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What is the correct prime factorisation of 4410?
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Answer and explanation
Correct answer: (2\times3^2\times5\times7^2)
Step 1: Write (4410=90\times49). Step 2: (90=2\times3^2\times5) and (49=7^2), so (4410=2\times3^2\times5\times7^2). Step 3: Give prime form to both 90 and 49.
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What is the correct answer to this question?
(2\times3^2\times5\times7^2)
Why is this the correct answer?
Step 1: Write (4410=90\times49). Step 2: (90=2\times3^2\times5) and (49=7^2), so (4410=2\times3^2\times5\times7^2). Step 3: Give prime form to both 90 and 49.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Prime Factorisation.
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