अभाज्य गुणनखंडन में घातों की तुलना करते समय सबसे पहले क्या देखना चाहिए?
What should be checked first while comparing powers in prime factorisation?
#prime-factorisation
#powers
#medium
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A एक ही अभाज्य आधार की घातें / Powers of the same prime base
B सभी संयुक्त गुणनखंडों का योग / Sum of all composite factors
C संख्या का अंतिम अंक ही / Only the last digit of the number
D गुणनखंडों का क्रम ही / Only the order of factors
Explanation opens after your attempt
Correct Answer
A. एक ही अभाज्य आधार की घातें / Powers of the same prime base
Step 1
Concept
अभाज्य गुणनखंडन में आधार पहले पहचानते हैं। / In prime factorisation, identify the bases first.
Step 2
Why this answer is correct
एक ही आधार की घातों की तुलना की जाती है, जैसे 2 की घात 2 से और 3 की घात 3 से। / Powers of the same base are compared, such as power of 2 with power of 2 and power of 3 with power of 3.
Step 3
Exam Tip
परीक्षा में आधार अलग हों तो घातों को सीधे न मिलाएं। / In exams, do not compare powers directly when bases are different.
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संख्या 1170 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 1170?
#prime-factorisation
#number-1170
#medium
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A \(2\times3^2\times5\times13\)
B \(2^2\times3\times5\times13\)
C \(117\times10\)
D \(9\times130\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3^2\times5\times13\)
Step 1
Concept
\(1170=117\times10\) लिखें। / Write \(1170=117\times10\).
Step 2
Why this answer is correct
\(117=3^2\times13\) और \(10=2\times5\), इसलिए \(1170=2\times3^2\times5\times13\)। / \(117=3^2\times13\) and \(10=2\times5\), so \(1170=2\times3^2\times5\times13\).
Step 3
Exam Tip
117 और 10 को अंतिम रूप में न रखें। / Do not keep 117 and 10 in the final form.
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संख्या 1215 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 1215?
#prime-factorisation
#number-1215
#medium
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A \(3^5\times5\)
B \(3^4\times5^2\)
C \(243\times5\)
D \(81\times15\)
Explanation opens after your attempt
Correct Answer
A. \(3^5\times5\)
Step 1
Concept
\(1215=243\times5\) लिखें। / Write \(1215=243\times5\).
Step 2
Why this answer is correct
\(243=3^5\), इसलिए \(1215=3^5\times5\)। / Since \(243=3^5\), \(1215=3^5\times5\).
Step 3
Exam Tip
243 संयुक्त है, इसलिए अंतिम अभाज्य रूप में 3 की घात लिखें। / 243 is composite, so write it as a power of 3 in final prime form.
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संख्या 1344 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 1344?
#prime-factorisation
#number-1344
#medium
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A \(2^6\times3\times7\)
B \(2^5\times3\times7\)
C \(64\times21\)
D \(2^6\times21\)
Explanation opens after your attempt
Correct Answer
A. \(2^6\times3\times7\)
Step 1
Concept
\(1344=64\times21\) लिखें। / Write \(1344=64\times21\).
Step 2
Why this answer is correct
\(64=2^6\) और \(21=3\times7\), इसलिए \(1344=2^6\times3\times7\)। / \(64=2^6\) and \(21=3\times7\), so \(1344=2^6\times3\times7\).
Step 3
Exam Tip
21 संयुक्त है, इसलिए उसे 3 और 7 में तोड़ें। / Since 21 is composite, split it into 3 and 7.
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संख्या 1485 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 1485?
#prime-factorisation
#number-1485
#medium
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A \(3^3\times5\times11\)
B \(3^2\times5\times11\)
C \(135\times11\)
D \(27\times55\)
Explanation opens after your attempt
Correct Answer
A. \(3^3\times5\times11\)
Step 1
Concept
\(1485=135\times11\) लिखें। / Write \(1485=135\times11\).
Step 2
Why this answer is correct
\(135=3^3\times5\), इसलिए \(1485=3^3\times5\times11\)। / \(135=3^3\times5\), so \(1485=3^3\times5\times11\).
Step 3
Exam Tip
135 को पूरा अभाज्य रूप दें। / Give 135 its complete prime form.
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संख्या 1620 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 1620?
#prime-factorisation
#number-1620
#medium
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A \(2^2\times3^4\times5\)
B \(2\times3^4\times5\)
C \(162\times10\)
D \(4\times405\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^4\times5\)
Step 1
Concept
\(1620=162\times10\) लिखें। / Write \(1620=162\times10\).
Step 2
Why this answer is correct
\(162=2\times3^4\) और \(10=2\times5\), इसलिए \(1620=2^2\times3^4\times5\)। / \(162=2\times3^4\) and \(10=2\times5\), so \(1620=2^2\times3^4\times5\).
