Concept-wise Practice

number-127008 MCQ Questions for Class 10

number-127008 se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

4 questions tagged with number-127008.

Question 1/4 Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

किस विकल्प में \(2^5\times3^4\times7^2\) का सही मान है?

Which option gives the correct value of \(2^5\times3^4\times7^2\)?

Explanation opens after your attempt
Correct Answer

A. 127008

Step 1

Concept

Calculate \(2^5=32\), \(3^4=81\), and \(7^2=49\).

Step 2

Why this answer is correct

\(32\times81\times49=127008\).

Step 3

Exam Tip

Solve all three powers separately first. चरण 1: \(2^5=32\), \(3^4=81\) और \(7^2=49\) निकालें। चरण 2: \(32\times81\times49=127008\)। चरण 3: तीनों घातों को पहले अलग-अलग हल करें।

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Question 2/4 Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

किस संख्या का अभाज्य गुणनखंडन \(2^5\times3^4\times7^2\) है?

Which number has prime factorisation \(2^5\times3^4\times7^2\)?

Explanation opens after your attempt
Correct Answer

A. 127008

Step 1

Concept

Calculate \(2^5=32\), \(3^4=81\), and \(7^2=49\).

Step 2

Why this answer is correct

\(32\times81\times49=127008\).

Step 3

Exam Tip

Solving powers first keeps multiplication clear. चरण 1: \(2^5=32\), \(3^4=81\) और \(7^2=49\) निकालें। चरण 2: \(32\times81\times49=127008\)। चरण 3: घातों को पहले हल करने से गुणा साफ रहता है।

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Question 3/4 Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

यदि \(127008=2^a\times3^4\times7^2\), तो (a) का मान क्या है?

If \(127008=2^a\times3^4\times7^2\), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

A. 5

Step 1

Concept

\(127008=32\times3969\).

Step 2

Why this answer is correct

\(32=2^5\) and \(3969=3^4\times7^2\), so the power of 2 is 5.

Step 3

Exam Tip

Comparing gives (a=5). चरण 1: \(127008=32\times3969\) है। चरण 2: \(32=2^5\) और \(3969=3^4\times7^2\), इसलिए 2 की घात 5 है। चरण 3: तुलना करने पर (a=5) मिलता है।

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Question 4/4 Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

संख्या 127008 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 127008?

Explanation opens after your attempt
Correct Answer

A. \(2^5\times3^4\times7^2\)

Step 1

Concept

Write \(127008=32\times3969\).

Step 2

Why this answer is correct

\(3969=3^4\times7^2\), so \(127008=2^5\times3^4\times7^2\).

Step 3

Exam Tip

Convert 3969 into prime powers. चरण 1: \(127008=32\times3969\) लिखें। चरण 2: \(3969=3^4\times7^2\), इसलिए \(127008=2^5\times3^4\times7^2\)। चरण 3: 3969 को अभाज्य घातों में बदलें।

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