अभाज्य गुणनखंडन में \(18^2\times5\) को अंतिम रूप क्यों नहीं माना जाता?
Why is \(18^2\times5\) not considered the final form in prime factorisation?
#prime-factorisation
#composite-base
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A क्योंकि 18 संयुक्त संख्या है / Because 18 is composite
B क्योंकि 5 संयुक्त संख्या है / Because 5 is composite
C क्योंकि घात का प्रयोग नहीं किया जा सकता / Because powers cannot be used
D क्योंकि गुणनफल बदल जाता है / Because the product changes
Explanation opens after your attempt
Correct Answer
A. क्योंकि 18 संयुक्त संख्या है / Because 18 is composite
Step 1
Concept
अंतिम अभाज्य गुणनखंडन में आधार अभाज्य होने चाहिए। / In the final prime factorisation, bases must be prime.
Step 2
Why this answer is correct
\(18=2\times3^2\), इसलिए \(18^2\) को \(2^2\times3^4\) में बदलना होगा। / \(18=2\times3^2\), so \(18^2\) must be changed into \(2^2\times3^4\).
Step 3
Exam Tip
संयुक्त आधार को अंतिम उत्तर में न छोड़ें। / Do not leave a composite base in the final answer.
Login to save your score, XP, coins and progress. Login
संख्या 2376 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 2376?
#prime-factorisation
#number-2376
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^3\times3^3\times11\)
B \(2^2\times3^3\times11\)
C \(8\times297\)
D \(2^3\times27\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3^3\times11\)
Step 1
Concept
\(2376=8\times297\) लिखें। / Write \(2376=8\times297\).
Step 2
Why this answer is correct
\(8=2^3\) और \(297=3^3\times11\), इसलिए \(2376=2^3\times3^3\times11\)। / \(8=2^3\) and \(297=3^3\times11\), so \(2376=2^3\times3^3\times11\).
Step 3
Exam Tip
297 को अंतिम रूप में न छोड़ें। / Do not leave 297 in the final form.
Login to save your score, XP, coins and progress. Login
संख्या 3465 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 3465?
#prime-factorisation
#number-3465
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(3^2\times5\times7\times11\)
B \(3\times5\times7\times11\)
C \(9\times385\)
D \(45\times77\)
Explanation opens after your attempt
Correct Answer
A. \(3^2\times5\times7\times11\)
Step 1
Concept
\(3465=9\times385\) लिखें। / Write \(3465=9\times385\).
Step 2
Why this answer is correct
\(9=3^2\) और \(385=5\times7\times11\), इसलिए \(3465=3^2\times5\times7\times11\)। / \(9=3^2\) and \(385=5\times7\times11\), so \(3465=3^2\times5\times7\times11\).
Step 3
Exam Tip
385 को भी पूरा अभाज्य रूप दें। / Give 385 its complete prime form too.
Login to save your score, XP, coins and progress. Login
संख्या 4410 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 4410?
#prime-factorisation
#number-4410
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2\times3^2\times5\times7^2\)
B \(2^2\times3\times5\times7^2\)
C \(90\times49\)
D \(2\times45\times49\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3^2\times5\times7^2\)
Step 1
Concept
\(4410=90\times49\) लिखें। / Write \(4410=90\times49\).
Step 2
Why this answer is correct
\(90=2\times3^2\times5\) और \(49=7^2\), इसलिए \(4410=2\times3^2\times5\times7^2\)। / \(90=2\times3^2\times5\) and \(49=7^2\), so \(4410=2\times3^2\times5\times7^2\).
Step 3
Exam Tip
90 और 49 दोनों को अभाज्य रूप दें। / Give prime form to both 90 and 49.
Login to save your score, XP, coins and progress. Login
संख्या 5040 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 5040?
#prime-factorisation
#number-5040
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^4\times3^2\times5\times7\)
B \(2^3\times3^2\times5\times7\)
C \(16\times315\)
D \(2^4\times9\times35\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times3^2\times5\times7\)
Step 1
Concept
\(5040=16\times315\) लिखें। / Write \(5040=16\times315\).
Step 2
Why this answer is correct
\(16=2^4\) और \(315=3^2\times5\times7\), इसलिए \(5040=2^4\times3^2\times5\times7\)। / \(16=2^4\) and \(315=3^2\times5\times7\), so \(5040=2^4\times3^2\times5\times7\).
Step 3
Exam Tip
315 को पूरा अभाज्य रूप दें। / Give 315 its complete prime form.
Login to save your score, XP, coins and progress. Login
संख्या 5292 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 5292?
#prime-factorisation
#number-5292
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^2\times3^3\times7^2\)
B \(2^3\times3^2\times7^2\)
C \(4\times1323\)
D \(12\times441\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^3\times7^2\)
Step 1
Concept
\(5292=4\times1323\) लिखें। / Write \(5292=4\times1323\).
Step 2
Why this answer is correct
\(4=2^2\) और \(1323=3^3\times7^2\), इसलिए \(5292=2^2\times3^3\times7^2\)। / \(4=2^2\) and \(1323=3^3\times7^2\), so \(5292=2^2\times3^3\times7^2\).
Step 3
Exam Tip
1323 को 3 और 7 की घातों में बदलें। / Convert 1323 into powers of 3 and 7.
Login to save your score, XP, coins and progress. Login
संख्या 5670 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 5670?