Step 3
Exam Tip
2 की कुल घात सही गिनें। / Count the total power of 2 correctly.
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संख्या 1848 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 1848?
#prime-factorisation
#number-1848
#medium
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A \(2^3\times3\times7\times11\)
B \(2^2\times3\times7\times11\)
C \(8\times231\)
D \(2^3\times21\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3\times7\times11\)
Step 1
Concept
\(1848=8\times231\) लिखें। / Write \(1848=8\times231\).
Step 2
Why this answer is correct
\(8=2^3\) और \(231=3\times7\times11\), इसलिए \(1848=2^3\times3\times7\times11\)। / \(8=2^3\) and \(231=3\times7\times11\), so \(1848=2^3\times3\times7\times11\).
Step 3
Exam Tip
231 को पूरा अभाज्य रूप दें। / Give 231 its complete prime form.
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संख्या 1875 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 1875?
#prime-factorisation
#number-1875
#medium
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A \(3\times5^4\)
B \(3^2\times5^3\)
C \(75\times25\)
D \(3\times625\)
Explanation opens after your attempt
Correct Answer
A. \(3\times5^4\)
Step 1
Concept
\(1875=3\times625\) लिखें। / Write \(1875=3\times625\).
Step 2
Why this answer is correct
\(625=5^4\), इसलिए \(1875=3\times5^4\)। / Since \(625=5^4\), \(1875=3\times5^4\).
Step 3
Exam Tip
625 को अंतिम रूप में न छोड़कर \(5^4\) लिखें। / Do not leave 625 in the final form; write \(5^4\).
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संख्या 2016 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 2016?
#prime-factorisation
#number-2016
#medium
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A \(2^5\times3^2\times7\)
B \(2^4\times3^2\times7\)
C \(32\times63\)
D \(2^5\times9\times7\)
Explanation opens after your attempt
Correct Answer
A. \(2^5\times3^2\times7\)
Step 1
Concept
\(2016=32\times63\) लिखें। / Write \(2016=32\times63\).
Step 2
Why this answer is correct
\(32=2^5\) और \(63=3^2\times7\), इसलिए \(2016=2^5\times3^2\times7\)। / \(32=2^5\) and \(63=3^2\times7\), so \(2016=2^5\times3^2\times7\).
Step 3
Exam Tip
63 को अभाज्य घातों में बदलें। / Convert 63 into prime powers.
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संख्या 2205 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 2205?
#prime-factorisation
#number-2205
#medium
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A \(3^2\times5\times7^2\)
B \(3\times5\times7^2\)
C \(45\times49\)
D \(9\times245\)
Explanation opens after your attempt
Correct Answer
A. \(3^2\times5\times7^2\)
Step 1
Concept
\(2205=45\times49\) लिखें। / Write \(2205=45\times49\).
Step 2
Why this answer is correct
\(45=3^2\times5\) और \(49=7^2\), इसलिए \(2205=3^2\times5\times7^2\)। / \(45=3^2\times5\) and \(49=7^2\), so \(2205=3^2\times5\times7^2\).
Step 3
Exam Tip
45 और 49 को पूरा अभाज्य रूप दें। / Give complete prime form to 45 and 49.
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संख्या 2268 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 2268?
#prime-factorisation
#number-2268
#medium
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A \(2^2\times3^4\times7\)
B \(2^3\times3^3\times7\)
C \(4\times567\)
D \(2^2\times81\times7\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^4\times7\)
Step 1
Concept
\(2268=4\times567\) लिखें। / Write \(2268=4\times567\).
Step 2
Why this answer is correct
\(4=2^2\) और \(567=3^4\times7\), इसलिए \(2268=2^2\times3^4\times7\)। / \(4=2^2\) and \(567=3^4\times7\), so \(2268=2^2\times3^4\times7\).
Step 3
Exam Tip
567 को पूरा अभाज्य रूप में बदलें। / Convert 567 into complete prime form.
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संख्या 2340 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 2340?
#prime-factorisation
#number-2340
#medium
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A \(2^2\times3^2\times5\times13\)
B \(2\times3^2\times5\times13\)
C \(234\times10\)
D \(4\times585\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^2\times5\times13\)
Step 1
Concept
\(2340=234\times10\) लिखें। / Write \(2340=234\times10\).
Step 2
Why this answer is correct
\(234=2\times3^2\times13\) और \(10=2\times5\), इसलिए \(2340=2^2\times3^2\times5\times13\)। / \(234=2\times3^2\times13\) and \(10=2\times5\), so \(2340=2^2\times3^2\times5\times13\).
