ वह (10) है।
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समीकरण \(2x^2+3x-8=0\) में स्थिर पद कौन-सा है?
What is the constant term in \(2x^2+3x-8=0\)?
#quadratic-equations
#constant-term
#easy
A (2)
B (3)
C (8)
D (-8)
Explanation opens after your attempt
Step 1
Concept
The term without (x) is the constant term. Here the constant term is (-8).
Step 2
Why this answer is correct
The correct answer is D. (-8). The term without (x) is the constant term. Here the constant term is (-8).
Step 3
Exam Tip
जिस पद में (x) नहीं होता वह स्थिर पद होता है। यहाँ स्थिर पद (-8) है।
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यदि (p(x)=x-2 -2x-3\sqrt{2}) है, तो स्थिर पद का शून्यकों से संबंध क्या बताता है?
If (p(x)=x-2 -2x-3\sqrt{2}), what does the constant term tell about the zeroes?
#constant-term
#product-of-zeroes
#irrational
A शून्यकों का गुणनफल \(-3\sqrt{2}\) है / The product of zeroes is \(-3\sqrt{2}\)
B शून्यकों का योग \(-3\sqrt{2}\) है / The sum of zeroes is \(-3\sqrt{2}\)
C दोनों शून्यक परिमेय हैं / Both zeroes are rational
D विविक्तकर \(-3\sqrt{2}\) है / The discriminant is \(-3\sqrt{2}\)
Explanation opens after your attempt
Correct Answer
A. शून्यकों का गुणनफल \(-3\sqrt{2}\) है / The product of zeroes is \(-3\sqrt{2}\)
Step 1
Concept
In a monic quadratic, the constant term is the product of zeroes. Here \(\alpha\beta=-3\sqrt{2}\).
Step 2
Why this answer is correct
The correct answer is A. शून्यकों का गुणनफल \(-3\sqrt{2}\) है / The product of zeroes is \(-3\sqrt{2}\). In a monic quadratic, the constant term is the product of zeroes. Here \(\alpha\beta=-3\sqrt{2}\).
Step 3
Exam Tip
एकक द्विघात में स्थिर पद शून्यकों का गुणनफल होता है। यहाँ \(\alpha\beta=-3\sqrt{2}\) है।
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यदि शून्यक \(2\sqrt{2}\) और \(3\sqrt{2}\) हैं, तो बहुपद का स्थिर पद क्या होगा यदि अग्र गुणांक (1) है?
If the zeroes are \(2\sqrt{2}\) and \(3\sqrt{2}\), what is the constant term if the leading coefficient is (1)?
#constant-term
#product
#irrational-zeroes
A (12)
B \(5\sqrt{2}\)
C \(6\sqrt{2}\)
D (10)
Explanation opens after your attempt
Step 1
Concept
The constant term equals the product of the zeroes. (\(2\sqrt{2}\)\(3\sqrt{2}\)=12).
Step 2
Why this answer is correct
The correct answer is A. (12). The constant term equals the product of the zeroes. (\(2\sqrt{2}\)\(3\sqrt{2}\)=12).
Step 3
Exam Tip
स्थिर पद शून्यकों के गुणनफल के बराबर है। (\(2\sqrt{2}\)\(3\sqrt{2}\)=12) है।
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बहुपद \(7x^5-3x^4+x^2-11\) में अनुपस्थित \(x^3\) पद का गुणांक क्या है?
What is the coefficient of the missing \(x^3\) term in \(7x^5-3x^4+x^2-11\)?
#missing-term
#coefficient
#degree
A (7)
B (-3)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
There is no \(x^3\) term in this polynomial. The coefficient of a missing term is taken as (0).
Step 2
Why this answer is correct
The correct answer is C. (0). There is no \(x^3\) term in this polynomial. The coefficient of a missing term is taken as (0).
Step 3
Exam Tip
इस बहुपद में \(x^3\) का पद नहीं है। अनुपस्थित पद का गुणांक (0) माना जाता है।
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\(x^4+3x^2+2\) में कौन सा पद अनुपस्थित है?
Which term is missing in \(x^4+3x^2+2\)?
#polynomials
#missing-term
#easy
#standard-form
A \(x^4\)
B \(x^3\)
C \(3x^2\)
D (2)
Explanation opens after your attempt
Correct Answer
B. \(x^3\)
Step 1
Concept
The \(x^3\)-term is not present in this polynomial. Its coefficient may be taken as (0).
Step 2
Why this answer is correct
The correct answer is B. \(x^3\). The \(x^3\)-term is not present in this polynomial. Its coefficient may be taken as (0).
Step 3
Exam Tip
इस बहुपद में \(x^3\) पद नहीं है। अनुपस्थित पद का गुणांक (0) माना जा सकता है।
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यदि समान्तर श्रेणी का (5)वां पद (x+7) और (12)वां पद (x+42) है तो (20)वां पद (x) के रूप में क्या होगा?
If the (5)th term of an AP is (x+7) and the (12)th term is (x+42), what is the (20)th term in terms of (x)?
#ap-algebra-hard
A (x+74)
B (x+77)
C (x+82)
D (x+89)
Explanation opens after your attempt
Step 1
Concept
From (7d=35), (d=5). \(a_{20}=a_{12}+8d=x+42+40=x+82\).
Step 2
Why this answer is correct
The correct answer is C. (x+82). From (7d=35), (d=5). \(a_{20}=a_{12}+8d=x+42+40=x+82\).
Step 3
Exam Tip
(7d=35) से (d=5)। \(a_{20}=a_{12}+8d=x+42+40=x+82\)।
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यदि AP का (5)वां पद (27) और (14)वां पद (90) है तो (20)वां पद क्या होगा?
If the (5)th term of an AP is (27) and the (14)th term is (90), what is the (20)th term?
#ap two-terms nth-term class10
A (126)
B (130)
C (132)
D (136)
Explanation opens after your attempt
Step 1
Concept
\(d=\frac{90-27}{14-5}=7\) and \(a_{20}=90+6\times7=132\). First find (d) then move forward.
Step 2
Why this answer is correct
The correct answer is C. (132). \(d=\frac{90-27}{14-5}=7\) and \(a_{20}=90+6\times7=132\). First find (d) then move forward.
Step 3
Exam Tip
\(d=\frac{90-27}{14-5}=7\) और \(a_{20}=90+6\times7=132\)। पहले (d) निकालें फिर आगे बढ़ें।
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यदि समान्तर श्रेणी का (4)वां पद (15) और (12)वां पद (55) है तो (16)वां पद क्या होगा?
If the (4)th term of an AP is (15) and the (12)th term is (55), what is the (16)th term?
#ap
#two-terms
#nth-term
#class10
A (70)
B (80)
C (75)
D (85)
Explanation opens after your attempt
Step 1
Concept
\(d=\frac{55-15}{12-4}=5\) and \(a_{16}=55+4\times5=75\). First find (d), then the required term.
Step 2
Why this answer is correct
The correct answer is C. (75). \(d=\frac{55-15}{12-4}=5\) and \(a_{16}=55+4\times5=75\). First find (d), then the required term.
Step 3
Exam Tip
\(d=\frac{55-15}{12-4}=5\) और \(a_{16}=55+4\times5=75\)। पहले (d) फिर वांछित पद निकालें।
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यदि AP का (3)वां पद (8) और (8)वां पद (3) है, तो (11)वां पद क्या होगा?
If the (3)rd term of an AP is (8) and the (8)th term is (3), what is the (11)th term?
#ap
#two-terms
#nth-term
#class10
A (0)
B (1)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
\(d=\frac{3-8}{8-3}=-1\), so (a_{11}=3+3(-1)=0). Moving from the nearer known term is simple.
Step 2
Why this answer is correct
The correct answer is A. (0). \(d=\frac{3-8}{8-3}=-1\), so (a_{11}=3+3(-1)=0). Moving from the nearer known term is simple.
Step 3
Exam Tip
\(d=\frac{3-8}{8-3}=-1\), इसलिए (a_{11}=3+3(-1)=0)। ज्ञात पास वाले पद से आगे बढ़ना सरल है।
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यदि किसी AP का (p)वां पद (q) और (q)वां पद (p) है, तो उसका ((p+q))वां पद क्या होगा?
If the (p)th term of an AP is (q) and the (q)th term is (p), what is its ((p+q))th term?
#ap
#symbolic
#nth-term
#class10
A (0)
B (p+q)
C (p-q)
D (q-p)
Explanation opens after your attempt
Step 1
Concept
Subtracting the relations gives (d=-1), and substitution gives \(a_{p+q}=0\). Even in symbolic APs, use (a_n=a+(n-1)d).
Step 2
Why this answer is correct
The correct answer is A. (0). Subtracting the relations gives (d=-1), and substitution gives \(a_{p+q}=0\). Even in symbolic APs, use (a_n=a+(n-1)d).
Step 3
Exam Tip
संबंधों को घटाने पर (d=-1) और आगे रखने पर \(a_{p+q}=0\) मिलता है। प्रतीकात्मक AP में भी (a_n=a+(n-1)d) ही लगाएं।
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यदि किसी समान्तर श्रेणी का (5)वां पद (16) और (9)वां पद (32) है, तो (13)वां पद क्या होगा?