#prime-factorisation
#number-5670
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2\times3^4\times5\times7\)
B \(2\times3^3\times5\times7\)
C \(81\times70\)
D \(2\times81\times35\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3^4\times5\times7\)
Step 1
Concept
\(5670=81\times70\) लिखें। / Write \(5670=81\times70\).
Step 2
Why this answer is correct
\(81=3^4\) और \(70=2\times5\times7\), इसलिए \(5670=2\times3^4\times5\times7\)। / \(81=3^4\) and \(70=2\times5\times7\), so \(5670=2\times3^4\times5\times7\).
Step 3
Exam Tip
81 को \(3^4\) में बदलना जरूरी है। / It is necessary to change 81 into \(3^4\).
Login to save your score, XP, coins and progress. Login
संख्या 7350 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 7350?
#prime-factorisation
#number-7350
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2\times3\times5^2\times7^2\)
B \(2^2\times3\times5\times7^2\)
C \(150\times49\)
D \(2\times75\times49\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3\times5^2\times7^2\)
Step 1
Concept
\(7350=150\times49\) लिखें। / Write \(7350=150\times49\).
Step 2
Why this answer is correct
\(150=2\times3\times5^2\) और \(49=7^2\), इसलिए \(7350=2\times3\times5^2\times7^2\)। / \(150=2\times3\times5^2\) and \(49=7^2\), so \(7350=2\times3\times5^2\times7^2\).
Step 3
Exam Tip
150 और 49 को अलग-अलग पूरा तोड़ें। / Break 150 and 49 completely and separately.
Login to save your score, XP, coins and progress. Login
संख्या 7560 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 7560?
#prime-factorisation
#number-7560
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^3\times3^3\times5\times7\)
B \(2^2\times3^3\times5\times7\)
C \(8\times945\)
D \(2^3\times27\times35\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3^3\times5\times7\)
Step 1
Concept
\(7560=8\times945\) लिखें। / Write \(7560=8\times945\).
Step 2
Why this answer is correct
\(8=2^3\) और \(945=3^3\times5\times7\), इसलिए \(7560=2^3\times3^3\times5\times7\)। / \(8=2^3\) and \(945=3^3\times5\times7\), so \(7560=2^3\times3^3\times5\times7\).
Step 3
Exam Tip
945 को अंतिम रूप में न छोड़ें। / Do not leave 945 in the final form.
Login to save your score, XP, coins and progress. Login
संख्या 8085 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 8085?
#prime-factorisation
#number-8085
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(3\times5\times7^2\times11\)
B \(3^2\times5\times7\times11\)
C \(15\times539\)
D \(3\times2695\)
Explanation opens after your attempt
Correct Answer
A. \(3\times5\times7^2\times11\)
Step 1
Concept
\(8085=15\times539\) लिखें। / Write \(8085=15\times539\).
Step 2
Why this answer is correct
\(15=3\times5\) और \(539=7^2\times11\), इसलिए \(8085=3\times5\times7^2\times11\)। / \(15=3\times5\) and \(539=7^2\times11\), so \(8085=3\times5\times7^2\times11\).
Step 3
Exam Tip
539 को भी पूरा अभाज्य रूप दें। / Give 539 its complete prime form too.
Login to save your score, XP, coins and progress. Login
संख्या 8820 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 8820?
#prime-factorisation
#number-8820
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^2\times3^2\times5\times7^2\)
B \(2\times3^2\times5\times7^2\)
C \(180\times49\)
D \(4\times2205\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^2\times5\times7^2\)
Step 1
Concept
\(8820=180\times49\) लिखें। / Write \(8820=180\times49\).
Step 2
Why this answer is correct
\(180=2^2\times3^2\times5\) और \(49=7^2\), इसलिए \(8820=2^2\times3^2\times5\times7^2\)। / \(180=2^2\times3^2\times5\) and \(49=7^2\), so \(8820=2^2\times3^2\times5\times7^2\).
Step 3
Exam Tip
180 और 49 को अभाज्य घातों में बदलें। / Convert 180 and 49 into prime powers.
Login to save your score, XP, coins and progress. Login
संख्या 9800 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 9800?
#prime-factorisation
#number-9800
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^3\times5^2\times7^2\)
B \(2^2\times5^2\times7^2\)
C \(8\times1225\)
D \(2^3\times35^2\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times5^2\times7^2\)
Step 1
Concept
\(9800=8\times1225\) लिखें। / Write \(9800=8\times1225\).
Step 2
Why this answer is correct
\(8=2^3\) और \(1225=5^2\times7^2\), इसलिए \(9800=2^3\times5^2\times7^2\)। / \(8=2^3\) and \(1225=5^2\times7^2\), so \(9800=2^3\times5^2\times7^2\).
Step 3
Exam Tip
1225 को अंतिम रूप में न छोड़ें। / Do not leave 1225 in the final form.
Login to save your score, XP, coins and progress. Login
संख्या 10368 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 10368?
#prime-factorisation
#number-10368
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^7\times3^4\)
B \(2^6\times3^4\)
C \(128\times81\)
D \(2^7\times27\times3\)
Explanation opens after your attempt
Correct Answer
A. \(2^7\times3^4\)
Step 1
Concept
\(10368=128\times81\) लिखें। / Write \(10368=128\times81\).