Step 3
Exam Tip
2 की घात 2 बनती है। / The power of 2 becomes 2.
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संख्या 2450 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 2450?
#prime-factorisation
#number-2450
#medium
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A \(2\times5^2\times7^2\)
B \(2^2\times5\times7^2\)
C \(2\times1225\)
D \(50\times49\)
Explanation opens after your attempt
Correct Answer
A. \(2\times5^2\times7^2\)
Step 1
Concept
\(2450=2\times1225\) लिखें। / Write \(2450=2\times1225\).
Step 2
Why this answer is correct
\(1225=5^2\times7^2\), इसलिए \(2450=2\times5^2\times7^2\)। / \(1225=5^2\times7^2\), so \(2450=2\times5^2\times7^2\).
Step 3
Exam Tip
1225 को अभाज्य घातों में बदलें। / Convert 1225 into prime powers.
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संख्या 2640 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 2640?
#prime-factorisation
#number-2640
#medium
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A \(2^4\times3\times5\times11\)
B \(2^3\times3\times5\times11\)
C \(24\times110\)
D \(16\times165\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times3\times5\times11\)
Step 1
Concept
\(2640=16\times165\) लिखें। / Write \(2640=16\times165\).
Step 2
Why this answer is correct
\(16=2^4\) और \(165=3\times5\times11\), इसलिए \(2640=2^4\times3\times5\times11\)। / \(16=2^4\) and \(165=3\times5\times11\), so \(2640=2^4\times3\times5\times11\).
Step 3
Exam Tip
165 को आगे तोड़ें। / Break 165 further.
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संख्या 2835 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 2835?
#prime-factorisation
#number-2835
#medium
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A \(3^4\times5\times7\)
B \(3^3\times5\times7\)
C \(81\times35\)
D \(9\times315\)
Explanation opens after your attempt
Correct Answer
A. \(3^4\times5\times7\)
Step 1
Concept
\(2835=81\times35\) लिखें। / Write \(2835=81\times35\).
Step 2
Why this answer is correct
\(81=3^4\) और \(35=5\times7\), इसलिए \(2835=3^4\times5\times7\)। / \(81=3^4\) and \(35=5\times7\), so \(2835=3^4\times5\times7\).
Step 3
Exam Tip
81 को \(3^4\) में बदलें। / Change 81 into \(3^4\).
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संख्या 3120 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 3120?
#prime-factorisation
#number-3120
#medium
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A \(2^4\times3\times5\times13\)
B \(2^3\times3\times5\times13\)
C \(312\times10\)
D \(16\times195\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times3\times5\times13\)
Step 1
Concept
\(3120=16\times195\) लिखें। / Write \(3120=16\times195\).
Step 2
Why this answer is correct
\(16=2^4\) और \(195=3\times5\times13\), इसलिए \(3120=2^4\times3\times5\times13\)। / \(16=2^4\) and \(195=3\times5\times13\), so \(3120=2^4\times3\times5\times13\).
Step 3
Exam Tip
195 को पूरा अभाज्य रूप दें। / Give 195 its complete prime form.
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संख्या 3402 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 3402?
#prime-factorisation
#number-3402
#medium
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A \(2\times3^5\times7\)
B \(2\times3^4\times7\)
C \(2\times1701\)
D \(486\times7\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3^5\times7\)
Step 1
Concept
\(3402=2\times1701\) लिखें। / Write \(3402=2\times1701\).
Step 2
Why this answer is correct
\(1701=3^5\times7\), इसलिए \(3402=2\times3^5\times7\)। / \(1701=3^5\times7\), so \(3402=2\times3^5\times7\).
Step 3
Exam Tip
1701 को 3 और 7 के अभाज्य रूप में बदलें। / Convert 1701 into prime form using 3 and 7.
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संख्या 3528 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 3528?
#prime-factorisation
#number-3528
#medium
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A \(2^3\times3^2\times7^2\)
B \(2^2\times3^2\times7^2\)
C \(72\times49\)
D \(8\times441\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3^2\times7^2\)
Step 1
Concept
\(3528=72\times49\) लिखें। / Write \(3528=72\times49\).
Step 2
Why this answer is correct
\(72=2^3\times3^2\) और \(49=7^2\), इसलिए \(3528=2^3\times3^2\times7^2\)। / \(72=2^3\times3^2\) and \(49=7^2\), so \(3528=2^3\times3^2\times7^2\).
Step 3
Exam Tip
72 और 49 को अभाज्य घातों में बदलें। / Convert 72 and 49 into prime powers.
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संख्या 3645 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 3645?
