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If the HCF of (2160) and (3780) is found using prime factorisation, what is the correct value?

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Answer and explanation

Correct answer: (540)

Step 1: (2160=2^4\times 3^3\times 5) and (3780=2^2\times 3^3\times 5\times 7). Step 2: For HCF, take the smaller exponents of common prime factors, so (2^2\times 3^3\times 5=540). Step 3: In such questions, carefully choose the smaller powers.

Related tags

HcfPrime FactorisationReal Numbers

Frequently asked questions

What is the correct answer to this question?

(540)

Why is this the correct answer?

Step 1: (2160=2^4\times 3^3\times 5) and (3780=2^2\times 3^3\times 5\times 7). Step 2: For HCF, take the smaller exponents of common prime factors, so (2^2\times 3^3\times 5=540). Step 3: In such questions, carefully choose the smaller powers.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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