If the (5)th term of an AP is (16) and the (9)th term is (32), what is the (13)th term?
#ap
#two-known-terms
#nth-term
#class10
A (44)
B (46)
C (48)
D (50)
Explanation opens after your attempt
Step 1
Concept
\(d=\frac{32-16}{9-5}=4\), so \(a_{13}=32+4\times4=48\). Equal position gaps give equal term gaps in an AP.
Step 2
Why this answer is correct
The correct answer is C. (48). \(d=\frac{32-16}{9-5}=4\), so \(a_{13}=32+4\times4=48\). Equal position gaps give equal term gaps in an AP.
Step 3
Exam Tip
\(d=\frac{32-16}{9-5}=4\), इसलिए \(a_{13}=32+4\times4=48\)। समान स्थान अंतर होने पर पदों का अंतर भी समान होता है।
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यदि \(a+\sqrt{b}\) और \(a-\sqrt{b}\) किसी एकक द्विघात बहुपद के शून्यक हैं, तो स्थिर पद क्या होगा?
If \(a+\sqrt{b}\) and \(a-\sqrt{b}\) are zeroes of a monic quadratic polynomial, what is the constant term?
#general-form
#conjugates
#constant-term
A \(a^2-b\)
B \(a^2+b\)
C (2a)
D (-2a)
Explanation opens after your attempt
Correct Answer
A. \(a^2-b\)
Step 1
Concept
In a monic polynomial, the constant term is the product of zeroes. Here the product is (\(a+\sqrt{b}\)\(a-\sqrt{b}\)=a-2 -b).
Step 2
Why this answer is correct
The correct answer is A. \(a^2-b\). In a monic polynomial, the constant term is the product of zeroes. Here the product is (\(a+\sqrt{b}\)\(a-\sqrt{b}\)=a-2 -b).
Step 3
Exam Tip
एकक बहुपद में स्थिर पद शून्यकों का गुणनफल होता है। यहाँ गुणनफल (\(a+\sqrt{b}\)\(a-\sqrt{b}\)=a-2 -b) है।
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यदि समान्तर श्रेणी का (8)वां पद (x+19) और (20)वां पद (x+91) है, तो (35)वां पद (x) के रूप में क्या होगा?
If the (8)th term of an AP is (x+19) and the (20)th term is (x+91), what is the (35)th term in terms of (x)?
#ap-algebra-expert
A (x+169)
B (x+175)
C (x+181)
D (x+187)
Explanation opens after your attempt
Correct Answer
C. (x+181)
Step 1
Concept
(12d=72), so (d=6). \(a_{35}=x+91+15\times6=x+181\).
Step 2
Why this answer is correct
The correct answer is C. (x+181). (12d=72), so (d=6). \(a_{35}=x+91+15\times6=x+181\).
Step 3
Exam Tip
(12d=72), इसलिए (d=6)। \(a_{35}=x+91+15\times6=x+181\)।
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यदि समान्तर श्रेणी का (7)वां पद (x+13) और (18)वां पद (x+90) है तो (32)वां पद (x) के रूप में क्या होगा?
If the (7)th term of an AP is (x+13) and the (18)th term is (x+90), what is the (32)nd term in terms of (x)?
#ap algebra hard
A (x+181)
B (x+188)
C (x+195)
D (x+202)
Explanation opens after your attempt
Correct Answer
B. (x+188)
Step 1
Concept
From (11d=77), (d=7). \(a_{32}=a_{18}+14d=x+90+98=x+188\).
Step 2
Why this answer is correct
The correct answer is B. (x+188). From (11d=77), (d=7). \(a_{32}=a_{18}+14d=x+90+98=x+188\).
Step 3
Exam Tip
(11d=77) से (d=7)। \(a_{32}=a_{18}+14d=x+90+98=x+188\)।
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यदि समान्तर श्रेणी का (6)वां पद (x+11) और (15)वां पद (x+65) है तो (27)वां पद (x) के रूप में क्या होगा?
If the (6)th term of an AP is (x+11) and the (15)th term is (x+65), what is the (27)th term in terms of (x)?
#ap-algebra-hard
A (x+131)
B (x+137)
C (x+143)
D (x+149)
Explanation opens after your attempt
Correct Answer
B. (x+137)
Step 1
Concept
From (9d=54), (d=6). \(a_{27}=a_{15}+12d=x+65+72=x+137\).
Step 2
Why this answer is correct
The correct answer is B. (x+137). From (9d=54), (d=6). \(a_{27}=a_{15}+12d=x+65+72=x+137\).
Step 3
Exam Tip
(9d=54) से (d=6)। \(a_{27}=a_{15}+12d=x+65+72=x+137\)।
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किसी समान्तर श्रेणी का (12)वां पद (71) और सार्व अंतर (5) है। पहला पद क्या होगा?
The (12)th term of an AP is (71) and the common difference is (5). What is the first term?
#ap first-term known-term class10
A (18)
B (14)
C (20)
D (16)
Explanation opens after your attempt
Step 1
Concept
From \(71=a+11\times5\), (a=16). To move from the known term to the first term subtract (11d).
Step 2
Why this answer is correct
The correct answer is D. (16). From \(71=a+11\times5\), (a=16). To move from the known term to the first term subtract (11d).
Step 3
Exam Tip
\(71=a+11\times5\) से (a=16)। ज्ञात पद से पहले पद तक जाने के लिए (11d) घटाएं।
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किसी समान्तर श्रेणी का (9)वां पद (47) और सार्व अंतर (4) है। पहला पद क्या है?
The (9)th term of an AP is (47) and the common difference is (4). What is the first term?
#ap
#first-term
#nth-term
#class10
A (11)
B (13)
C (17)
D (15)
Explanation opens after your attempt
Step 1
Concept
From \(47=a+8\times4\), (a=15). To move from the known term to the first term, subtract (8d).
Step 2
Why this answer is correct
The correct answer is D. (15). From \(47=a+8\times4\), (a=15). To move from the known term to the first term, subtract (8d).
Step 3
Exam Tip
\(47=a+8\times4\) से (a=15)। ज्ञात पद से पहले पद तक जाने के लिए (8d) घटाएं।
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एक समान्तर श्रेणी का (6)वां पद (23) और सार्व अंतर (5) है। पहला पद क्या होगा?
The (6)th term of an AP is (23) and the common difference is (5). What is the first term?
#ap
#first-term
#nth-term
#class10
A (0)
B (3)
C (2)
D (-2)
Explanation opens after your attempt
Step 1
Concept
(23=a+5d=a+25), so (a=-2). When moving backward from a given term, subtract (5d).
Step 2
Why this answer is correct
The correct answer is D. (-2). (23=a+5d=a+25), so (a=-2). When moving backward from a given term, subtract (5d).
Step 3
Exam Tip
(23=a+5d=a+25), इसलिए (a=-2)। दिए गए पद से पीछे जाते समय (5d) घटाया जाता है।
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समांतर श्रेढ़ी का सामान्य पद \(a_n=7n+2\) है। (11)वाँ पद ज्ञात कीजिए।
The general term of an AP is \(a_n=7n+2\). Find the (11)th term.
#ap
#general term
#nth term
A (72)
B (84)
C (79)
D (77)
Explanation opens after your attempt
Step 1
Concept
\(a_{11}=7\times11+2=79\). The main step is substituting the correct term number in the general term.
Step 2
Why this answer is correct
The correct answer is C. (79). \(a_{11}=7\times11+2=79\). The main step is substituting the correct term number in the general term.
Step 3
Exam Tip
\(a_{11}=7\times11+2=79\)। सामान्य पद में सही पद संख्या रखना ही मुख्य कदम है।
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अनुक्रम \(6,10,14,\Box,22,\ldots\) में रिक्त स्थान का मान क्या है?
What is the missing value in \(6,10,14,\Box,22,\ldots\)?
#arithmetic-progression
#missing-term
#class10
A (16)
B (17)
C (18)
D (19)
Explanation opens after your attempt
Step 1
Concept
The common difference is (4). Therefore, (14+4=18) fills the blank.
Step 2
Why this answer is correct
The correct answer is C. (18). The common difference is (4). Therefore, (14+4=18) fills the blank.
Step 3
Exam Tip
यहाँ सार्व अंतर (4) है। इसलिए (14+4=18) रिक्त स्थान में आएगा।
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समीकरण \(x^2-13x=0\) में कौन सा पद अनुपस्थित है?
Which term is absent in \(x^2-13x=0\)?
#quadratic equations
#missing term
#constant
A द्विघात पद / Quadratic term
B रैखिक पद / Linear term
C स्थिर पद / Constant term
D चर पद / Variable term
Explanation opens after your attempt
Correct Answer
C. स्थिर पद / Constant term
Step 1
Concept
It can be written as \(x^2-13x+0=0\). So the constant term is absent.
Step 2
Why this answer is correct
The correct answer is C. स्थिर पद / Constant term. It can be written as \(x^2-13x+0=0\). So the constant term is absent.