#prime-factorisation
#number-3645
#medium
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? Hint Small clue
A \(3^6\times5\)
B \(3^5\times5\)
C \(729\times5\)
D \(81\times45\)
Explanation opens after your attempt
Correct Answer
A. \(3^6\times5\)
Step 1
Concept
\(3645=729\times5\) लिखें। / Write \(3645=729\times5\).
Step 2
Why this answer is correct
\(729=3^6\), इसलिए \(3645=3^6\times5\)। / Since \(729=3^6\), \(3645=3^6\times5\).
Step 3
Exam Tip
729 को अंतिम रूप में नहीं छोड़ना चाहिए। / 729 should not be left in the final form.
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संख्या 3888 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 3888?
#prime-factorisation
#number-3888
#medium
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? Hint Small clue
A \(2^4\times3^5\)
B \(2^3\times3^5\)
C \(16\times243\)
D \(2^4\times243\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times3^5\)
Step 1
Concept
\(3888=16\times243\) लिखें। / Write \(3888=16\times243\).
Step 2
Why this answer is correct
\(16=2^4\) और \(243=3^5\), इसलिए \(3888=2^4\times3^5\)। / \(16=2^4\) and \(243=3^5\), so \(3888=2^4\times3^5\).
Step 3
Exam Tip
243 को 3 की घात में बदलें। / Change 243 into a power of 3.
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संख्या 3969 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 3969?
#prime-factorisation
#number-3969
#medium
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? Hint Small clue
A \(3^4\times7^2\)
B \(3^3\times7^2\)
C \(81\times49\)
D \(63\times63\)
Explanation opens after your attempt
Correct Answer
A. \(3^4\times7^2\)
Step 1
Concept
\(3969=81\times49\) लिखें। / Write \(3969=81\times49\).
Step 2
Why this answer is correct
\(81=3^4\) और \(49=7^2\), इसलिए \(3969=3^4\times7^2\)। / \(81=3^4\) and \(49=7^2\), so \(3969=3^4\times7^2\).
Step 3
Exam Tip
दोनों भागों को अभाज्य घातों में लिखें। / Write both parts as prime powers.
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यदि \(2016=2^a\times3^2\times7\), तो (a) का मान क्या है?
If \(2016=2^a\times3^2\times7\), what is the value of (a)?
#exponent-comparison
#number-2016
#medium
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A 5
B 4
C 6
D 3
Explanation opens after your attempt
Step 1
Concept
\(2016=32\times63\) लिखें। / Write \(2016=32\times63\).
Step 2
Why this answer is correct
\(32=2^5\) और \(63=3^2\times7\), इसलिए \(2016=2^5\times3^2\times7\)। / \(32=2^5\) and \(63=3^2\times7\), so \(2016=2^5\times3^2\times7\).
Step 3
Exam Tip
तुलना करने पर (a=5) है। / Comparing gives (a=5).
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यदि \(2205=3^b\times5\times7^2\), तो (b) का मान क्या है?
If \(2205=3^b\times5\times7^2\), what is the value of (b)?
#exponent-comparison
#number-2205
#medium
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A 2
B 1
C 3
D 4
Explanation opens after your attempt
Step 1
Concept
\(2205=45\times49\) है। / \(2205=45\times49\).
Step 2
Why this answer is correct
\(45=3^2\times5\) और \(49=7^2\), इसलिए \(2205=3^2\times5\times7^2\)। / \(45=3^2\times5\) and \(49=7^2\), so \(2205=3^2\times5\times7^2\).
Step 3
Exam Tip
तुलना करने पर (b=2) है। / Comparing gives (b=2).
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यदि \(2450=2\times5^m\times7^2\), तो (m) का मान क्या है?
If \(2450=2\times5^m\times7^2\), what is the value of (m)?
#exponent-comparison
#number-2450
#medium
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A 2
B 1
C 3
D 4
Explanation opens after your attempt
Step 1
Concept
\(2450=2\times1225\) है। / \(2450=2\times1225\).
Step 2
Why this answer is correct
\(1225=5^2\times7^2\), इसलिए \(2450=2\times5^2\times7^2\)। / \(1225=5^2\times7^2\), so \(2450=2\times5^2\times7^2\).
Step 3
Exam Tip
दिए गए रूप से तुलना करने पर (m=2) होगा। / Comparing with the given form gives (m=2).
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यदि \(3888=2^p\times3^5\), तो (p) का मान क्या है?
If \(3888=2^p\times3^5\), what is the value of (p)?
#exponent-comparison
#number-3888
#medium
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A 4
B 3
C 5
D 6
Explanation opens after your attempt
Step 1
Concept
\(3888=16\times243\) लिखें। / Write \(3888=16\times243\).
Step 2
Why this answer is correct
\(16=2^4\) और \(243=3^5\), इसलिए 2 की घात 4 है। / \(16=2^4\) and \(243=3^5\), so the power of 2 is 4.
