Question 1/2
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^2\times3\times7\times11\) है?
Which number has prime factorisation \(2^2\times3\times7\times11\)?
#evaluate-factorisation
#number-924
#medium
A 924
B 462
C 1848
D 1386
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\).
Step 2
Why this answer is correct
\(4\times3\times7\times11=924\).
Step 3
Exam Tip
With many factors, multiply in pairs. चरण 1: \(2^2=4\) निकालें। चरण 2: \(4\times3\times7\times11=924\)। चरण 3: कई गुणनखंडों में जोड़े बनाकर गुणा करें।
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Question 2/2
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
संख्या 924 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 924?
#prime-factorisation
#number-924
#medium
A \(2^2\times3\times7\times11\)
B \(2\times3\times7\times22\)
C \(4\times231\)
D \(2^2\times21\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3\times7\times11\)
Step 1
Concept
Write \(924=4\times231\).
Step 2
Why this answer is correct
\(4=2^2\) and \(231=3\times7\times11\), so \(924=2^2\times3\times7\times11\).
Step 3
Exam Tip
Give 231 its complete prime form. चरण 1: \(924=4\times231\) लिखें। चरण 2: \(4=2^2\) और \(231=3\times7\times11\), इसलिए \(924=2^2\times3\times7\times11\)। चरण 3: 231 को पूरा अभाज्य रूप दें।
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