संख्या 9800 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 9800?
Explanation opens after your attempt
Correct Answer
A. \(2^3\times5^2\times7^2\)
Concept
Write \(9800=8\times1225\).
Why this answer is correct
\(8=2^3\) and \(1225=5^2\times7^2\), so \(9800=2^3\times5^2\times7^2\).
Exam Tip
Do not leave 1225 in the final form. चरण 1: \(9800=8\times1225\) लिखें। चरण 2: \(8=2^3\) और \(1225=5^2\times7^2\), इसलिए \(9800=2^3\times5^2\times7^2\)। चरण 3: 1225 को अंतिम रूप में न छोड़ें।
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