Step 2
Why this answer is correct
\(128=2^7\) और \(81=3^4\), इसलिए \(10368=2^7\times3^4\)। / \(128=2^7\) and \(81=3^4\), so \(10368=2^7\times3^4\).
Step 3
Exam Tip
128 और 81 दोनों को अभाज्य घातों में लिखें। / Write both 128 and 81 as prime powers.
Login to save your score, XP, coins and progress. Login
संख्या 12320 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 12320?
#prime-factorisation
#number-12320
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^5\times5\times7\times11\)
B \(2^4\times5\times7\times11\)
C \(32\times385\)
D \(2^5\times35\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^5\times5\times7\times11\)
Step 1
Concept
\(12320=32\times385\) लिखें। / Write \(12320=32\times385\).
Step 2
Why this answer is correct
\(32=2^5\) और \(385=5\times7\times11\), इसलिए \(12320=2^5\times5\times7\times11\)। / \(32=2^5\) and \(385=5\times7\times11\), so \(12320=2^5\times5\times7\times11\).
Step 3
Exam Tip
385 को पूरा अभाज्य रूप दें। / Give 385 its complete prime form.
Login to save your score, XP, coins and progress. Login
संख्या 13230 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 13230?
#prime-factorisation
#number-13230
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2\times3^3\times5\times7^2\)
B \(2^2\times3^2\times5\times7^2\)
C \(270\times49\)
D \(2\times135\times49\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3^3\times5\times7^2\)
Step 1
Concept
\(13230=270\times49\) लिखें। / Write \(13230=270\times49\).
Step 2
Why this answer is correct
\(270=2\times3^3\times5\) और \(49=7^2\), इसलिए \(13230=2\times3^3\times5\times7^2\)। / \(270=2\times3^3\times5\) and \(49=7^2\), so \(13230=2\times3^3\times5\times7^2\).
Step 3
Exam Tip
270 और 49 को अंतिम रूप में न रखें। / Do not keep 270 and 49 in the final form.
Login to save your score, XP, coins and progress. Login
संख्या 14700 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 14700?
#prime-factorisation
#number-14700
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^2\times3\times5^2\times7^2\)
B \(2\times3^2\times5^2\times7^2\)
C \(300\times49\)
D \(4\times3675\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3\times5^2\times7^2\)
Step 1
Concept
\(14700=300\times49\) लिखें। / Write \(14700=300\times49\).
Step 2
Why this answer is correct
\(300=2^2\times3\times5^2\) और \(49=7^2\), इसलिए \(14700=2^2\times3\times5^2\times7^2\)। / \(300=2^2\times3\times5^2\) and \(49=7^2\), so \(14700=2^2\times3\times5^2\times7^2\).
Step 3
Exam Tip
300 को अभाज्य घातों में बदलें। / Convert 300 into prime powers.
Login to save your score, XP, coins and progress. Login
संख्या 15840 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 15840?
#prime-factorisation
#number-15840
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^5\times3^2\times5\times11\)
B \(2^4\times3^2\times5\times11\)
C \(32\times495\)
D \(2^5\times45\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^5\times3^2\times5\times11\)
Step 1
Concept
\(15840=32\times495\) लिखें। / Write \(15840=32\times495\).
Step 2
Why this answer is correct
\(32=2^5\) और \(495=3^2\times5\times11\), इसलिए \(15840=2^5\times3^2\times5\times11\)। / \(32=2^5\) and \(495=3^2\times5\times11\), so \(15840=2^5\times3^2\times5\times11\).
Step 3
Exam Tip
495 को पूरा अभाज्य रूप दें। / Give 495 its complete prime form.
Login to save your score, XP, coins and progress. Login
संख्या 17640 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 17640?
#prime-factorisation
#number-17640
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^3\times3^2\times5\times7^2\)
B \(2^4\times3^2\times5\times7\)
C \(8\times2205\)
D \(2^3\times45\times49\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3^2\times5\times7^2\)
Step 1
Concept
\(17640=8\times2205\) लिखें। / Write \(17640=8\times2205\).
Step 2
Why this answer is correct
\(2205=3^2\times5\times7^2\), इसलिए \(17640=2^3\times3^2\times5\times7^2\)। / \(2205=3^2\times5\times7^2\), so \(17640=2^3\times3^2\times5\times7^2\).
Step 3
Exam Tip
2205 को पूरा अभाज्य रूप दें। / Give 2205 its complete prime form.
Login to save your score, XP, coins and progress. Login
संख्या 20736 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 20736?
#prime-factorisation
#square-number
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^8\times3^4\)
B \(2^7\times3^4\)
C \(256\times81\)
D \(144^2\)
Explanation opens after your attempt
Correct Answer
A. \(2^8\times3^4\)
Step 1
Concept
\(20736=256\times81\) लिखें। / Write \(20736=256\times81\).
Step 2
Why this answer is correct
\(256=2^8\) और \(81=3^4\), इसलिए \(20736=2^8\times3^4\)। / \(256=2^8\) and \(81=3^4\), so \(20736=2^8\times3^4\).
Step 3
Exam Tip
256 और 81 को अभाज्य घातों में बदलें। / Convert 256 and 81 into prime powers.
Login to save your score, XP, coins and progress. Login
संख्या 22050 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 22050?