Step 3
Exam Tip
इसे \(x^2-13x+0=0\) लिखा जा सकता है। इसलिए स्थिर पद अनुपस्थित है।
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समीकरण \(x^2+10x=0\) में कौन सा पद अनुपस्थित है?
Which term is absent in \(x^2+10x=0\)?
#quadratic equations
#missing term
#constant
A द्विघात पद / Quadratic term
B रैखिक पद / Linear term
C स्थिर पद / Constant term
D सभी पद / All terms
Explanation opens after your attempt
Correct Answer
C. स्थिर पद / Constant term
Step 1
Concept
It is treated as \(x^2+10x+0=0\). So the constant term is absent.
Step 2
Why this answer is correct
The correct answer is C. स्थिर पद / Constant term. It is treated as \(x^2+10x+0=0\). So the constant term is absent.
Step 3
Exam Tip
इसे \(x^2+10x+0=0\) माना जाता है। इसलिए स्थिर पद अनुपस्थित है।
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एक समांतर श्रेढ़ी का पहला पद (6) है और उसका (14)वाँ पद उसके (4)वें पद का (3) गुना है। पहले (30) पदों का योग क्या होगा?
The first term of an AP is (6), and its (14)th term is (3) times its (4)th term. What is the sum of the first (30) terms?
#term condition
#ap sum
#expert
A (1425)
B (1485)
C (1545)
D (1605)
Explanation opens after your attempt
Step 1
Concept
The condition gives (6+13d=3(6+3d)), so (d=3) and \(S_{30}=1485\). Convert the term condition into an equation first.
Step 2
Why this answer is correct
The correct answer is B. (1485). The condition gives (6+13d=3(6+3d)), so (d=3) and \(S_{30}=1485\). Convert the term condition into an equation first.
Step 3
Exam Tip
शर्त से (6+13d=3(6+3d)), इसलिए (d=3) और \(S_{30}=1485\) है। पदों की शर्त को पहले समीकरण में बदलें।
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एक समांतर श्रेढ़ी का पहला पद (5) है और उसका (12)वाँ पद उसके (3)वें पद का (4) गुना है। पहले (20) पदों का योग क्या होगा?
The first term of an AP is (5), and its (12)th term is (4) times its (3)rd term. What is the sum of the first (20) terms?
#term condition
#ap sum
#hard
A (1050)
B (1025)
C (1075)
D (1100)
Explanation opens after your attempt
Step 1
Concept
The condition gives (5+11d=4(5+2d)), so (d=5) and \(S_{20}=1050\). Convert the term condition into an equation first.
Step 2
Why this answer is correct
The correct answer is A. (1050). The condition gives (5+11d=4(5+2d)), so (d=5) and \(S_{20}=1050\). Convert the term condition into an equation first.
Step 3
Exam Tip
शर्त से (5+11d=4(5+2d)), इसलिए (d=5) और \(S_{20}=1050\) है। पदों की शर्त को पहले समीकरण में बदलें।
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एक समांतर श्रेढ़ी का पहला पद (6) है और उसका (9)वाँ पद उसके (4)वें पद का (2) गुना है। पहले (25) पदों का योग क्या होगा?
The first term of an AP is (6), and its (9)th term is (2) times its (4)th term. What is the sum of the first (25) terms?
#term condition
#ap sum
#hard
A (1000)
B (1025)
C (1050)
D (1075)
Explanation opens after your attempt
Step 1
Concept
The condition gives (6+8d=2(6+3d)), so (d=3) and \(S_{25}=1050\). Convert the term condition into an equation first.
Step 2
Why this answer is correct
The correct answer is C. (1050). The condition gives (6+8d=2(6+3d)), so (d=3) and \(S_{25}=1050\). Convert the term condition into an equation first.
Step 3
Exam Tip
शर्त से (6+8d=2(6+3d)), इसलिए (d=3) और \(S_{25}=1050\) है। पदों की शर्त को पहले समीकरण में बदलें।
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एक समांतर श्रेढ़ी का पहला पद (4) है और उसका (8)वाँ पद उसके (3)वें पद का (3) गुना है। पहले (12) पदों का योग क्या होगा?
The first term of an AP is (4), and its (8)th term is (3) times its (3)rd term. What is the sum of the first (12) terms?
#term condition
#ap sum
#hard
A (528)
B (552)
C (576)
D (600)
Explanation opens after your attempt
Step 1
Concept
The condition gives (4+7d=3(4+2d)), so (d=8) and \(S_{12}=576\). Convert the term condition into an equation first.
Step 2
Why this answer is correct
The correct answer is C. (576). The condition gives (4+7d=3(4+2d)), so (d=8) and \(S_{12}=576\). Convert the term condition into an equation first.
Step 3
Exam Tip
शर्त से (4+7d=3(4+2d)), इसलिए (d=8) और \(S_{12}=576\)। पदों की शर्त को पहले समीकरण में बदलें।
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समान्तर श्रेणी \(23,31,39,\ldots\) के (n)वें पद का सूत्र \(a_n=8n+15\) है। (36)वां पद क्या होगा?
The (n)th-term formula of the AP \(23,31,39,\ldots\) is \(a_n=8n+15\). What is the (36)th term?
#ap direct-formula nth-term class10
A (293)
B (301)
C (303)
D (311)
Explanation opens after your attempt
Step 1
Concept
\(a_{36}=8\times36+15=303\). Put (n=36) in the formed formula to get the answer directly.
Step 2
Why this answer is correct
The correct answer is C. (303). \(a_{36}=8\times36+15=303\). Put (n=36) in the formed formula to get the answer directly.
Step 3
Exam Tip
\(a_{36}=8\times36+15=303\)। बने हुए सूत्र में (n=36) रखकर सीधे उत्तर पाएं।
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यदि किसी AP का (r)वां पद (3r-2) और (d=4) है तो ((r+6))वां पद क्या होगा?
If the (r)th term of an AP is (3r-2) and (d=4), what is the ((r+6))th term?
#ap symbolic nth-term class10
A (3r+18)
B (3r+20)
C (3r+22)
D (3r+24)
Explanation opens after your attempt
Correct Answer
C. (3r+22)
Step 1
Concept
The ((r+6))th term is (6d) ahead of the (r)th term so (3r-2+24=3r+22). In symbolic questions look at the position gap.
Step 2
Why this answer is correct
The correct answer is C. (3r+22). The ((r+6))th term is (6d) ahead of the (r)th term so (3r-2+24=3r+22). In symbolic questions look at the position gap.
Step 3
Exam Tip
((r+6))वां पद (r)वें पद से (6d) आगे है इसलिए (3r-2+24=3r+22)। प्रतीकात्मक प्रश्न में स्थान अंतर देखें।
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समान्तर श्रेणी \(19,26,33,\ldots\) के (n)वें पद का सूत्र \(a_n=7n+12\) है। (41)वां पद क्या होगा?
The (n)th-term formula of the AP \(19,26,33,\ldots\) is \(a_n=7n+12\). What is the (41)st term?
#ap
#direct-formula
#nth-term
#class10
A (294)
B (304)
C (309)
D (299)
Explanation opens after your attempt
Step 1
Concept
\(a_{41}=7\times41+12=299\). Put only (n=41) in the formed formula.
Step 2
Why this answer is correct
The correct answer is D. (299). \(a_{41}=7\times41+12=299\). Put only (n=41) in the formed formula.
Step 3
Exam Tip
\(a_{41}=7\times41+12=299\)। बने हुए सूत्र में केवल (n=41) रखें।
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यदि किसी समान्तर श्रेणी का (m)वां पद (2m+3) और (d=2) है तो ((m+5))वां पद क्या होगा?
If the (m)th term of an AP is (2m+3) and (d=2), what is the ((m+5))th term?
#ap
#symbolic
#nth-term
#class10
A (2m+8)
B (2m+10)
C (2m+11)
D (2m+13)
Explanation opens after your attempt
Correct Answer
D. (2m+13)
Step 1
Concept
The ((m+5))th term is (5d) ahead of the (m)th term, so (2m+3+10=2m+13). In symbolic terms, look at the position gap.
Step 2
Why this answer is correct
The correct answer is D. (2m+13). The ((m+5))th term is (5d) ahead of the (m)th term, so (2m+3+10=2m+13). In symbolic terms, look at the position gap.
Step 3
Exam Tip
((m+5))वां पद (m)वें पद से (5d) आगे है इसलिए (2m+3+10=2m+13)। प्रतीकात्मक पदों में भी स्थान अंतर देखें।
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समान्तर श्रेणी का पहला पद (25) है और (18)वां पद (93) है। सार्व अंतर क्या है?
The first term of an AP is (25) and the (18)th term is (93). What is the common difference?
#ap
#common-difference
#nth-term
#class10
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
From (93=25+17d), (68=17d) so (d=4). For the (18)th term, the multiplier is (17).
Step 2
Why this answer is correct
The correct answer is C. (4). From (93=25+17d), (68=17d) so (d=4). For the (18)th term, the multiplier is (17).
