Concept-wise Practice

number-2772 MCQ Questions for Class 10

number-2772 se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

3 questions tagged with number-2772.

Question 1/3 Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

यदि \(2^2\times3^2\times7\times11\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?

If \(2^2\times3^2\times7\times11\) is the prime factorisation of a number, what is the number?

Explanation opens after your attempt
Correct Answer

A. 2772

Step 1

Concept

Calculate \(2^2=4\) and \(3^2=9\).

Step 2

Why this answer is correct

\(4\times9\times7\times11=2772\).

Step 3

Exam Tip

Move step by step while multiplying. चरण 1: \(2^2=4\) और \(3^2=9\) निकालें। चरण 2: \(4\times9\times7\times11=2772\)। चरण 3: गुणा करते समय चरणों में आगे बढ़ें।

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Question 2/3 Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

किस संख्या का अभाज्य गुणनखंडन \(2^2\times3^2\times7\times11\) है?

Which number has prime factorisation \(2^2\times3^2\times7\times11\)?

Explanation opens after your attempt
Correct Answer

A. 2772

Step 1

Concept

Calculate \(2^2=4\) and \(3^2=9\).

Step 2

Why this answer is correct

\(4\times9\times7\times11=2772\).

Step 3

Exam Tip

First multiply 4 and 9, then include the remaining factors. चरण 1: \(2^2=4\) और \(3^2=9\) निकालें। चरण 2: \(4\times9\times7\times11=2772\)। चरण 3: पहले 4 और 9 को गुणा करें, फिर बाकी गुणनखंड जोड़ें।

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Question 3/3 Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 2772 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 2772?

Explanation opens after your attempt
Correct Answer

A. \(2^2\times3^2\times7\times11\)

Step 1

Concept

Write \(2772=36\times77\).

Step 2

Why this answer is correct

\(36=2^2\times3^2\) and \(77=7\times11\), so \(2772=2^2\times3^2\times7\times11\).

Step 3

Exam Tip

Write 36 and 77 in prime form. चरण 1: \(2772=36\times77\) लिखें। चरण 2: \(36=2^2\times3^2\) और \(77=7\times11\), इसलिए \(2772=2^2\times3^2\times7\times11\)। चरण 3: 36 और 77 को अभाज्य रूप में लिखें।

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