#prime-factorisation
#number-22050
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2\times3^2\times5^2\times7^2\)
B \(2^2\times3\times5^2\times7^2\)
C \(450\times49\)
D \(2\times225\times49\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3^2\times5^2\times7^2\)
Step 1
Concept
\(22050=450\times49\) लिखें। / Write \(22050=450\times49\).
Step 2
Why this answer is correct
\(450=2\times3^2\times5^2\) और \(49=7^2\), इसलिए \(22050=2\times3^2\times5^2\times7^2\)। / \(450=2\times3^2\times5^2\) and \(49=7^2\), so \(22050=2\times3^2\times5^2\times7^2\).
Step 3
Exam Tip
450 को पूरा अभाज्य रूप दें। / Give 450 its complete prime form.
Login to save your score, XP, coins and progress. Login
संख्या 27720 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 27720?
#prime-factorisation
#number-27720
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^3\times3^2\times5\times7\times11\)
B \(2^2\times3^3\times5\times7\times11\)
C \(8\times3465\)
D \(2^3\times9\times385\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3^2\times5\times7\times11\)
Step 1
Concept
\(27720=8\times3465\) लिखें। / Write \(27720=8\times3465\).
Step 2
Why this answer is correct
\(3465=3^2\times5\times7\times11\), इसलिए \(27720=2^3\times3^2\times5\times7\times11\)। / \(3465=3^2\times5\times7\times11\), so \(27720=2^3\times3^2\times5\times7\times11\).
Step 3
Exam Tip
3465 को पूरा अभाज्य रूप दें। / Give 3465 its complete prime form.
Login to save your score, XP, coins and progress. Login
यदि \(15840=2^a\times3^2\times5\times11\), तो (a) का मान क्या है?
If \(15840=2^a\times3^2\times5\times11\), what is the value of (a)?
#exponent-comparison
#number-15840
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 5
B 4
C 6
D 3
Explanation opens after your attempt
Step 1
Concept
\(15840=32\times495\) है। / \(15840=32\times495\).
Step 2
Why this answer is correct
\(32=2^5\) और \(495=3^2\times5\times11\), इसलिए 2 की घात 5 है। / \(32=2^5\) and \(495=3^2\times5\times11\), so the power of 2 is 5.
Step 3
Exam Tip
तुलना करने पर (a=5) मिलेगा। / Comparing gives (a=5).
Login to save your score, XP, coins and progress. Login
यदि \(22050=2\times3^b\times5^2\times7^2\), तो (b) का मान क्या है?
If \(22050=2\times3^b\times5^2\times7^2\), what is the value of (b)?
#exponent-comparison
#number-22050
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 2
B 1
C 3
D 4
Explanation opens after your attempt
Step 1
Concept
\(22050=450\times49\) लिखें। / Write \(22050=450\times49\).
Step 2
Why this answer is correct
\(450=2\times3^2\times5^2\) और \(49=7^2\), इसलिए 3 की घात 2 है। / \(450=2\times3^2\times5^2\) and \(49=7^2\), so the power of 3 is 2.
Step 3
Exam Tip
दिए गए रूप से तुलना करने पर (b=2) है। / Comparing with the given form gives (b=2).
Login to save your score, XP, coins and progress. Login
यदि \(20736=2^m\times3^4\), तो (m) का मान क्या है?
If \(20736=2^m\times3^4\), what is the value of (m)?
#exponent-comparison
#number-20736
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 8
B 7
C 6
D 9
Explanation opens after your attempt
Step 1
Concept
\(20736=256\times81\) लिखा जा सकता है। / (20736) can be written as \(256\times81\).
Step 2
Why this answer is correct
\(256=2^8\) और \(81=3^4\), इसलिए \(20736=2^8\times3^4\)। / \(256=2^8\) and \(81=3^4\), so \(20736=2^8\times3^4\).
Step 3
Exam Tip
तुलना करने पर (m=8) है। / Comparing gives (m=8).
Login to save your score, XP, coins and progress. Login
यदि \(27720=2^3\times3^2\times5\times7\times11\), तो इसमें अलग-अलग अभाज्य गुणनखंड कितने हैं?
If \(27720=2^3\times3^2\times5\times7\times11\), how many distinct prime factors does it have?
#distinct-prime-factors
#prime-exponents
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 5
B 8
C 6
D 11
Explanation opens after your attempt
Step 1
Concept
अलग-अलग अभाज्य गुणनखंडों में घातों को नहीं जोड़ा जाता। / For distinct prime factors, exponents are not added.
Step 2
Why this answer is correct
आधार 2, 3, 5, 7 और 11 हैं। / The bases are 2, 3, 5, 7, and 11.
Step 3
Exam Tip
इसलिए अलग-अलग अभाज्य गुणनखंड 5 हैं। / Therefore, there are 5 distinct prime factors.
Login to save your score, XP, coins and progress. Login
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^3\times11\) है?
Which number has prime factorisation \(2^3\times3^3\times11\)?
#evaluate-factorisation
#number-2376
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 2376
B 1188
C 4752
D 3564
Explanation opens after your attempt
Step 1
Concept
\(2^3=8\) और \(3^3=27\) निकालें। / Calculate \(2^3=8\) and \(3^3=27\).
Step 2
Why this answer is correct
\(8\times27\times11=2376\)। / \(8\times27\times11=2376\).
