Question 1/2
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^5\times3^3\) है?
Which number has prime factorisation \(2^5\times3^3\)?
#evaluate-factorisation
#number-864
#medium
A 864
B 432
C 1728
D 1296
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^5=32\) and \(3^3=27\).
Step 2
Why this answer is correct
\(32\times27=864\).
Step 3
Exam Tip
Simplify both powers separately. चरण 1: \(2^5=32\) और \(3^3=27\) निकालें। चरण 2: \(32\times27=864\)। चरण 3: दोनों घातों को अलग-अलग सरल करें।
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Question 2/2
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
संख्या 864 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 864?
#prime-factorisation
#number-864
#medium
A \(2^5\times3^3\)
B \(2^4\times3^3\)
C \(32\times27\)
D \(2^5\times27\)
Explanation opens after your attempt
Correct Answer
A. \(2^5\times3^3\)
Step 1
Concept
Write \(864=32\times27\).
Step 2
Why this answer is correct
\(32=2^5\) and \(27=3^3\), so \(864=2^5\times3^3\).
Step 3
Exam Tip
It is necessary to convert 32 and 27 into prime powers. चरण 1: \(864=32\times27\) लिखें। चरण 2: \(32=2^5\) और \(27=3^3\), इसलिए \(864=2^5\times3^3\)। चरण 3: 32 और 27 को अभाज्य घातों में बदलना जरूरी है।
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