Step 3
Exam Tip
(93=25+17d) से (68=17d) इसलिए (d=4)। (18)वें पद के लिए गुणक (17) होता है।
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समान्तर श्रेणी \(11,17,23,\ldots\) का (n)वां पद \(a_n=6n+5\) है। इसका (32)वां पद क्या होगा?
The (n)th term of the AP \(11,17,23,\ldots\) is \(a_n=6n+5\). What is its (32)nd term?
#ap
#direct-formula
#nth-term
#class10
A (191)
B (197)
C (203)
D (209)
Explanation opens after your attempt
Step 1
Concept
\(a_{32}=6\times32+5=197\). Substitute the correct value of (n) in the formed formula.
Step 2
Why this answer is correct
The correct answer is B. (197). \(a_{32}=6\times32+5=197\). Substitute the correct value of (n) in the formed formula.
Step 3
Exam Tip
\(a_{32}=6\times32+5=197\)। बनाए गए सूत्र में (n) का सही मान रखें।
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एक समान्तर श्रेणी का पहला पद (18) और (16)वां पद (93) है। सार्व अंतर क्या है?
The first term of an AP is (18) and the (16)th term is (93). What is the common difference?
#ap
#common-difference
#nth-term
#class10
A (5)
B (4)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
(93=18+15d), so (75=15d) and (d=5). For the (16)th term, the multiplier is (15).
Step 2
Why this answer is correct
The correct answer is A. (5). (93=18+15d), so (75=15d) and (d=5). For the (16)th term, the multiplier is (15).
Step 3
Exam Tip
(93=18+15d), इसलिए (75=15d) और (d=5)। (16)वें पद के लिए गुणक (15) होगा।
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यदि किसी समान्तर श्रेणी का (10)वां पद (41) और (20)वां पद (81) है, तो उसका सार्व अंतर क्या है?
If the (10)th term of an AP is (41) and the (20)th term is (81), what is its common difference?
#ap
#common-difference
#nth-term
#class10
A (3)
B (5)
C (4)
D (6)
Explanation opens after your attempt
Step 1
Concept
\(The difference of terms is (81-41=40) and the difference of positions is (10), so (d=4). Use (d=\frac{\)difference of terms}{difference of positions}).
Step 2
Why this answer is correct
\(The correct answer is C. (4). The difference of terms is (81-41=40) and the difference of positions is (10), so (d=4). Use (d=\frac{\)difference of terms}{difference of positions}).
Step 3
Exam Tip
दो पदों का अंतर (81-41=40) है और पद संख्या का अंतर (10), इसलिए (d=4)। \(दो ज्ञात पदों में (d=\frac{\)पदों का अंतर}{स्थान का अंतर}) लगाएं।
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यदि किसी समान्तर श्रेणी का पहला पद (7) और सार्व अंतर (4) है, तो उसका (18)वां पद क्या होगा?
If the first term of an AP is (7) and the common difference is (4), what is its (18)th term?
#ap
#nth-term
#medium
#class10
A (75)
B (71)
C (79)
D (83)
Explanation opens after your attempt
Step 1
Concept
Using (a_n=a+(n-1)d), \(7+17\times4=75\). Exam tip: do not forget (n-1).
Step 2
Why this answer is correct
The correct answer is A. (75). Using (a_n=a+(n-1)d), \(7+17\times4=75\). Exam tip: do not forget (n-1).
Step 3
Exam Tip
सूत्र (a_n=a+(n-1)d) लगाने पर \(7+17\times4=75\)। परीक्षा में (n-1) को भूलना नहीं चाहिए।
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यदि एपी का (4)था पद (21) और (d=6) है तो (10)वाँ पद क्या होगा?
If the (4)th term of an AP is (21) and (d=6), what is the (10)th term?
#ap
#nth-term
#easy
#class10
A (53)
B (55)
C (57)
D (59)
Explanation opens after your attempt
Step 1
Concept
The (10)th term is (6d) after the (4)th term, so (21+36=57). Use the difference in term numbers directly.
Step 2
Why this answer is correct
The correct answer is C. (57). The (10)th term is (6d) after the (4)th term, so (21+36=57). Use the difference in term numbers directly.
Step 3
Exam Tip
(10)वाँ पद (4)थे पद से (6d) आगे है इसलिए (21+36=57)। पद संख्या का अंतर सीधे उपयोग करें।
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यदि एपी का प्रथम पद (-12) और सार्व अंतर (5) है तो (16)वाँ पद क्या होगा?
If the first term of an AP is (-12) and the common difference is (5), what is the (16)th term?
#ap
#nth-term
#easy
#class10
A (61)
B (63)
C (65)
D (67)
Explanation opens after your attempt
Step 1
Concept
\(a_{16}=-12+15\times5=63\). First calculate (15d), then add the first term.
Step 2
Why this answer is correct
The correct answer is B. (63). \(a_{16}=-12+15\times5=63\). First calculate (15d), then add the first term.
Step 3
Exam Tip
\(a_{16}=-12+15\times5=63\)। पहले (15d) निकालें फिर प्रथम पद जोड़ें।
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यदि किसी एपी का प्रथम पद (9) और सार्व अंतर (10) है तो (7)वाँ पद क्या होगा?
If the first term of an AP is (9) and the common difference is (10), what is the (7)th term?
#ap
#nth-term
#easy
#class10
A (59)
B (69)
C (79)
D (89)
Explanation opens after your attempt
Step 1
Concept
\(a_7=9+6\times10=69\). For the (7)th term, (6d) is added.
Step 2
Why this answer is correct
The correct answer is B. (69). \(a_7=9+6\times10=69\). For the (7)th term, (6d) is added.
Step 3
Exam Tip
\(a_7=9+6\times10=69\)। (7)वें पद के लिए (6d) जोड़ना होता है।
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यदि किसी एपी का (3)रा पद (14) और (d=5) है तो (7)वाँ पद क्या होगा?
If the (3)rd term of an AP is (14) and (d=5), what is the (7)th term?
#ap
#nth-term
#easy
#class10
A (29)
B (31)
C (34)
D (36)
Explanation opens after your attempt
Step 1
Concept
The (7)th term is (4d) after the (3)rd term, so (14+20=34). Count the gap between terms correctly.
Step 2
Why this answer is correct
The correct answer is C. (34). The (7)th term is (4d) after the (3)rd term, so (14+20=34). Count the gap between terms correctly.
Step 3
Exam Tip
(7)वाँ पद (3)रे पद से (4d) आगे है इसलिए (14+20=34)। बीच के पदों की संख्या सही गिनें।
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यदि एपी का प्रथम पद (-2) और सार्व अंतर (6) है तो (12)वाँ पद क्या होगा?
If the first term of an AP is (-2) and the common difference is (6), what is the (12)th term?
#ap
#nth-term
#easy
#class10
A (62)
B (64)
C (66)
D (68)
Explanation opens after your attempt
Step 1
Concept
\(a_{12}=-2+11\times6=64\). Multiply first and then add (-2).
Step 2
Why this answer is correct
The correct answer is B. (64). \(a_{12}=-2+11\times6=64\). Multiply first and then add (-2).
Step 3
Exam Tip
\(a_{12}=-2+11\times6=64\)। पहले गुणा करें फिर (-2) जोड़ें।
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यदि किसी एपी का (5)वाँ पद (22) और (d=6) है तो (8)वाँ पद क्या है?
If the (5)th term of an AP is (22) and (d=6), what is the (8)th term?
#ap
#nth-term
#easy
#class10
A (34)
B (36)
C (38)
D (40)
Explanation opens after your attempt
Step 1
Concept
The (8)th term is (3d) after the (5)th term, so (22+18=40). Counting the gap between terms is an easy method.
Step 2
Why this answer is correct
The correct answer is D. (40). The (8)th term is (3d) after the (5)th term, so (22+18=40). Counting the gap between terms is an easy method.
Step 3
Exam Tip
(8)वाँ पद (5)वें पद से (3d) आगे है इसलिए (22+18=40)। पदों का अंतर गिनना आसान तरीका है।
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यदि एपी का (7)वाँ पद (31) है और (d=4) है तो (10)वाँ पद क्या होगा?
If the (7)th term of an AP is (31) and (d=4), what is the (10)th term?
#ap
#nth-term
#easy
#class10
A (39)
B (41)
C (43)
D (45)
Explanation opens after your attempt
Step 1
Concept
The (10)th term is (3d) after the (7)th term, so \(31+3\times4=43\). The difference method is quick for nearby terms.
Step 2
Why this answer is correct
The correct answer is C. (43). The (10)th term is (3d) after the (7)th term, so \(31+3\times4=43\). The difference method is quick for nearby terms.
Step 3
Exam Tip
(10)वाँ पद (7)वें पद से (3d) आगे है इसलिए \(31+3\times4=43\)। पास के पदों के लिए अंतर विधि तेज होती है।
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यदि एपी का प्रथम पद (15) और सार्व अंतर (-4) है तो (8)वाँ पद क्या होगा?
If the first term of an AP is (15) and the common difference is (-4), what is the (8)th term?