Step 3
Exam Tip
घातों का मान पहले निकालना सही तरीका है। / Finding powers first is the correct method.
Login to save your score, XP, coins and progress. Login
किस संख्या का अभाज्य गुणनखंडन \(3^2\times5\times7\times11\) है?
Which number has prime factorisation \(3^2\times5\times7\times11\)?
#evaluate-factorisation
#number-3465
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 3465
B 1732
C 6930
D 1155
Explanation opens after your attempt
Step 1
Concept
\(3^2=9\) निकालें। / Calculate \(3^2=9\).
Step 2
Why this answer is correct
\(9\times5\times7\times11=3465\)। / \(9\times5\times7\times11=3465\).
Step 3
Exam Tip
कई गुणनखंड हों तो जोड़े बनाकर गुणा करें। / When there are many factors, multiply in pairs.
Login to save your score, XP, coins and progress. Login
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3^2\times5\times7\) है?
Which number has prime factorisation \(2^4\times3^2\times5\times7\)?
#evaluate-factorisation
#number-5040
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 5040
B 2520
C 10080
D 7560
Explanation opens after your attempt
Step 1
Concept
\(2^4=16\) और \(3^2=9\) निकालें। / Calculate \(2^4=16\) and \(3^2=9\).
Step 2
Why this answer is correct
\(16\times9\times5\times7=5040\)। / \(16\times9\times5\times7=5040\).
Step 3
Exam Tip
पहले \(16\times9=144\) करें, फिर बाकी गुणा करें। / First do \(16\times9=144\), then multiply the rest.
Login to save your score, XP, coins and progress. Login
किस संख्या का अभाज्य गुणनखंडन \(2^2\times3^3\times7^2\) है?
Which number has prime factorisation \(2^2\times3^3\times7^2\)?
#evaluate-factorisation
#number-5292
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 5292
B 2646
C 10584
D 4410
Explanation opens after your attempt
Step 1
Concept
\(2^2=4\), \(3^3=27\) और \(7^2=49\) निकालें। / Calculate \(2^2=4\), \(3^3=27\), and \(7^2=49\).
Step 2
Why this answer is correct
\(4\times27\times49=5292\)। / \(4\times27\times49=5292\).
Step 3
Exam Tip
तीनों घातों को अलग-अलग सरल करें। / Simplify all three powers separately.
Login to save your score, XP, coins and progress. Login
किस संख्या का अभाज्य गुणनखंडन \(2^7\times3^4\) है?
Which number has prime factorisation \(2^7\times3^4\)?
#evaluate-factorisation
#number-10368
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 10368
B 5184
C 20736
D 7776
Explanation opens after your attempt
Step 1
Concept
\(2^7=128\) और \(3^4=81\) निकालें। / Calculate \(2^7=128\) and \(3^4=81\).
Step 2
Why this answer is correct
\(128\times81=10368\)। / \(128\times81=10368\).
Step 3
Exam Tip
बड़ी घातों को पहले हल करने से गलती कम होती है। / Solving large powers first reduces mistakes.
Login to save your score, XP, coins and progress. Login
यदि संख्या \(2^7\times3^2\times5^3\times11\) है, तो इसे पूर्ण वर्ग बनाने के लिए सबसे छोटी किस संख्या से गुणा करना होगा?
If the number is \(2^7\times3^2\times5^3\times11\), by which smallest number should it be multiplied to make a perfect square?
#perfect-square
#prime-exponents
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 110
B 10
C 55
D 22
Explanation opens after your attempt
Step 1
Concept
पूर्ण वर्ग में सभी घातें सम होती हैं। / In a perfect square, all exponents are even.
Step 2
Why this answer is correct
2 की घात 7, 5 की घात 3 और 11 की घात 1 विषम हैं। / Powers of 2, 5, and 11 are odd.
Step 3
Exam Tip
\(2\times5\times11=110\) से गुणा करने पर सभी घातें सम हो जाएंगी। / Multiplying by \(2\times5\times11=110\) makes all exponents even.
Login to save your score, XP, coins and progress. Login
यदि संख्या \(2^6\times3^5\times7^2\) है, तो इसे पूर्ण वर्ग बनाने के लिए सबसे छोटी किस संख्या से भाग देना होगा?
If the number is \(2^6\times3^5\times7^2\), by which smallest number should it be divided to make a perfect square?
#perfect-square
#division
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 3
B 9
C 21
D 7
Explanation opens after your attempt
Step 1
Concept
पूर्ण वर्ग में सभी घातें सम होनी चाहिए। / In a perfect square, all exponents should be even.
Step 2
Why this answer is correct
केवल 3 की घात 5 विषम है। / Only the power of 3 is odd.
Step 3
Exam Tip
3 से भाग देने पर 3 की घात 4 हो जाएगी और संख्या पूर्ण वर्ग बनेगी। / Dividing by 3 makes the power of 3 equal to 4 and the number becomes a perfect square.
Login to save your score, XP, coins and progress. Login
यदि संख्या \(2^5\times3^4\times5^2\times7\) है, तो इसे पूर्ण घन बनाने के लिए सबसे छोटी किस संख्या से गुणा करना होगा?
If the number is \(2^5\times3^4\times5^2\times7\), by which smallest number should it be multiplied to make a perfect cube?
