Concept-wise Practice

number-25410 MCQ Questions for Class 10

number-25410 se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

2 questions tagged with number-25410.

Question 1/2 Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

किस संख्या का अभाज्य गुणनखंडन \(2\times3\times5\times7\times11^2\) है?

Which number has prime factorisation \(2\times3\times5\times7\times11^2\)?

Explanation opens after your attempt
Correct Answer

A. 25410

Step 1

Concept

Calculate \(11^2=121\).

Step 2

Why this answer is correct

\(2\times3\times5\times7\times121=25410\).

Step 3

Exam Tip

First take the product of smaller factors as 210, then multiply by 121. चरण 1: \(11^2=121\) निकालें। चरण 2: \(2\times3\times5\times7\times121=25410\)। चरण 3: पहले छोटे गुणनखंडों का गुणनफल 210 लें, फिर 121 से गुणा करें।

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Question 2/2 Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

संख्या 25410 का अभाज्य गुणनखंडन कौन सा है?

Which is the prime factorisation of 25410?

Explanation opens after your attempt
Correct Answer

A. \(2\times3\times5\times7\times11^2\)

Step 1

Concept

Write \(25410=210\times121\).

Step 2

Why this answer is correct

\(210=2\times3\times5\times7\) and \(121=11^2\), so \(25410=2\times3\times5\times7\times11^2\).

Step 3

Exam Tip

Give prime form to both 210 and 121. चरण 1: \(25410=210\times121\) लिखें। चरण 2: \(210=2\times3\times5\times7\) और \(121=11^2\), इसलिए \(25410=2\times3\times5\times7\times11^2\)। चरण 3: 210 और 121 दोनों को अभाज्य रूप दें।

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