#ap
#nth-term
#easy
#class10
A (-13)
B (-11)
C (-9)
D (-7)
Explanation opens after your attempt
Step 1
Concept
(a_8=15+7(-4)=-13). Writing negative (d) in brackets is useful.
Step 2
Why this answer is correct
The correct answer is A. (-13). (a_8=15+7(-4)=-13). Writing negative (d) in brackets is useful.
Step 3
Exam Tip
(a_8=15+7(-4)=-13)। ऋणात्मक (d) को कोष्ठक में लिखना उपयोगी है।
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यदि किसी एपी का प्रथम पद (5) और सार्व अंतर (3) है तो (8)वाँ पद क्या होगा?
If the first term of an AP is (5) and common difference is (3), what is the (8)th term?
#ap
#nth-term
#easy
#class10
A (23)
B (24)
C (26)
D (28)
Explanation opens after your attempt
Step 1
Concept
Using (a_n=a+(n-1)d), \(5+7\times3=26\). In exams, do not forget (n-1).
Step 2
Why this answer is correct
The correct answer is C. (26). Using (a_n=a+(n-1)d), \(5+7\times3=26\). In exams, do not forget (n-1).
Step 3
Exam Tip
सूत्र (a_n=a+(n-1)d) लगाएं तो \(5+7\times3=26\)। परीक्षा में (n-1) लेना न भूलें।
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किसी समांतर श्रेढ़ी का (n)वाँ पद \(a_n=2n+3\) है। (18)वाँ पद क्या होगा?
The (n)th term of an AP is \(a_n=2n+3\). What will be the (18)th term?
#nth term
#ap expression
#class 10
A (39)
B (41)
C (36)
D (38)
Explanation opens after your attempt
Step 1
Concept
Putting (n=18), \(a_{18}=2\times18+3=39\). Substitute the term number directly in the given \(a_n\).
Step 2
Why this answer is correct
The correct answer is A. (39). Putting (n=18), \(a_{18}=2\times18+3=39\). Substitute the term number directly in the given \(a_n\).
Step 3
Exam Tip
(n=18) रखने पर \(a_{18}=2\times18+3=39\)। दिए गए \(a_n\) में सीधे पद संख्या रखें।
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एक समांतर श्रेढ़ी का प्रथम पद (25) और सार्व अंतर (4) है। (21)वाँ पद क्या होगा?
The first term of an AP is (25) and the common difference is (4). What will be the (21)st term?
#ap formula
#nth term
#class 10
A (101)
B (105)
C (109)
D (96)
Explanation opens after your attempt
Step 1
Concept
\(a_{21}=25+20\times4=105\). Do not forget to subtract (1) from the term number.
Step 2
Why this answer is correct
The correct answer is B. (105). \(a_{21}=25+20\times4=105\). Do not forget to subtract (1) from the term number.
Step 3
Exam Tip
\(a_{21}=25+20\times4=105\)। पद संख्या से (1) घटाना न भूलें।
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यदि समांतर श्रेढ़ी का प्रथम पद (6) और सार्व अंतर (7) है, तो (11)वाँ पद क्या है?
If the first term of an AP is (6) and the common difference is (7), what is the (11)th term?
#ap common difference
#nth term
#easy
A (83)
B (70)
C (79)
D (76)
Explanation opens after your attempt
Step 1
Concept
\(a_{11}=6+10\times7=76\). Up to the (11)th term, the difference is added (10) times.
Step 2
Why this answer is correct
The correct answer is D. (76). \(a_{11}=6+10\times7=76\). Up to the (11)th term, the difference is added (10) times.
Step 3
Exam Tip
\(a_{11}=6+10\times7=76\)। (11)वें पद तक (10) बार अंतर जुड़ता है।
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समांतर श्रेढ़ी में प्रथम पद (a=4) और सार्व अंतर (d=3) है। इसका (10)वाँ पद क्या होगा?
In an AP, first term (a=4) and common difference (d=3). What is the (10)th term?
#arithmetic progression
#nth term
#easy
#class 10
A (31)
B (30)
C (34)
D (27)
Explanation opens after your attempt
Step 1
Concept
Using (a_n=a+(n-1)d), \(a_{10}=4+9\times3=31\). Exam tip: write (n-1) carefully.
Step 2
Why this answer is correct
The correct answer is A. (31). Using (a_n=a+(n-1)d), \(a_{10}=4+9\times3=31\). Exam tip: write (n-1) carefully.
Step 3
Exam Tip
सूत्र (a_n=a+(n-1)d) लगाने पर \(a_{10}=4+9\times3=31\)। परीक्षा में (n-1) को ध्यान से लिखें।
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किस मान के लिए ((r+4)x-3 +(r-1)x-2 +9) अचर बहुपद बन सकता है?
For what value of (r) can ((r+4)x-3 +(r-1)x-2 +9) become a constant polynomial?
#constant polynomial
#parameter
#condition
A (r=-4)
B (r=1)
C (r=0)
D ऐसा कोई मान नहीं / No such value
Explanation opens after your attempt
Correct Answer
D. ऐसा कोई मान नहीं / No such value
Step 1
Concept
For a constant polynomial, both (r+4=0) and (r-1=0) are needed, which is impossible together. All variable terms must vanish.
Step 2
Why this answer is correct
The correct answer is D. ऐसा कोई मान नहीं / No such value. For a constant polynomial, both (r+4=0) and (r-1=0) are needed, which is impossible together. All variable terms must vanish.
Step 3
Exam Tip
अचर बहुपद के लिए (r+4=0) और (r-1=0) दोनों चाहिए, जो साथ संभव नहीं हैं। सभी चर वाले पद हटने चाहिए।
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निम्न में से कौन-सा स्थिर बहुपद है?
Which of the following is a constant polynomial?
#constant-polynomial
#degree
#basic-concept
A (7)
B (7x)
C (x+7)
D \(x^2+7\)
Explanation opens after your attempt
Step 1
Concept
A constant polynomial has no variable term, so (7) is a constant polynomial. A non-zero constant polynomial has degree (0).
Step 2
Why this answer is correct
The correct answer is A. (7). A constant polynomial has no variable term, so (7) is a constant polynomial. A non-zero constant polynomial has degree (0).
Step 3
Exam Tip
स्थिर बहुपद में चर का पद नहीं होता, इसलिए (7) स्थिर बहुपद है। अशून्य स्थिर बहुपद की घात (0) होती है।
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किस मान के लिए ((n-2)x-2 +(n+1)x+5) अचर बहुपद बन सकता है?
For what value of (n) can ((n-2)x-2 +(n+1)x+5) become a constant polynomial?
#constant polynomial
#parameter
#condition
A (n=2)
B (n=-1)
C (n=1)
D ऐसा कोई मान नहीं / No such value
Explanation opens after your attempt
Correct Answer
D. ऐसा कोई मान नहीं / No such value
Step 1
Concept
For a constant polynomial, both (n-2=0) and (n+1=0) are needed, which is impossible together. All variable terms must vanish.
Step 2
Why this answer is correct
The correct answer is D. ऐसा कोई मान नहीं / No such value. For a constant polynomial, both (n-2=0) and (n+1=0) are needed, which is impossible together. All variable terms must vanish.
Step 3
Exam Tip
अचर बहुपद के लिए (n-2=0) और (n+1=0) दोनों चाहिए, जो साथ संभव नहीं हैं। सभी चर वाले पद हटने चाहिए।
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किस मान के लिए ((m+1)x-2 +(m-2 )x+7) अचर बहुपद बन सकता है?
For what value of (m) can ((m+1)x-2 +(m-2 )x+7) become a constant polynomial?
#constant polynomial
#parameter
#condition
A (m=-1)
B (m=2)
C ऐसा कोई मान नहीं / No such value
D (m=1)
Explanation opens after your attempt
Correct Answer
C. ऐसा कोई मान नहीं / No such value
Step 1
Concept
For a constant polynomial, both (m+1=0) and (m-2 =0) are needed, which is impossible together. All variable terms must vanish.
Step 2
Why this answer is correct
The correct answer is C. ऐसा कोई मान नहीं / No such value. For a constant polynomial, both (m+1=0) and (m-2 =0) are needed, which is impossible together. All variable terms must vanish.
Step 3
Exam Tip
अचर बहुपद के लिए (m+1=0) और (m-2 =0) दोनों चाहिए, जो साथ संभव नहीं हैं। सभी चर वाले पद हटने चाहिए।
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अशून्य अचर बहुपद (p(x)=-18) की घात क्या है?
What is the degree of the non-zero constant polynomial (p(x)=-18)?
#constant polynomial
#degree
#definition
A (0)
B (1)
C (18)
D परिभाषित नहीं / Undefined
Explanation opens after your attempt
Step 1
Concept
A non-zero constant polynomial has degree (0). A constant number is linked with degree (0).
Step 2
Why this answer is correct
The correct answer is A. (0). A non-zero constant polynomial has degree (0). A constant number is linked with degree (0).