#perfect-cube
#prime-exponents
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2\times3^2\times5\times7^2\)
B \(2\times3\times5\times7\)
C \(3^2\times7^2\)
D \(2^2\times5\times7\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3^2\times5\times7^2\)
Step 1
Concept
पूर्ण घन में घातें 3 के गुणज होती हैं। / In a perfect cube, exponents are multiples of 3.
Step 2
Why this answer is correct
2 की घात 5 को 6, 3 की घात 4 को 6, 5 की घात 2 को 3 और 7 की घात 1 को 3 बनाना होगा। / Powers 5, 4, 2, and 1 must become 6, 6, 3, and 3.
Step 3
Exam Tip
सबसे छोटा गुणक \(2\times3^2\times5\times7^2\) है। / The smallest multiplier is \(2\times3^2\times5\times7^2\).
Login to save your score, XP, coins and progress. Login
यदि संख्या \(2^8\times3^7\times5^4\) है, तो इसे पूर्ण घन बनाने के लिए सबसे छोटी किस संख्या से भाग देना होगा?
If the number is \(2^8\times3^7\times5^4\), by which smallest number should it be divided to make a perfect cube?
#perfect-cube
#division
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^2\times3\times5\)
B \(2\times3\times5\)
C \(2^2\times3^2\times5\)
D \(2\times5\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3\times5\)
Step 1
Concept
पूर्ण घन के लिए घातें 3 के गुणज चाहिए। / For a perfect cube, exponents should be multiples of 3.
Step 2
Why this answer is correct
8 को 6, 7 को 6 और 4 को 3 तक घटाना सबसे छोटा तरीका है। / Reducing 8 to 6, 7 to 6, and 4 to 3 is the smallest way.
Step 3
Exam Tip
इसलिए भाजक \(2^2\times3\times5\) होगा। / Therefore, the divisor is \(2^2\times3\times5\).
Login to save your score, XP, coins and progress. Login
यदि \(n=2^5\times3^4\times5^2\times7\), तो (n) किस संख्या से विभाज्य नहीं होगा?
If \(n=2^5\times3^4\times5^2\times7\), by which number will (n) not be divisible?
#divisibility
#prime-exponents
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^6\)
B \(2^4\times3^2\)
C \(3^4\times5\)
D \(2^5\times7\)
Explanation opens after your attempt
Correct Answer
A. \(2^6\)
Step 1
Concept
किसी भाजक की हर अभाज्य घात संख्या में उपलब्ध होनी चाहिए। / Every prime power of a divisor must be available in the number.
Step 2
Why this answer is correct
(n) में 2 की घात 5 है, लेकिन \(2^6\) के लिए 6 चाहिए। / (n) has power 5 of 2, but \(2^6\) needs 6.
Step 3
Exam Tip
इसलिए (n), \(2^6\) से विभाज्य नहीं होगा। / Therefore, (n) is not divisible by \(2^6\).
Login to save your score, XP, coins and progress. Login
यदि \(n=2^6\times3^2\times5^5\times11\), तो (n) किस संख्या से अवश्य विभाज्य होगा?
If \(n=2^6\times3^2\times5^5\times11\), by which number must (n) be divisible?
#divisibility
#prime-exponents
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^5\times3\times5^4\times11\)
B \(2^7\times3\times5^4\)
C \(3^3\times5^2\)
D \(2^6\times5^6\)
Explanation opens after your attempt
Correct Answer
A. \(2^5\times3\times5^4\times11\)
Step 1
Concept
विभाज्यता के लिए भाजक की घातें संख्या की घातों से अधिक नहीं होनी चाहिए। / For divisibility, exponents in the divisor must not exceed those in the number.
Step 2
Why this answer is correct
\(2^5\), (3), \(5^4\) और 11 सभी (n) में उपलब्ध हैं। / \(2^5\), (3), \(5^4\), and 11 are all available in (n).
Step 3
Exam Tip
इसलिए (n) इस संख्या से अवश्य विभाज्य होगा। / Therefore, (n) must be divisible by this number.
Login to save your score, XP, coins and progress. Login
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^6\times3^4\times5^3\times7^2\) है, तो दोहराव सहित अभाज्य गुणनखंडों की संख्या कितनी है?
If a number has prime factorisation \(2^6\times3^4\times5^3\times7^2\), how many prime factors does it have with repetition?
#counting-prime-factors
#prime-exponents
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 15
B 4
C 12
D 10
Explanation opens after your attempt
Step 1
Concept
दोहराव सहित गिनती में घातों को जोड़ा जाता है। / For counting with repetition, add the exponents.
Step 2
Why this answer is correct
(6+4+3+2=15)। / (6+4+3+2=15).
Step 3
Exam Tip
अलग-अलग आधारों की संख्या और दोहराव सहित संख्या में अंतर याद रखें। / Remember the difference between the number of distinct bases and the count with repetition.
Login to save your score, XP, coins and progress. Login
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^4\times3^7\times11^3\times13^2\) है, तो उसमें अलग-अलग अभाज्य गुणनखंड कितने हैं?
If a number has prime factorisation \(2^4\times3^7\times11^3\times13^2\), how many distinct prime factors does it have?
#distinct-prime-factors
#prime-exponents
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 4
B 16
C 7
D 5
Explanation opens after your attempt
Step 1
Concept
अलग-अलग अभाज्य गिनते समय केवल आधार गिने जाते हैं। / While counting distinct primes, only bases are counted.
