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An AP has first term a = 63 and common difference d = −4. Which term is equal to −1?एक समान्तर श्रेणी का पहला पद a = 63 और सार्व अंतर d = −4 है। उसका कौन-सा पद −1 के बराबर है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 17वाँ पद17वाँ पद
Use aₙ = a + (n − 1)d: −1 = 63 − 4(n − 1). Thus −64 = −4(n − 1), so n − 1 = 16 and n = 17. Therefore, −1 is the 17th term.सूत्र aₙ = a + (n − 1)d का उपयोग करें: −1 = 63 − 4(n − 1)। इससे −64 = −4(n − 1), इसलिए n − 1 = 16 और n = 17। अतः −1, 17वाँ पद है।
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