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number-1980 MCQ Questions for Class 10

number-1980 se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

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3 questions tagged with number-1980.

Question 1/3 Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

किस संख्या का अभाज्य गुणनखंडन \(2^2\times3^2\times5\times11\) है?

Which number has prime factorisation \(2^2\times3^2\times5\times11\)?

Explanation opens after your attempt
Correct Answer

A. 1980

Step 1

Concept

Calculate \(2^2=4\) and \(3^2=9\).

Step 2

Why this answer is correct

\(4\times9\times5\times11=1980\).

Step 3

Exam Tip

Simplifying powers first gives the answer quickly. चरण 1: \(2^2=4\) और \(3^2=9\) निकालें। चरण 2: \(4\times9\times5\times11=1980\)। चरण 3: घातों को पहले सरल करने से उत्तर जल्दी मिलता है।

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Question 2/3 Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

संख्या 1980 का अभाज्य गुणनखंडन कौन सा है?

Which is the prime factorisation of 1980?

Explanation opens after your attempt
Correct Answer

A. \(2^2\times3^2\times5\times11\)

Step 1

Concept

Write \(1980=198\times10\).

Step 2

Why this answer is correct

\(198=2\times3^2\times11\) and \(10=2\times5\), so \(1980=2^2\times3^2\times5\times11\).

Step 3

Exam Tip

Since 2 appears twice, write \(2^2\). चरण 1: \(1980=198\times10\) लिखें। चरण 2: \(198=2\times3^2\times11\) और \(10=2\times5\), इसलिए \(1980=2^2\times3^2\times5\times11\)। चरण 3: 2 दो बार आता है, इसलिए \(2^2\) लिखें।

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Question 3/3 Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

संख्या 1980 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 1980?

Explanation opens after your attempt
Correct Answer

A. \(2^2\times3^2\times5\times11\)

Step 1

Concept

Write \(1980=198\times10\).

Step 2

Why this answer is correct

\(198=2\times3^2\times11\) and \(10=2\times5\), so \(1980=2^2\times3^2\times5\times11\).

Step 3

Exam Tip

Since 2 appears twice, write \(2^2\). चरण 1: \(1980=198\times10\) लिखें। चरण 2: \(198=2\times3^2\times11\) और \(10=2\times5\), इसलिए \(1980=2^2\times3^2\times5\times11\)। चरण 3: 2 दो बार आता है, इसलिए \(2^2\) लिखें।

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