Step 2
Why this answer is correct
आधार 2, 3, 11 और 13 हैं। / The bases are 2, 3, 11, and 13.
Step 3
Exam Tip
इसलिए अलग-अलग अभाज्य गुणनखंड 4 हैं। / Therefore, there are 4 distinct prime factors.
Login to save your score, XP, coins and progress. Login
यदि \(a=2^4\times3^5\times7\) और \(b=2^3\times3^2\times5\times7^2\), तो (ab) में 7 की घात क्या होगी?
If \(a=2^4\times3^5\times7\) and \(b=2^3\times3^2\times5\times7^2\), what will be the power of 7 in (ab)?
#product-factorisation
#powers
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 3
B 2
C 1
D 4
Explanation opens after your attempt
Step 1
Concept
गुणा में समान अभाज्य आधार की घातें जुड़ती हैं। / In multiplication, powers of the same prime base are added.
Step 2
Why this answer is correct
(a) में 7 की घात 1 है और (b) में 7 की घात 2 है। / The power of 7 in (a) is 1 and in (b) is 2.
Step 3
Exam Tip
(ab) में 7 की घात (1+2=3) होगी। / In (ab), the power of 7 will be (1+2=3).
Login to save your score, XP, coins and progress. Login
यदि \(x=2^7\times5^4\times11^2\) और \(y=2^2\times3^3\times5^3\times11\), तो (xy) में 11 की घात क्या होगी?
If \(x=2^7\times5^4\times11^2\) and \(y=2^2\times3^3\times5^3\times11\), what will be the power of 11 in (xy)?
#product-factorisation
#powers
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 3
B 2
C 1
D 4
Explanation opens after your attempt
Step 1
Concept
समान आधार 11 की घातें गुणा में जोड़ी जाती हैं। / Powers of the same base 11 are added in multiplication.
Step 2
Why this answer is correct
(x) में 11 की घात 2 है और (y) में 11 की घात 1 है। / The power of 11 in (x) is 2 and in (y) is 1.
Step 3
Exam Tip
कुल घात (2+1=3) होगी। / The total power will be (2+1=3).
Login to save your score, XP, coins and progress. Login
किस विकल्प में \(2^4\times3^2\times5\times7^2\) का सही मान है?
Which option gives the correct value of \(2^4\times3^2\times5\times7^2\)?
#evaluate-factorisation
#number-35280
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 35280
B 17640
C 70560
D 22050
Explanation opens after your attempt
Step 1
Concept
\(2^4=16\), \(3^2=9\) और \(7^2=49\) निकालें। / Calculate \(2^4=16\), \(3^2=9\), and \(7^2=49\).
Step 2
Why this answer is correct
\(16\times9\times5\times49=35280\)। / \(16\times9\times5\times49=35280\).
Step 3
Exam Tip
घातों को पहले अलग-अलग हल करें। / Solve powers separately first.
Login to save your score, XP, coins and progress. Login
किस विकल्प में \(2^8\times3^4\) का सही मान है?
Which option gives the correct value of \(2^8\times3^4\)?
#evaluate-factorisation
#number-20736
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 20736
B 10368
C 41472
D 7776
Explanation opens after your attempt
Step 1
Concept
\(2^8=256\) और \(3^4=81\) निकालें। / Calculate \(2^8=256\) and \(3^4=81\).
Step 2
Why this answer is correct
\(256\times81=20736\)। / \(256\times81=20736\).
Step 3
Exam Tip
बड़ी घातों को अलग-अलग सरल करके गुणा करें। / Simplify higher powers separately and multiply.
Login to save your score, XP, coins and progress. Login
किस विकल्प में केवल अंतिम अभाज्य गुणनखंडन दिया गया है?
Which option gives only the final prime factorisation?
#prime-factorisation
#final-form
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^3\times3^2\times5\times7\times11\)
B \(8\times9\times385\)
C \(2^3\times9\times385\)
D \(72\times385\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3^2\times5\times7\times11\)
Step 1
Concept
अंतिम रूप में आधार अभाज्य होने चाहिए। / In the final form, bases must be prime.
Step 2
Why this answer is correct
पहले रूप में आधार 2, 3, 5, 7 और 11 अभाज्य हैं। / In the first form, the bases 2, 3, 5, 7, and 11 are prime.
Step 3
Exam Tip
8, 9, 385 और 72 संयुक्त हैं, इसलिए वे अंतिम रूप नहीं हैं। / 8, 9, 385, and 72 are composite, so they are not final forms.
Login to save your score, XP, coins and progress. Login
किस विकल्प में अभाज्य गुणनखंडन अधूरा है?
Which option has incomplete prime factorisation?
#prime-factorisation
#incomplete-form
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^4\times45\times49\)
B \(2^4\times3^2\times5\times7^2\)
C \(2^3\times3^3\times5\times7\)
D \(2\times3\times5^2\times7^2\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times45\times49\)
Step 1
Concept
अधूरे रूप में संयुक्त गुणनखंड बचा रहता है। / In an incomplete form, composite factors remain.
Step 2
Why this answer is correct
45 और 49 दोनों संयुक्त हैं। / Both 45 and 49 are composite.
Step 3
Exam Tip
\(2^4\times45\times49\) को \(2^4\times3^2\times5\times7^2\) में बदलना होगा। / \(2^4\times45\times49\) must be changed into \(2^4\times3^2\times5\times7^2\).