Step 3
Exam Tip
अशून्य अचर बहुपद की घात (0) होती है। अचर संख्या का अर्थ घात (0) से जुड़ा है।
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यदि किसी गैर-शून्य नियत बहुपद की घात पूछी जाए, तो सही उत्तर क्या होगा?
If the degree of a non-zero constant polynomial is asked, what will be the correct answer?
#constant-polynomial
#degree
#concept
A (0)
B (1)
C परिभाषित नहीं / Not defined
D बहुपद नहीं / Not a polynomial
Explanation opens after your attempt
Step 1
Concept
The degree of a non-zero constant polynomial is (0). Keep it separate from the zero polynomial.
Step 2
Why this answer is correct
The correct answer is A. (0). The degree of a non-zero constant polynomial is (0). Keep it separate from the zero polynomial.
Step 3
Exam Tip
गैर-शून्य नियत बहुपद की घात (0) होती है। इसे शून्य बहुपद से अलग रखें।
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निम्न में से कौन सा बहुपद नियत बहुपद नहीं है?
Which of the following is not a constant polynomial?
#constant-polynomial
#classification
A (8)
B (-3)
C (0)
D (2x+1)
Explanation opens after your attempt
Step 1
Concept
(2x+1) contains the variable (x), so it is not a constant polynomial. A constant polynomial has no variable term.
Step 2
Why this answer is correct
The correct answer is D. (2x+1). (2x+1) contains the variable (x), so it is not a constant polynomial. A constant polynomial has no variable term.
Step 3
Exam Tip
(2x+1) में चर (x) है इसलिए यह नियत बहुपद नहीं है। नियत बहुपद में चर वाला पद नहीं होता।
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अशून्य अचर बहुपद (p(x)=12) की घात क्या होती है?
What is the degree of the non-zero constant polynomial (p(x)=12)?
#constant polynomial
#degree
#definition
A (0)
B (1)
C (12)
D परिभाषित नहीं / Undefined
Explanation opens after your attempt
Step 1
Concept
A non-zero constant polynomial has degree (0). Keep it separate from the zero polynomial.
Step 2
Why this answer is correct
The correct answer is A. (0). A non-zero constant polynomial has degree (0). Keep it separate from the zero polynomial.
Step 3
Exam Tip
अशून्य अचर बहुपद की घात (0) होती है। शून्य बहुपद से इसे अलग रखें।
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कौन सा बहुपद नियत बहुपद है?
Which is a constant polynomial?
#polynomials
#constant-polynomial
#easy
A (6)
B (x+6)
C (6x)
D \(x^2+6\)
Explanation opens after your attempt
Step 1
Concept
A polynomial with no variable is a constant polynomial. (6) has no (x).
Step 2
Why this answer is correct
The correct answer is A. (6). A polynomial with no variable is a constant polynomial. (6) has no (x).
Step 3
Exam Tip
जिस बहुपद में चर नहीं होता वह नियत बहुपद है। (6) में (x) नहीं है।
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स्थिर बहुपद (p(x)=5) के ग्राफ के वास्तविक शून्यक कितने हैं?
How many real zeroes does the constant polynomial (p(x)=5) have?
#constant-polynomial
#no-zero
#graph
A शून्य / Zero
B एक / One
C पाँच / Five
D अनंत / Infinite
Explanation opens after your attempt
Correct Answer
A. शून्य / Zero
Step 1
Concept
The line (y=5) is parallel to the (x)-axis and does not meet it. So it has no real zero.
Step 2
Why this answer is correct
The correct answer is A. शून्य / Zero. The line (y=5) is parallel to the (x)-axis and does not meet it. So it has no real zero.
Step 3
Exam Tip
रेखा (y=5) (x)-अक्ष के समानांतर है और उससे नहीं मिलती। इसलिए कोई वास्तविक शून्यक नहीं है।
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अशून्य स्थिर बहुपद (p(x)=5) के आलेख का (x)-अक्ष से संबंध क्या है?
What is the relation of the graph of the non-zero constant polynomial (p(x)=5) with the (x)-axis?
#constant polynomial graph
A यह (x)-अक्ष के समांतर है और उसे नहीं काटता / It is parallel to the (x)-axis and does not cut it
B यह (x)-अक्ष को दो बार काटता है / It cuts the (x)-axis twice
C यह मूल बिंदु से गुजरता है / It passes through the origin
D यह (y)-अक्ष के समांतर है / It is parallel to the (y)-axis
Explanation opens after your attempt
Correct Answer
A. यह (x)-अक्ष के समांतर है और उसे नहीं काटता / It is parallel to the (x)-axis and does not cut it
Step 1
Concept
The value (p(x)=5) is never (0) so it has no zero. Tip: a non-zero constant polynomial has no zero.
Step 2
Why this answer is correct
The correct answer is A. यह (x)-अक्ष के समांतर है और उसे नहीं काटता / It is parallel to the (x)-axis and does not cut it. The value (p(x)=5) is never (0) so it has no zero. Tip: a non-zero constant polynomial has no zero.
Step 3
Exam Tip
(p(x)=5) कभी (0) नहीं होता इसलिए शून्यक नहीं है। टिप: अशून्य स्थिर बहुपद का शून्यक नहीं होता।
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किसी स्थिर अशून्य बहुपद (p(x)=-3) का ग्राफ (x)-अक्ष को क्यों नहीं काटता?
Why does the graph of the non-zero constant polynomial (p(x)=-3) not cut the (x)-axis?
#constant-polynomial
#no-zero
#x-axis
#easy
A क्योंकि (y) हमेशा (-3) रहता है / Because (y) always remains (-3)
B क्योंकि (x) हमेशा (-3) रहता है / Because (x) always remains (-3)
C क्योंकि ग्राफ पर कोई बिंदु नहीं होता / Because the graph has no point
D क्योंकि यह परवलय है / Because it is a parabola
Explanation opens after your attempt
Correct Answer
A. क्योंकि (y) हमेशा (-3) रहता है / Because (y) always remains (-3)
Step 1
Concept
For (p(x)=-3), the (y)-value is never (0). So the graph does not cut the (x)-axis and has no zero.
Step 2
Why this answer is correct
The correct answer is A. क्योंकि (y) हमेशा (-3) रहता है / Because (y) always remains (-3). For (p(x)=-3), the (y)-value is never (0). So the graph does not cut the (x)-axis and has no zero.
Step 3
Exam Tip
(p(x)=-3) का (y)-मान कभी (0) नहीं होता। इसलिए ग्राफ (x)-अक्ष को नहीं काटता और कोई शून्यक नहीं है।
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किसी स्थिर अशून्य बहुपद जैसे (p(x)=5) के ग्राफ से शून्यकों के बारे में क्या पता चलता है?
What does the graph of a non-zero constant polynomial like (p(x)=5) show about its zeroes?
#constant-polynomial
#no-zero
#graph
#easy
A कोई शून्यक नहीं / No zero
B एक शून्यक / One zero
C दो शून्यक / Two zeroes
D अनंत शून्यक / Infinite zeroes
Explanation opens after your attempt
Correct Answer
A. कोई शून्यक नहीं / No zero
Step 1
Concept
The graph of (p(x)=5) is a line parallel to the (x)-axis and does not cut it. Hence it has no zero.
Step 2
Why this answer is correct
The correct answer is A. कोई शून्यक नहीं / No zero. The graph of (p(x)=5) is a line parallel to the (x)-axis and does not cut it. Hence it has no zero.
Step 3
Exam Tip
(p(x)=5) का ग्राफ (x)-अक्ष के समानांतर रेखा है जो (x)-अक्ष को नहीं काटती। इसलिए इसका कोई शून्यक नहीं है।
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(p(x)=x-5 +3x-3 -2) में कौन सी घात अनुपस्थित है?
Which power is missing in (p(x)=x-5 +3x-3 -2)?
#missing power
#coefficient zero
#polynomial
A \(x^5\)
B \(x^4\)
C \(x^3\)
D \(x^0\)
Explanation opens after your attempt
Correct Answer
B. \(x^4\)
Step 1
Concept
The term \(x^4\) is not present in this polynomial. A missing term has coefficient (0).
Step 2
Why this answer is correct
The correct answer is B. \(x^4\). The term \(x^4\) is not present in this polynomial. A missing term has coefficient (0).
Step 3
Exam Tip
इस बहुपद में \(x^4\) का पद नहीं है। अनुपस्थित पद का गुणांक (0) होता है।
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(p(x)=x-4 +2x-2 +1) में कौन सी घात अनुपस्थित है?
Which power is missing in (p(x)=x-4 +2x-2 +1)?
#missing power
#coefficient zero
#polynomial
A \(x^4\)
B \(x^3\)
C \(x^2\)
D \(x^0\)
Explanation opens after your attempt
Correct Answer
B. \(x^3\)
Step 1
Concept
The term \(x^3\) is not present in this polynomial. A missing term has coefficient (0).
Step 2
Why this answer is correct
The correct answer is B. \(x^3\). The term \(x^3\) is not present in this polynomial. A missing term has coefficient (0).