Step 3
Exam Tip
तुलना करने पर (p=4) मिलेगा। / Comparing gives (p=4).
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किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times11\) है?
Which number has prime factorisation \(2^3\times3^2\times11\)?
#evaluate-factorisation
#number-792
#medium
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A 792
B 396
C 1188
D 1584
Explanation opens after your attempt
Step 1
Concept
\(2^3=8\) और \(3^2=9\) निकालें। / Calculate \(2^3=8\) and \(3^2=9\).
Step 2
Why this answer is correct
\(8\times9\times11=792\)। / \(8\times9\times11=792\).
Step 3
Exam Tip
पहले घातों को हल करें, फिर 11 से गुणा करें। / First solve the powers, then multiply by 11.
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किस संख्या का अभाज्य गुणनखंडन \(3\times5^2\times11\) है?
Which number has prime factorisation \(3\times5^2\times11\)?
#evaluate-factorisation
#number-825
#medium
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A 825
B 550
C 1650
D 275
Explanation opens after your attempt
Step 1
Concept
\(5^2=25\) निकालें। / Calculate \(5^2=25\).
Step 2
Why this answer is correct
\(3\times25\times11=825\)। / \(3\times25\times11=825\).
Step 3
Exam Tip
घात वाले भाग को पहले सरल करना उपयोगी है। / It is useful to simplify the power part first.
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किस संख्या का अभाज्य गुणनखंडन \(2^5\times3^3\) है?
Which number has prime factorisation \(2^5\times3^3\)?
#evaluate-factorisation
#number-864
#medium
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A 864
B 432
C 1728
D 1296
Explanation opens after your attempt
Step 1
Concept
\(2^5=32\) और \(3^3=27\) निकालें। / Calculate \(2^5=32\) and \(3^3=27\).
Step 2
Why this answer is correct
\(32\times27=864\)। / \(32\times27=864\).
Step 3
Exam Tip
दोनों घातों को अलग-अलग सरल करें। / Simplify both powers separately.
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किस संख्या का अभाज्य गुणनखंडन \(2^2\times3\times7\times11\) है?
Which number has prime factorisation \(2^2\times3\times7\times11\)?
#evaluate-factorisation
#number-924
#medium
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A 924
B 462
C 1848
D 1386
Explanation opens after your attempt
Step 1
Concept
\(2^2=4\) निकालें। / Calculate \(2^2=4\).
Step 2
Why this answer is correct
\(4\times3\times7\times11=924\)। / \(4\times3\times7\times11=924\).
Step 3
Exam Tip
कई गुणनखंडों में जोड़े बनाकर गुणा करें। / With many factors, multiply in pairs.
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किस संख्या का अभाज्य गुणनखंडन \(2^4\times3\times5\times13\) है?
Which number has prime factorisation \(2^4\times3\times5\times13\)?
#evaluate-factorisation
#number-3120
#medium
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A 3120
B 1560
C 6240
D 2340
Explanation opens after your attempt
Step 1
Concept
\(2^4=16\) निकालें। / Calculate \(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times5\times13=3120\)। / \(16\times3\times5\times13=3120\).
Step 3
Exam Tip
पहले \(3\times5\times13\) को 195 समझकर गुणा करना आसान है। / It is easy to first treat \(3\times5\times13\) as 195 and multiply.
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यदि \(n=2^4\times3\times5\times11\), तो (n) का मान क्या है?
If \(n=2^4\times3\times5\times11\), what is the value of (n)?
#evaluate-factorisation
#powers
#medium
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A 2640
B 1320
C 5280
D 1980
Explanation opens after your attempt
Step 1
Concept
\(2^4=16\) है। / \(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times5\times11=2640\)। / \(16\times3\times5\times11=2640\).
Step 3
Exam Tip
अभाज्य रूप से संख्या पाने के लिए सभी गुणनखंडों को गुणा करें। / Multiply all factors to get the number from prime form.
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यदि \(m=3^4\times5\times7\), तो (m) का मान क्या है?
If \(m=3^4\times5\times7\), what is the value of (m)?
#evaluate-factorisation
#powers
#medium
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A 2835
B 945
C 5670
D 2025
Explanation opens after your attempt
Step 1
Concept
\(3^4=81\) है। / \(3^4=81\).
Step 2
Why this answer is correct
\(81\times5\times7=2835\)। / \(81\times5\times7=2835\).
Step 3
Exam Tip
घात को पहले सरल करने से गणना साफ रहती है। / Simplifying the power first keeps the calculation clear.
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किस विकल्प में केवल अभाज्य गुणनखंडों का अंतिम रूप दिया गया है?
