Question 1/2
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^6\times3^3\times5^2\) है?
Which number has prime factorisation \(2^6\times3^3\times5^2\)?
#evaluate-factorisation
#number-43200
#hard
A 43200
B 21600
C 86400
D 32400
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^6=64\), \(3^3=27\), and \(5^2=25\).
Step 2
Why this answer is correct
\(64\times27\times25=43200\).
Step 3
Exam Tip
Simplify all three powers separately. चरण 1: \(2^6=64\), \(3^3=27\) और \(5^2=25\) निकालें। चरण 2: \(64\times27\times25=43200\)। चरण 3: तीनों घातों को अलग-अलग सरल करें।
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Question 2/2
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
संख्या 43200 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 43200?
#prime-factorisation
#number-43200
#hard
A \(2^6\times3^3\times5^2\)
B \(2^5\times3^3\times5^2\)
C \(432\times100\)
D \(64\times675\)
Explanation opens after your attempt
Correct Answer
A. \(2^6\times3^3\times5^2\)
Step 1
Concept
Write \(43200=432\times100\).
Step 2
Why this answer is correct
\(432=2^4\times3^3\) and \(100=2^2\times5^2\), so \(43200=2^6\times3^3\times5^2\).
Step 3
Exam Tip
Count the total power of 2 as 6. चरण 1: \(43200=432\times100\) लिखें। चरण 2: \(432=2^4\times3^3\) और \(100=2^2\times5^2\), इसलिए \(43200=2^6\times3^3\times5^2\)। चरण 3: 2 की कुल घात 6 गिनें।
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