The (n)th term of the AP (11,17,23,\ldots) is (a_n=6n+5). What is its (32)nd term?
Answer and explanation
Correct answer: 197
The given formula is \(a_n=6n+5\). Putting \(n=32\), \(a_{32}=6\times32+5=192+5=197\). Hence, 197 is correct. The value 191 would result from incorrectly using \(n=31\). Exam tip: Substitute the required term number directly for \(n\) in the formula.
Frequently asked questions
What is the correct answer to this question?
197
Why is this the correct answer?
The given formula is \(a_n=6n+5\). Putting \(n=32\), \(a_{32}=6\times32+5=192+5=197\). Hence, 197 is correct. The value 191 would result from incorrectly using \(n=31\). Exam tip: Substitute the required term number directly for \(n\) in the formula.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.
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