Which option gives the final form using only prime factors?
#prime-factors
#concept-check
#medium
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A \(2^2\times3^4\times7\)
B \(4\times81\times7\)
C \(2^2\times567\)
D \(12\times189\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^4\times7\)
Step 1
Concept
अंतिम अभाज्य रूप में आधार अभाज्य होने चाहिए। / In final prime form, bases should be prime.
Step 2
Why this answer is correct
पहले विकल्प में 2, 3 और 7 अभाज्य आधार हैं। / In the first option, 2, 3, and 7 are prime bases.
Step 3
Exam Tip
4, 81, 567, 12 और 189 संयुक्त हैं, इसलिए वे अंतिम रूप नहीं हैं। / 4, 81, 567, 12, and 189 are composite, so they are not final forms.
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किस विकल्प में अंतिम अभाज्य गुणनखंडन नहीं दिया गया है?
Which option is not a final prime factorisation?
#prime-factorisation
#not-final-form
#medium
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A \(2^4\times195\)
B \(2^4\times3\times5\times13\)
C \(3^4\times5\times7\)
D \(2\times5^2\times7^2\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times195\)
Step 1
Concept
अंतिम अभाज्य गुणनखंडन में संयुक्त गुणनखंड नहीं होना चाहिए। / Final prime factorisation must not contain a composite factor.
Step 2
Why this answer is correct
195 संयुक्त है और \(195=3\times5\times13\)। / 195 is composite and \(195=3\times5\times13\).
Step 3
Exam Tip
इसलिए \(2^4\times195\) अंतिम रूप नहीं है। / Therefore, \(2^4\times195\) is not final form.
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संख्या 7776 का अभाज्य गुणनखंडन क्या है?
What is the prime factorisation of 7776?
#prime-factorisation
#number-7776
#medium
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A \(2^5\times3^5\)
B \(2^4\times3^5\)
C \(32\times243\)
D \(6^5\)
Explanation opens after your attempt
Correct Answer
A. \(2^5\times3^5\)
Step 1
Concept
\(7776=32\times243\) लिखें। / Write \(7776=32\times243\).
Step 2
Why this answer is correct
\(32=2^5\) और \(243=3^5\), इसलिए \(7776=2^5\times3^5\)। / \(32=2^5\) and \(243=3^5\), so \(7776=2^5\times3^5\).
Step 3
Exam Tip
32 और 243 संयुक्त हैं, इसलिए अंतिम रूप में अभाज्य आधार लिखें। / 32 and 243 are composite, so write prime bases in the final form.
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संख्या 10000 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 10000?
#prime-factorisation
#number-10000
#medium
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A \(2^4\times5^4\)
B \(2^5\times5^3\)
C \(10^4\)
D \(100\times100\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times5^4\)
Step 1
Concept
\(10000=10^4\) लिखा जा सकता है। / (10000) can be written as \(10^4\).
Step 2
Why this answer is correct
\(10=2\times5\), इसलिए \(10^4=2^4\times5^4\)। / Since \(10=2\times5\), \(10^4=2^4\times5^4\).
Step 3
Exam Tip
10 संयुक्त है, इसलिए अंतिम रूप में 2 और 5 की घातें लिखें। / 10 is composite, so write powers of 2 and 5 in the final form.
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संख्या 4913 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 4913?
#prime-factorisation
#cube-number
#medium
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A \(17^3\)
B \(17^2\)
C \(289\times17\)
D \(4913\times1\)
Explanation opens after your attempt
Correct Answer
A. \(17^3\)
Step 1
Concept
\(4913=17\times289\) लिखें। / Write \(4913=17\times289\).
Step 2
Why this answer is correct
\(289=17^2\), इसलिए \(4913=17^3\)। / \(289=17^2\), so \(4913=17^3\).
Step 3
Exam Tip
289 संयुक्त है, इसलिए अंतिम रूप में \(17^3\) लिखें। / Since 289 is composite, write \(17^3\) in the final form.
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संख्या 12500 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 12500?
#prime-factorisation
#number-12500
#medium
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A \(2^2\times5^5\)
B \(2\times5^5\)
C \(125\times100\)
D \(4\times3125\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times5^5\)
Step 1
Concept
\(12500=125\times100\) लिखें। / Write \(12500=125\times100\).
Step 2
Why this answer is correct
\(125=5^3\) और \(100=2^2\times5^2\), इसलिए \(12500=2^2\times5^5\)। / \(125=5^3\) and \(100=2^2\times5^2\), so \(12500=2^2\times5^5\).
Step 3
Exam Tip
5 की कुल घात 5 गिनें। / Count the total power of 5 as 5.
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संख्या 10206 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 10206?
