संख्या 1980 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 1980?
Explanation opens after your attempt
A. \(2^2\times3^2\times5\times11\)
Concept
Write \(1980=198\times10\).
Why this answer is correct
\(198=2\times3^2\times11\) and \(10=2\times5\), so \(1980=2^2\times3^2\times5\times11\).
Exam Tip
Since 2 appears twice, write \(2^2\). चरण 1: \(1980=198\times10\) लिखें। चरण 2: \(198=2\times3^2\times11\) और \(10=2\times5\), इसलिए \(1980=2^2\times3^2\times5\times11\)। चरण 3: 2 दो बार आता है, इसलिए \(2^2\) लिखें।
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