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number-252 MCQ Questions for Class 10

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2 questions tagged with number-252.

Question 1/2 Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

किस संख्या का अभाज्य गुणनखंडन \(2^2\times3^2\times7\) है?

Which number has prime factorisation \(2^2\times3^2\times7\)?

Explanation opens after your attempt
Correct Answer

A. 252

Step 1

Concept

Calculate \(2^2=4\) and \(3^2=9\).

Step 2

Why this answer is correct

\(4\times9\times7=252\).

Step 3

Exam Tip

Evaluate prime powers and then multiply. चरण 1: \(2^2=4\) और \(3^2=9\) निकालें। चरण 2: \(4\times9\times7=252\)। चरण 3: अभाज्य घातों का मान निकालकर गुणा करें।

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Question 2/2 Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 252 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 252?

Explanation opens after your attempt
Correct Answer

A. \(2^2\times3^2\times7\)

Step 1

Concept

Write \(252=4\times63\).

Step 2

Why this answer is correct

\(4=2^2\) and \(63=3^2\times7\), so \(252=2^2\times3^2\times7\).

Step 3

Exam Tip

Break 63 completely into prime form too. चरण 1: \(252=4\times63\) लिखें। चरण 2: \(4=2^2\) और \(63=3^2\times7\), इसलिए \(252=2^2\times3^2\times7\)। चरण 3: 63 को भी पूरी तरह अभाज्य रूप में तोड़ें।

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