Step 3
Exam Tip
इस बहुपद में \(x^3\) का पद नहीं है। अनुपस्थित पद का गुणांक (0) होता है।
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बहुपद \(4x^3-2x^2+7x-9\) में \(x^2\) के गुणांक और नियत पद का योग क्या है?
In the polynomial \(4x^3-2x^2+7x-9\), what is the sum of the coefficient of \(x^2\) and the constant term?
#coefficient
#constant-term
#polynomial
A (-11)
B (-7)
C (7)
D (11)
Explanation opens after your attempt
Step 1
Concept
The coefficient of \(x^2\) is (-2) and the constant term is (-9). Their sum is (-11).
Step 2
Why this answer is correct
The correct answer is A. (-11). The coefficient of \(x^2\) is (-2) and the constant term is (-9). Their sum is (-11).
Step 3
Exam Tip
\(x^2\) का गुणांक (-2) और नियत पद (-9) है। उनका योग (-11) है।
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बहुपद \(7x^2+5x-11\) में स्थिर पद क्या है?
What is the constant term in the polynomial \(7x^2+5x-11\)?
#constant_term
#polynomials
#basics
A (7)
B (5)
C \(-11\)
D (2)
Explanation opens after your attempt
Correct Answer
C. \(-11\)
Step 1
Concept
The constant term is the term without (x). Here the constant term is (-11).
Step 2
Why this answer is correct
The correct answer is C. \(-11\). The constant term is the term without (x). Here the constant term is (-11).
Step 3
Exam Tip
स्थिर पद वह होता है जिसमें (x) नहीं होता। यहाँ स्थिर पद (-11) है।
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यदि किसी एकक द्विघात बहुपद के शून्यक \(4+\sqrt{11}\) और \(4-\sqrt{11}\) हैं, तो स्थिर पद क्या होगा?
If the zeroes of a monic quadratic polynomial are \(4+\sqrt{11}\) and \(4-\sqrt{11}\), what will be the constant term?
#conjugate-zeroes
#constant-term
#quadratic
A (5)
B (27)
C (8)
D \(16+\sqrt{11}\)
Explanation opens after your attempt
Step 1
Concept
The constant term is the product, and (\(4+\sqrt{11}\)\(4-\sqrt{11}\)=16-11=5). In conjugate products, the irrational middle part cancels.
Step 2
Why this answer is correct
The correct answer is A. (5). The constant term is the product, and (\(4+\sqrt{11}\)\(4-\sqrt{11}\)=16-11=5). In conjugate products, the irrational middle part cancels.
Step 3
Exam Tip
स्थिर पद गुणनफल है और (\(4+\sqrt{11}\)\(4-\sqrt{11}\)=16-11=5)। संयुग्मी गुणनफल में बीच का अपरिमेय भाग हट जाता है।
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बहुपद \(x^5-4x^2+10\) में लुप्त \(x^4\) पद का गुणांक क्या है?
What is the coefficient of the missing \(x^4\) term in \(x^5-4x^2+10\)?
#missing_term
#coefficient
#polynomials
A (1)
B \(-4\)
C (0)
D (10)
Explanation opens after your attempt
Step 1
Concept
A missing term is treated as having coefficient (0). So the coefficient of \(x^4\) is (0).
Step 2
Why this answer is correct
The correct answer is C. (0). A missing term is treated as having coefficient (0). So the coefficient of \(x^4\) is (0).
Step 3
Exam Tip
जो पद लिखा नहीं है उसका गुणांक (0) माना जाता है। इसलिए \(x^4\) का गुणांक (0) है।
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यदि \(9,9,9,\ldots\) को \(2,5,8,\ldots\) से पद-दर-पद जोड़ा जाए तो नए अनुक्रम का (d) क्या होगा?
If \(9,9,9,\ldots\) is added term by term to \(2,5,8,\ldots\), what will be (d) of the new sequence?
#ap
#constant sequence
#sum
#hard
A (0)
B (3)
C (9)
D (12)
Explanation opens after your attempt
Step 1
Concept
The constant sequence has (d=0), and the second has (d=3), so the sum has (d=3). Adding a constant sequence does not change (d).
Step 2
Why this answer is correct
The correct answer is B. (3). The constant sequence has (d=0), and the second has (d=3), so the sum has (d=3). Adding a constant sequence does not change (d).
Step 3
Exam Tip
स्थिर अनुक्रम का (d=0) है और दूसरे का (d=3) है, इसलिए योग का (d=3)। स्थिर अनुक्रम जोड़ने से (d) नहीं बदलता।
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यदि \(13, 13, 13,\ldots\) को \(1, 4, 7,\ldots\) से पद-दर-पद घटाया जाए, तो नए अनुक्रम का (d) क्या होगा?
If \(1, 4, 7,\ldots\) is subtracted term by term from \(13, 13, 13,\ldots\), what will be (d) of the new sequence?
#ap
#constant sequence
#difference
#expert
A (-3)
B (0)
C (3)
D (13)
Explanation opens after your attempt
Step 1
Concept
The constant sequence has (d=0), and the second has (d=3), so the new (d=0-3=-3). Even with a constant sequence, subtraction can change (d).
Step 2
Why this answer is correct
The correct answer is A. (-3). The constant sequence has (d=0), and the second has (d=3), so the new (d=0-3=-3). Even with a constant sequence, subtraction can change (d).
Step 3
Exam Tip
स्थिर अनुक्रम का (d=0) और दूसरे का (d=3) है, इसलिए नया (d=0-3=-3)। स्थिर अनुक्रम घटाव में भी (d) बदल सकता है।
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यदि \(5, 5, 5,\ldots\) को \(2, 4, 6,\ldots\) से पद-दर-पद जोड़ा जाए, तो नए अनुक्रम का (d) क्या होगा?
If \(5, 5, 5,\ldots\) is added term by term to \(2, 4, 6,\ldots\), what will be (d) of the new sequence?
#ap
#constant sequence
#sum
#hard
A (0)
B (2)
C (5)
D (7)
Explanation opens after your attempt
Step 1
Concept
The first sequence has (d=0) and the second has (d=2), so the new (d=2). Adding a constant sequence does not change (d).
Step 2
Why this answer is correct
The correct answer is B. (2). The first sequence has (d=0) and the second has (d=2), so the new (d=2). Adding a constant sequence does not change (d).
Step 3
Exam Tip
पहले अनुक्रम का (d=0) और दूसरे का (d=2) है, इसलिए नया (d=2)। स्थिर अनुक्रम जोड़ने से (d) नहीं बदलता।
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समीकरण \(x^2-7=0\) में रैखिक पद कौन-सा है?
What is the linear term in \(x^2-7=0\)?
#quadratic-equations
#linear-term
#missing-term
A \(x^2\)
B (-7)
C (0x)
D (7x)
Explanation opens after your attempt
Step 1
Concept
There is no (x) term, so the linear term is considered (0x). A missing term has coefficient (0).
Step 2
Why this answer is correct
The correct answer is C. (0x). There is no (x) term, so the linear term is considered (0x). A missing term has coefficient (0).
Step 3
Exam Tip
इसमें (x) वाला पद नहीं है इसलिए रैखिक पद (0x) माना जाता है। अनुपस्थित पद का गुणांक (0) होता है।
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फूट डालो और राज करो नीति को अल्पकालिक नियंत्रण और दीर्घकालिक संकट दोनों से कैसे जोड़ा जा सकता है?
How can divide and rule policy be linked with both short term control and long term crisis?
#divide-and-rule
#short-term-control
#long-term-crisis
A इससे तत्काल विरोध कमजोर हो सकता था लेकिन सामाजिक अविश्वास बचता था / It could weaken immediate resistance but leave social distrust
B इससे स्थायी समानता बनती थी / It created permanent equality
C इससे उपनिवेशवाद तुरंत समाप्त होता था / It immediately ended colonialism
D यह केवल वित्तीय नीति थी / It was only financial policy
Explanation opens after your attempt
Correct Answer
A. इससे तत्काल विरोध कमजोर हो सकता था लेकिन सामाजिक अविश्वास बचता था / It could weaken immediate resistance but leave social distrust
Step 1
Concept
This policy used division for control. For exams also write its legacy.
Step 2
Why this answer is correct
The correct answer is A. इससे तत्काल विरोध कमजोर हो सकता था लेकिन सामाजिक अविश्वास बचता था / It could weaken immediate resistance but leave social distrust. This policy used division for control. For exams also write its legacy.
Step 3
Exam Tip
यह नीति नियंत्रण के लिए विभाजन का उपयोग करती थी। परीक्षा में इसकी विरासत भी लिखें।
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किसी समांतर श्रेढ़ी के पहले पद और (60)वें पद का योग (300) है। (21)वें पद से (40)वें पद तक का योग ज्ञात कीजिए।
The sum of the first term and the (60)th term of an AP is (300). Find the sum from the (21)st term to the (40)th term.
#symmetric terms
#range sum
#ap
A (2900)
B (2950)
C (3000)
D (3050)
Explanation opens after your attempt
Step 1
Concept
\(a_{21}+a_{40}=a_1+a_{60}=300\), so the sum of (20) terms is (3000). Sums of symmetric terms are equal in an AP.