#prime-factorisation
#number-10206
#medium
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A \(2\times3^6\times7\)
B \(2\times3^5\times7\)
C \(2\times5103\)
D \(1458\times7\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3^6\times7\)
Step 1
Concept
\(10206=2\times5103\) लिखें। / Write \(10206=2\times5103\).
Step 2
Why this answer is correct
\(5103=3^6\times7\), इसलिए \(10206=2\times3^6\times7\)। / \(5103=3^6\times7\), so \(10206=2\times3^6\times7\).
Step 3
Exam Tip
5103 को अभाज्य घातों में बदलें। / Convert 5103 into prime powers.
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संख्या 13720 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 13720?
#prime-factorisation
#number-13720
#medium
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A \(2^3\times5\times7^3\)
B \(2^4\times5\times7^2\)
C \(40\times343\)
D \(8\times1715\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times5\times7^3\)
Step 1
Concept
\(13720=40\times343\) लिखें। / Write \(13720=40\times343\).
Step 2
Why this answer is correct
\(40=2^3\times5\) और \(343=7^3\), इसलिए \(13720=2^3\times5\times7^3\)। / \(40=2^3\times5\) and \(343=7^3\), so \(13720=2^3\times5\times7^3\).
Step 3
Exam Tip
40 और 343 को अभाज्य रूप में लिखें। / Write 40 and 343 in prime form.
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यदि \(2^5\times3^2\times7\) से संख्या बनाई जाए, तो वह कौन सी होगी?
If a number is formed from \(2^5\times3^2\times7\), which number will it be?
#evaluate-factorisation
#mcq-pattern
#medium
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? Hint Small clue
A 2016
B 1008
C 4032
D 1344
Explanation opens after your attempt
Step 1
Concept
\(2^5=32\) और \(3^2=9\) निकालें। / Calculate \(2^5=32\) and \(3^2=9\).
Step 2
Why this answer is correct
\(32\times9\times7=2016\)। / \(32\times9\times7=2016\).
Step 3
Exam Tip
घातों को पहले हल करने से उत्तर जल्दी मिलता है। / Solving powers first gives the answer quickly.
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यदि किसी संख्या का अभाज्य गुणनखंडन \(3^2\times5\times7^2\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(3^2\times5\times7^2\), which number is it?
#evaluate-factorisation
#number-2205
#medium
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? Hint Small clue
A 2205
B 735
C 4410
D 1470
Explanation opens after your attempt
Step 1
Concept
\(3^2=9\) और \(7^2=49\) निकालें। / Calculate \(3^2=9\) and \(7^2=49\).
Step 2
Why this answer is correct
\(9\times5\times49=2205\)। / \(9\times5\times49=2205\).
Step 3
Exam Tip
दो घातों को पहले सरल करके गुणा करें। / Simplify the two powers first and multiply.
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यदि किसी संख्या का अभाज्य गुणनखंडन \(2^2\times3^4\times7\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^2\times3^4\times7\), which number is it?
#evaluate-factorisation
#number-2268
#medium
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? Hint Small clue
A 2268
B 1134
C 4536
D 3402
Explanation opens after your attempt
Step 1
Concept
\(2^2=4\) और \(3^4=81\) निकालें। / Calculate \(2^2=4\) and \(3^4=81\).
Step 2
Why this answer is correct
\(4\times81\times7=2268\)। / \(4\times81\times7=2268\).
Step 3
Exam Tip
बड़ी घात को पहले सरल करना सही तरीका है। / Simplifying the higher power first is the right method.
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यदि \(2^4\times3\times5\times11\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^4\times3\times5\times11\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#number-2640
#medium
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? Hint Small clue
A 2640
B 1320
C 5280
D 3960
Explanation opens after your attempt
Step 1
Concept
\(2^4=16\) निकालें। / Calculate \(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times5\times11=2640\)। / \(16\times3\times5\times11=2640\).
Step 3
Exam Tip
गुणन को छोटे चरणों में करें ताकि गलती न हो। / Do multiplication in small steps to avoid mistakes.
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संख्या 4752 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 4752?
#prime-factorisation
#number-4752
#medium
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? Hint Small clue
A \(2^4\times3^3\times11\)
B \(2^3\times3^3\times11\)
C \(16\times297\)
D \(2^4\times27\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times3^3\times11\)
Step 1
Concept
\(4752=16\times297\) लिखें। / Write \(4752=16\times297\).
Step 2
Why this answer is correct
\(16=2^4\) और \(297=3^3\times11\), इसलिए \(4752=2^4\times3^3\times11\)। / \(16=2^4\) and \(297=3^3\times11\), so \(4752=2^4\times3^3\times11\).
Step 3
Exam Tip
297 को पूरा अभाज्य रूप दें। / Give 297 its complete prime form.
