Concept-wise Practice

number-99225 MCQ Questions for Class 10

number-99225 se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

2 questions tagged with number-99225.

Question 1/2 Expert Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

किस संख्या का अभाज्य गुणनखंडन \(3^4\times5^2\times7^2\) है?

Which number has prime factorisation \(3^4\times5^2\times7^2\)?

Explanation opens after your attempt
Correct Answer

A. 99225

Step 1

Concept

Calculate \(3^4=81\), \(5^2=25\), and \(7^2=49\).

Step 2

Why this answer is correct

\(81\times25\times49=99225\).

Step 3

Exam Tip

Do not skip square powers in a hurry. चरण 1: \(3^4=81\), \(5^2=25\) और \(7^2=49\) निकालें। चरण 2: \(81\times25\times49=99225\)। चरण 3: वर्ग घातों को जल्दबाजी में न छोड़ें।

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Question 2/2 Expert Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 99225 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 99225?

Explanation opens after your attempt
Correct Answer

A. \(3^4\times5^2\times7^2\)

Step 1

Concept

Write \(99225=81\times1225\).

Step 2

Why this answer is correct

\(81=3^4\) and \(1225=5^2\times7^2\), so \(99225=3^4\times5^2\times7^2\).

Step 3

Exam Tip

Convert 1225 into prime powers. चरण 1: \(99225=81\times1225\) लिखें। चरण 2: \(81=3^4\) और \(1225=5^2\times7^2\), इसलिए \(99225=3^4\times5^2\times7^2\)। चरण 3: 1225 को अभाज्य घातों में बदलें।

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