Step 2
Why this answer is correct
The correct answer is C. (3000). \(a_{21}+a_{40}=a_1+a_{60}=300\), so the sum of (20) terms is (3000). Sums of symmetric terms are equal in an AP.
Step 3
Exam Tip
\(a_{21}+a_{40}=a_1+a_{60}=300\), इसलिए (20) पदों का योग (3000) है। सममित पदों का योग बराबर होता है।
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किसी समांतर श्रेढ़ी के पहले पद और (40)वें पद का योग (210) है। (11)वें पद से (30)वें पद तक का योग ज्ञात कीजिए।
The sum of the first term and the (40)th term of an AP is (210). Find the sum from the (11)th term to the (30)th term.
#symmetric terms
#range sum
#ap
A (2000)
B (2100)
C (2200)
D (2300)
Explanation opens after your attempt
Step 1
Concept
\(a_{11}+a_{30}=a_1+a_{40}=210\), so the sum of (20) terms is (2100). Sums of symmetric terms are equal in an AP.
Step 2
Why this answer is correct
The correct answer is B. (2100). \(a_{11}+a_{30}=a_1+a_{40}=210\), so the sum of (20) terms is (2100). Sums of symmetric terms are equal in an AP.
Step 3
Exam Tip
\(a_{11}+a_{30}=a_1+a_{40}=210\), इसलिए (20) पदों का योग (2100) है। सममित पदों का योग बराबर होता है।
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किसी समांतर श्रेढ़ी में पहले (20) पदों का योग (740) है और (20)वाँ पद (60) है। पहला पद ज्ञात कीजिए।
In an AP, the sum of the first (20) terms is (740), and the (20)th term is (60). Find the first term.
#first term
#last term
#sum
#ap
A (10)
B (14)
C (18)
D (22)
Explanation opens after your attempt
Step 1
Concept
From (740=10(a+60)), (a=14). When the (n)th term is given, use it as the last term for the first (n) terms.
Step 2
Why this answer is correct
The correct answer is B. (14). From (740=10(a+60)), (a=14). When the (n)th term is given, use it as the last term for the first (n) terms.
Step 3
Exam Tip
(740=10(a+60)) से (a=14) मिलता है। जब (n)वाँ पद दिया हो तो उसे अंतिम पद की तरह इस्तेमाल करें।
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(600) से कम (13) के धनात्मक गुणजों में अंतिम पद क्या है?
What is the last term among the positive multiples of (13) less than (600)?
#ap multiples last-term nth-term
A (585)
B (598)
C (611)
D (624)
Explanation opens after your attempt
Step 1
Concept
In (13n<600), the greatest (n=46) so the term is \(13\times46=598\). Take the greatest integer below the limit.
Step 2
Why this answer is correct
The correct answer is B. (598). In (13n<600), the greatest (n=46) so the term is \(13\times46=598\). Take the greatest integer below the limit.
Step 3
Exam Tip
(13n<600) में सबसे बड़ा (n=46) है इसलिए पद \(13\times46=598\)। सीमा से कम सबसे बड़ा पूर्णांक लें।
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समान्तर श्रेणी \(73,68,63,\ldots\) का (n)वां पद (-12) है। (n) क्या है?
The (n)th term of the AP \(73,68,63,\ldots\) is (-12). What is (n)?
#ap negative-term term-number class10
A (16)
B (17)
C (18)
D (19)
Explanation opens after your attempt
Step 1
Concept
From (-12=73+(n-1)(-5)), (85=5(n-1)) so (n=18). In a decreasing AP keep signs correct up to the negative target.
Step 2
Why this answer is correct
The correct answer is C. (18). From (-12=73+(n-1)(-5)), (85=5(n-1)) so (n=18). In a decreasing AP keep signs correct up to the negative target.
Step 3
Exam Tip
(-12=73+(n-1)(-5)) से (85=5(n-1)) इसलिए (n=18)। घटती AP में ऋणात्मक लक्ष्य तक चिन्ह सही रखें।
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यदि AP \(z,z+5,z+10,\ldots\) का (19)वां पद (112) है तो (z) क्या होगा?
If the (19)th term of the AP \(z,z+5,z+10,\ldots\) is (112), what is (z)?
#ap variable-first-term nth-term class10
A (18)
B (20)
C (22)
D (24)
Explanation opens after your attempt
Step 1
Concept
From \(112=z+18\times5\), (z=22). Treat the variable first term as (a) and apply the formula.
Step 2
Why this answer is correct
The correct answer is C. (22). From \(112=z+18\times5\), (z=22). Treat the variable first term as (a) and apply the formula.
Step 3
Exam Tip
\(112=z+18\times5\) से (z=22)। चर वाले पहले पद को (a) मानकर सूत्र लगाएं।
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समान्तर श्रेणी \(7,12,17,\ldots\) में (180) से कम अंतिम पद क्या है?
In the AP \(7,12,17,\ldots\), what is the last term less than (180)?
#ap last-term-less-than nth-term class10
A (172)
B (175)
C (177)
D (179)
Explanation opens after your attempt
Step 1
Concept
The terms are (7+5(n-1)). The last term less than (180) is (177) because the next term will be (182).
Step 2
Why this answer is correct
The correct answer is C. (177). The terms are (7+5(n-1)). The last term less than (180) is (177) because the next term will be (182).
Step 3
Exam Tip
पद (7+5(n-1)) हैं। (180) से कम अंतिम पद (177) है क्योंकि अगला पद (182) होगा।
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एक AP में (a=63) और (d=-4) है। कौन-सा पद (-1) होगा?
In an AP (a=63) and (d=-4). Which term will be (-1)?
#ap negative-term term-number class10
A (15)वां / (15)th
B (16)वां / (16)th
C (17)वां / (17)th
D (18)वां / (18)th
Explanation opens after your attempt
Correct Answer
C. (17)वां / (17)th
Step 1
Concept
From (-1=63+(n-1)(-4)), (64=4(n-1)) so (n=17). Handle signs carefully with a negative target term.
Step 2
Why this answer is correct
The correct answer is C. (17)वां / (17)th. From (-1=63+(n-1)(-4)), (64=4(n-1)) so (n=17). Handle signs carefully with a negative target term.
Step 3
Exam Tip
(-1=63+(n-1)(-4)) से (64=4(n-1)) इसलिए (n=17)। ऋणात्मक लक्ष्य पद में चिन्हों को ध्यान से संभालें।
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समान्तर श्रेणी \(105,98,91,\ldots\) का प्रथम ऋणात्मक पद कौन-सा है?
Which is the first negative term of the AP \(105,98,91,\ldots\)?
#ap first-negative-term nth-term class10
A (15)वां / (15)th
B (16)वां / (16)th
C (17)वां / (17)th
D (18)वां / (18)th
Explanation opens after your attempt
Correct Answer
C. (17)वां / (17)th
Step 1
Concept
(a_n=105+(n-1)(-7)=112-7n). From \(a_n<0\), (n>16) so the first negative term is the (17)th.
Step 2
Why this answer is correct
The correct answer is C. (17)वां / (17)th. (a_n=105+(n-1)(-7)=112-7n). From \(a_n<0\), (n>16) so the first negative term is the (17)th.
Step 3
Exam Tip
(a_n=105+(n-1)(-7)=112-7n)। \(a_n<0\) से (n>16) इसलिए पहला ऋणात्मक पद (17)वां है।
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समान्तर श्रेणी \(26,35,44,\ldots\) का कौन-सा पद (206) है?
Which term of the AP \(26,35,44,\ldots\) is (206)?
#ap term-number nth-term class10
A (19)वां / (19)th
B (20)वां / (20)th
C (21)वां / (21)st
D (22)वां / (22)nd
Explanation opens after your attempt
Correct Answer
C. (21)वां / (21)st
Step 1
Concept
From (206=26+(n-1)9), (180=9(n-1)) so (n=21). Divide the difference between the term and first term by (d).
Step 2
Why this answer is correct
The correct answer is C. (21)वां / (21)st. From (206=26+(n-1)9), (180=9(n-1)) so (n=21). Divide the difference between the term and first term by (d).
Step 3
Exam Tip
(206=26+(n-1)9) से (180=9(n-1)) इसलिए (n=21)। पद और पहले पद का अंतर (d) से भाग दें।
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किसी समान्तर श्रेणी का (14)वां पद (92) और (d=7) है। \(a_1\) क्या होगा?
The (14)th term of an AP is (92) and (d=7). What is \(a_1\)?
#ap first-term known-term class10
A (1)
B (3)
C (5)
D (7)
Explanation opens after your attempt
Step 1
Concept
From \(92=a+13\times7\), (a=1). From the (14)th term to the first term (13d) is subtracted.
Step 2
Why this answer is correct
The correct answer is A. (1). From \(92=a+13\times7\), (a=1). From the (14)th term to the first term (13d) is subtracted.
Step 3
Exam Tip
\(92=a+13\times7\) से (a=1)। (14)वें पद से पहले पद तक (13d) घटता है।
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