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संख्या 5850 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 5850?
#prime-factorisation
#number-5850
#medium
50 50-50 2 wrong hide
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? Hint Small clue
A \(2\times3^2\times5^2\times13\)
B \(2^2\times3\times5^2\times13\)
C \(58.5\times100\)
D \(18\times325\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3^2\times5^2\times13\)
Step 1
Concept
\(5850=18\times325\) लिखें। / Write \(5850=18\times325\).
Step 2
Why this answer is correct
\(18=2\times3^2\) और \(325=5^2\times13\), इसलिए \(5850=2\times3^2\times5^2\times13\)। / \(18=2\times3^2\) and \(325=5^2\times13\), so \(5850=2\times3^2\times5^2\times13\).
Step 3
Exam Tip
दशमलव रूप से बचें और पूर्ण गुणनखंडों का उपयोग करें। / Avoid decimal forms and use whole factors.
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संख्या 7560 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 7560?
#prime-factorisation
#number-7560
#medium
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? Hint Small clue
A \(2^3\times3^3\times5\times7\)
B \(2^2\times3^3\times5\times7\)
C \(756\times10\)
D \(8\times945\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3^3\times5\times7\)
Step 1
Concept
\(7560=756\times10\) लिखें। / Write \(7560=756\times10\).
Step 2
Why this answer is correct
\(756=2^2\times3^3\times7\) और \(10=2\times5\), इसलिए \(7560=2^3\times3^3\times5\times7\)। / \(756=2^2\times3^3\times7\) and \(10=2\times5\), so \(7560=2^3\times3^3\times5\times7\).
Step 3
Exam Tip
2 की कुल घात 3 गिनें। / Count the total power of 2 as 3.
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किस संख्या का अभाज्य गुणनखंडन \(2\times3^2\times5^2\times13\) है?
Which number has prime factorisation \(2\times3^2\times5^2\times13\)?
#evaluate-factorisation
#number-5850
#medium
50 50-50 2 wrong hide
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? Hint Small clue
A 5850
B 2925
C 11700
D 3900
Explanation opens after your attempt
Step 1
Concept
\(3^2=9\) और \(5^2=25\) निकालें। / Calculate \(3^2=9\) and \(5^2=25\).
Step 2
Why this answer is correct
\(2\times9\times25\times13=5850\)। / \(2\times9\times25\times13=5850\).
Step 3
Exam Tip
पहले \(9\times25=225\) करें, फिर बाकी गुणा करें। / First do \(9\times25=225\), then multiply the rest.
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संख्या 16384 का अभाज्य गुणनखंडन क्या है?
What is the prime factorisation of 16384?
#prime-factorisation
#power-of-two
#medium
50 50-50 2 wrong hide
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? Hint Small clue
A \(2^{14}\)
B \(2^{13}\)
C \(128^2\)
D \(16^4\)
Explanation opens after your attempt
Correct Answer
A. \(2^{14}\)
Step 1
Concept
16384 को बार-बार 2 से भाग दें। / Divide 16384 repeatedly by 2.
Step 2
Why this answer is correct
चौदह बार 2 मिलने से \(16384=2^{14}\)। / Fourteen factors of 2 give \(16384=2^{14}\).
Step 3
Exam Tip
128 और 16 संयुक्त हैं, इसलिए अंतिम अभाज्य रूप में 2 की घात लिखें। / 128 and 16 are composite, so write the power of 2 in final prime form.
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अभाज्य गुणनखंडन में \(25^2\times7\) को अंतिम रूप क्यों नहीं माना जाता?
Why is \(25^2\times7\) not considered a final form in prime factorisation?
#prime-factorisation
#concept-check
#medium
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? Hint Small clue
A क्योंकि 25 संयुक्त संख्या है / Because 25 is composite
B क्योंकि 7 अभाज्य नहीं है / Because 7 is not prime
C क्योंकि घात लिखना गलत है / Because writing powers is wrong
D क्योंकि गुणा का उपयोग नहीं किया जा सकता / Because multiplication cannot be used
Explanation opens after your attempt
Correct Answer
A. क्योंकि 25 संयुक्त संख्या है / Because 25 is composite
Step 1
Concept
अंतिम अभाज्य गुणनखंडन में आधार अभाज्य होना चाहिए। / In final prime factorisation, the base must be prime.
Step 2
Why this answer is correct
25 संयुक्त है और \(25=5^2\) होता है। / 25 is composite and \(25=5^2\).
Step 3
Exam Tip
इसलिए \(25^2\times7\) को \(5^4\times7\) में बदलना होगा। / Therefore, \(25^2\times7\) must be changed into \(5^4\times7\).
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