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5 results found for "evaluate-prime-factorisation" in Class 10.
Question
Medium Mathematics
Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^6\times3^2\) है, तो वह संख्या क्या है?
If the prime factorisation of a number is \(2^6\times3^2\), what is the number?
#evaluate-prime-factorisation
#powers
#medium
A 288
B 576
C 1152
D 1728
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^6=64\) and \(3^2=9\).
Step 2
Why this answer is correct
\(64\times9=576\).
Step 3
Exam Tip
In a form with powers, it is easier to evaluate powers first. चरण 1: \(2^6=64\) और \(3^2=9\) निकालें। चरण 2: \(64\times9=576\)। चरण 3: घात वाले रूप में पहले घातों का मान निकालना आसान होता है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^5\times3^2\) है, तो वह संख्या क्या है?
If the prime factorisation of a number is \(2^5\times3^2\), what is the number?
#evaluate-prime-factorisation
#powers
#medium
A 144
B 288
C 576
D 864
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^5=32\) and \(3^2=9\).
Step 2
Why this answer is correct
\(32\times9=288\).
Step 3
Exam Tip
In prime factorisation with powers, evaluate powers first. चरण 1: \(2^5=32\) और \(3^2=9\) निकालें। चरण 2: \(32\times9=288\)। चरण 3: घात वाले अभाज्य गुणनखंडन में पहले घातों का मान निकालें।
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Question
Easy Mathematics
Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^6\times3\) है, तो वह संख्या क्या है?
If the prime factorisation of a number is \(2^6\times3\), what is the number?
#evaluate-prime-factorisation
#powers
#easy
A 96
B 128
C 192
D 256
Explanation opens after your attempt
Step 1
Concept
Find \(2^6=64\).
Step 2
Why this answer is correct
\(64\times3=192\), so the number is 192.
Step 3
Exam Tip
First evaluate the power, then multiply. चरण 1: \(2^6=64\) निकालें। चरण 2: \(64\times3=192\), इसलिए संख्या 192 है। चरण 3: पहले घात का मान निकालें और फिर गुणा करें।
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Question
Easy Mathematics
Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^5\times3\) है, तो वह संख्या क्या है?
If the prime factorisation of a number is \(2^5\times3\), what is the number?
#evaluate-prime-factorisation
#powers
#easy
A 64
B 96
C 128
D 192
Explanation opens after your attempt
Step 1
Concept
Find \(2^5=32\).
Step 2
Why this answer is correct
\(32\times3=96\), so the number is 96.
Step 3
Exam Tip
First evaluate the power, then multiply. चरण 1: \(2^5=32\) निकालें। चरण 2: \(32\times3=96\), इसलिए संख्या 96 है। चरण 3: पहले घात का मान निकालें और फिर गुणा करें।
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Question
Easy Mathematics
Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 4
संख्या \(3^2\times5\) का मान क्या है?
What is the value of \(3^2\times5\)?
#evaluate-prime-factorisation
#real-numbers
A 30
B 45
C 75
D 90
Explanation opens after your attempt
Step 1
Concept
First find \(3^2=9\).
Step 2
Why this answer is correct
\(9\times5=45\), so the number is 45.
Step 3
Exam Tip
In factorisation with powers, evaluate the power first. चरण 1: पहले \(3^2=9\) निकालें। चरण 2: \(9\times5=45\), इसलिए संख्या 45 है। चरण 3: घात वाले गुणनखंडन में पहले घात का मान निकालें।
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