Login to save your score, XP, coins and progress. Login
यदि \(2^4\times3^2\times5\times7\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^4\times3^2\times5\times7\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#hard
#mcq
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 5040
B 2520
C 10080
D 7560
Explanation opens after your attempt
Step 1
Concept
\(2^4=16\) और \(3^2=9\) निकालें। / Calculate \(2^4=16\) and \(3^2=9\).
Step 2
Why this answer is correct
\(16\times9\times5\times7=5040\)। / \(16\times9\times5\times7=5040\).
Step 3
Exam Tip
घातों को पहले हल करने से सही विकल्प जल्दी मिलता है। / Solving powers first helps find the correct option quickly.
Login to save your score, XP, coins and progress. Login
यदि \(2^3\times5^2\times7^2\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^3\times5^2\times7^2\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#square-base
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A 9800
B 4900
C 19600
D 1225
Explanation opens after your attempt
Step 1
Concept
\(2^3=8\), \(5^2=25\) और \(7^2=49\) निकालें। / Calculate \(2^3=8\), \(5^2=25\), and \(7^2=49\).
Step 2
Why this answer is correct
\(8\times25\times49=9800\)। / \(8\times25\times49=9800\).
Step 3
Exam Tip
तीनों घातों का मान अलग-अलग निकालें। / Find all three powers separately.
Login to save your score, XP, coins and progress. Login
संख्या 29400 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 29400?
#prime-factorisation
#number-29400
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^3\times3\times5^2\times7^2\)
B \(2^2\times3^2\times5^2\times7\)
C \(600\times49\)
D \(8\times3675\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3\times5^2\times7^2\)
Step 1
Concept
\(29400=600\times49\) लिखें। / Write \(29400=600\times49\).
Step 2
Why this answer is correct
\(600=2^3\times3\times5^2\) और \(49=7^2\), इसलिए \(29400=2^3\times3\times5^2\times7^2\)। / \(600=2^3\times3\times5^2\) and \(49=7^2\), so \(29400=2^3\times3\times5^2\times7^2\).
Step 3
Exam Tip
600 और 49 को पूरी तरह तोड़ें। / Break 600 and 49 completely.
Login to save your score, XP, coins and progress. Login
संख्या 33075 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 33075?
#prime-factorisation
#number-33075
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(3^3\times5^2\times7^2\)
B \(3^2\times5^3\times7^2\)
C \(675\times49\)
D \(27\times1225\)
Explanation opens after your attempt
Correct Answer
A. \(3^3\times5^2\times7^2\)
Step 1
Concept
\(33075=675\times49\) लिखें। / Write \(33075=675\times49\).
Step 2
Why this answer is correct
\(675=3^3\times5^2\) और \(49=7^2\), इसलिए \(33075=3^3\times5^2\times7^2\)। / \(675=3^3\times5^2\) and \(49=7^2\), so \(33075=3^3\times5^2\times7^2\).
Step 3
Exam Tip
675 और 49 को अभाज्य घातों में लिखें। / Write 675 and 49 as prime powers.
Login to save your score, XP, coins and progress. Login
संख्या 46656 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 46656?
#prime-factorisation
#number-46656
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(2^6\times3^6\)
B \(2^5\times3^6\)
C \(64\times729\)
D \(6^6\)
Explanation opens after your attempt
Correct Answer
A. \(2^6\times3^6\)
Step 1
Concept
\(46656=64\times729\) लिखा जा सकता है। / (46656) can be written as \(64\times729\).
Step 2
Why this answer is correct
\(64=2^6\) और \(729=3^6\), इसलिए \(46656=2^6\times3^6\)। / \(64=2^6\) and \(729=3^6\), so \(46656=2^6\times3^6\).
Step 3
Exam Tip
64 और 729 को अंतिम रूप में न छोड़ें। / Do not leave 64 and 729 in the final form.
Login to save your score, XP, coins and progress. Login
अभाज्य गुणनखंडन में \(600\times49\) को अंतिम उत्तर क्यों नहीं माना जाएगा?
Why will \(600\times49\) not be considered the final answer in prime factorisation?
#prime-factorisation
#concept-check
#hard
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A क्योंकि 600 और 49 संयुक्त रूप हैं / Because 600 and 49 are composite forms
B क्योंकि 49 अभाज्य संख्या है / Because 49 is prime
C क्योंकि 600 को तोड़ा नहीं जा सकता / Because 600 cannot be factorised
D क्योंकि गुणनफल बदल जाएगा / Because the product will change
Explanation opens after your attempt
Correct Answer
A. क्योंकि 600 और 49 संयुक्त रूप हैं / Because 600 and 49 are composite forms
Step 1
Concept
अंतिम अभाज्य गुणनखंडन में हर आधार अभाज्य होना चाहिए। / In final prime factorisation, every base should be prime.
Step 2
Why this answer is correct
\(600=2^3\times3\times5^2\) और \(49=7^2\) है। / \(600=2^3\times3\times5^2\) and \(49=7^2\).
Step 3
Exam Tip
इसलिए अंतिम रूप \(2^3\times3\times5^2\times7^2\) होगा। / Therefore, the final form is \(2^3\times3\times5^2\times7^2\).
Login to save your score, XP, coins and progress. Login
