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The (n)th term of the AP (11,17,23,\ldots) is (a_n=6n+5). What is its (32)nd term?

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Answer and explanation

Correct answer: 197

The given formula is \(a_n=6n+5\). Putting \(n=32\), \(a_{32}=6\times32+5=192+5=197\). Hence, 197 is correct. The value 191 would result from incorrectly using \(n=31\). Exam tip: Substitute the required term number directly for \(n\) in the formula.

Related tags

Arithmetic ProgressionNth TermAp FormulaClass 10Sequence And Series

Frequently asked questions

What is the correct answer to this question?

197

Why is this the correct answer?

The given formula is \(a_n=6n+5\). Putting \(n=32\), \(a_{32}=6\times32+5=192+5=197\). Hence, 197 is correct. The value 191 would result from incorrectly using \(n=31\). Exam tip: Substitute the required term number directly for \(n\) in the formula.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.

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