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Class 10MathematicsReal NumbersPrime FactorisationHardLevel 8

If a number has prime factorisation (2^7\times3^5\times11^2\times13), how many distinct prime factors does it have?

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Answer and explanation

Correct answer: 4

Step 1: While counting distinct prime factors, do not add exponents. Step 2: The prime bases are 2, 3, 11, and 13. Step 3: Therefore, the number of distinct prime factors is 4.

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distinct-prime-factorsprime-exponentshard

Frequently asked questions

What is the correct answer to this question?

4

Why is this the correct answer?

Step 1: While counting distinct prime factors, do not add exponents. Step 2: The prime bases are 2, 3, 11, and 13. Step 3: Therefore, the number of distinct prime factors is 4.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Prime Factorisation.

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