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number-1800 MCQ Questions for Class 10

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5 questions tagged with number-1800.

Question 1/5 Medium Mathematics Real Numbers Prime factorisation Class 10 Level 7

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times5^2\) है, तो वह संख्या कौन सी है?

If the prime factorisation of a number is \(2^3\times3^2\times5^2\), which number is it?

Explanation opens after your attempt
Correct Answer

A. 1800

Step 1

Concept

Calculate \(2^3=8\), \(3^2=9\), and \(5^2=25\).

Step 2

Why this answer is correct

\(8\times9\times25=1800\).

Step 3

Exam Tip

Find each power separately and then multiply. चरण 1: \(2^3=8\), \(3^2=9\) और \(5^2=25\) निकालें। चरण 2: \(8\times9\times25=1800\)। चरण 3: तीनों घातों का मान अलग-अलग निकालकर गुणा करें।

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Question 2/5 Medium Mathematics Real Numbers Prime factorisation Class 10 Level 7

यदि \(1800=2^p\times3^2\times5^2\), तो (p) का मान क्या है?

If \(1800=2^p\times3^2\times5^2\), what is the value of (p)?

Explanation opens after your attempt
Correct Answer

A. 3

Step 1

Concept

Write \(1800=18\times100\).

Step 2

Why this answer is correct

\(18=2\times3^2\) and \(100=2^2\times5^2\), so the total power of 2 is 3.

Step 3

Exam Tip

Therefore, (p=3). चरण 1: \(1800=18\times100\) लिखें। चरण 2: \(18=2\times3^2\) और \(100=2^2\times5^2\), इसलिए 2 की कुल घात 3 है। चरण 3: इसलिए (p=3) होगा।

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Question 3/5 Medium Mathematics Real Numbers Prime factorisation Class 10 Level 7

संख्या 1800 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 1800?

Explanation opens after your attempt
Correct Answer

A. \(2^3\times3^2\times5^2\)

Step 1

Concept

Write \(1800=18\times100\).

Step 2

Why this answer is correct

\(18=2\times3^2\) and \(100=2^2\times5^2\), so \(1800=2^3\times3^2\times5^2\).

Step 3

Exam Tip

Give complete prime form to both 18 and 100. चरण 1: \(1800=18\times100\) लिखें। चरण 2: \(18=2\times3^2\) और \(100=2^2\times5^2\), इसलिए \(1800=2^3\times3^2\times5^2\)। चरण 3: 18 और 100 दोनों को पूरा अभाज्य रूप दें।

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Question 4/5 Easy Mathematics Real Numbers Prime factorisation Class 10 Level 9

किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times5^2\) है?

Which number has prime factorisation \(2^3\times3^2\times5^2\)?

Explanation opens after your attempt
Correct Answer

A. 1800

Step 1

Concept

Calculate \(2^3=8\), \(3^2=9\), and \(5^2=25\).

Step 2

Why this answer is correct

\(8\times9\times25=1800\).

Step 3

Exam Tip

Simplify powers first, then multiply. चरण 1: \(2^3=8\), \(3^2=9\) और \(5^2=25\) निकालें। चरण 2: \(8\times9\times25=1800\)। चरण 3: घातों को पहले सरल करें, फिर गुणा करें।

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Question 5/5 Easy Mathematics Real Numbers Prime factorisation Class 10 Level 9

संख्या 1800 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 1800?

Explanation opens after your attempt
Correct Answer

A. \(2^3\times3^2\times5^2\)

Step 1

Concept

Write \(1800=18\times100\).

Step 2

Why this answer is correct

\(18=2\times3^2\) and \(100=2^2\times5^2\), so \(1800=2^3\times3^2\times5^2\).

Step 3

Exam Tip

Break 18 and 100 separately into prime form. चरण 1: \(1800=18\times100\) लिखें। चरण 2: \(18=2\times3^2\) और \(100=2^2\times5^2\), इसलिए \(1800=2^3\times3^2\times5^2\)। चरण 3: 18 और 100 को अलग-अलग अभाज्य रूप में तोड़ें।

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