42 results found for "300 deaths" in Class 10.
संख्या 300 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 300?
#prime-factorisation
#number-300
#easy
A \(2^2\times3\times5^2\)
B \(30\times10\)
C \(3\times100\)
D \(2\times150\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3\times5^2\)
Step 1
Concept
Write \(300=3\times100\).
Step 2
Why this answer is correct
\(100=2^2\times5^2\), so \(300=2^2\times3\times5^2\).
Step 3
Exam Tip
Convert 100 into prime powers. चरण 1: \(300=3\times100\) लिखें। चरण 2: \(100=2^2\times5^2\), इसलिए \(300=2^2\times3\times5^2\)। चरण 3: 100 को अभाज्य घातों में बदलें।
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एक दुकान पहले दिन (300) पैकेट बेचती है और हर अगले दिन (16) पैकेट कम बेचती है। (13) दिनों में कुल कितने पैकेट बिकेंगे?
A shop sells (300) packets on the first day and (16) fewer packets each next day. How many packets are sold in (13) days?
#ap
#word-problem
#sales
#decrease
A (2552)
B (2602)
C (2652)
D (2702)
Explanation opens after your attempt
Step 1
Concept
The sales form the decreasing AP \(300,284,268,\ldots\) and \(S_{13}=2652\). Exam tip: keep (d) negative for decreasing sales.
Step 2
Why this answer is correct
The correct answer is C. (2652). The sales form the decreasing AP \(300,284,268,\ldots\) and \(S_{13}=2652\). Exam tip: keep (d) negative for decreasing sales.
Step 3
Exam Tip
बिक्री \(300,284,268,\ldots\) घटती समान्तर श्रेणी है और \(S_{13}=2652\)। परीक्षा में कम होती बिक्री में (d) ऋणात्मक रखें।
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एक दान केंद्र में पहले दिन (300) भोजन पैकेट बांटे गए और हर अगले दिन (10) पैकेट कम बांटे गए। (18) दिनों में कुल कितने पैकेट बांटे जाएंगे?
At a donation centre (300) food packets are distributed on the first day and (10) fewer packets are distributed each next day. How many packets are distributed in (18) days?
#ap
#word-problem
#food-packets
#total
A (3690)
B (3780)
C (3870)
D (3960)
Explanation opens after your attempt
Step 1
Concept
The packets form the decreasing AP \(300,290,280,\ldots\) and \(S_{18}=3870\). Exam tip: keep the common difference negative for decreasing quantities.
Step 2
Why this answer is correct
The correct answer is C. (3870). The packets form the decreasing AP \(300,290,280,\ldots\) and \(S_{18}=3870\). Exam tip: keep the common difference negative for decreasing quantities.
Step 3
Exam Tip
पैकेट \(300,290,280,\ldots\) घटती समान्तर श्रेणी हैं और \(S_{18}=3870\)। परीक्षा में घटती मात्रा में सार्व अंतर ऋणात्मक रखें।
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एक फंड में पहले सप्ताह (300) रुपये जमा हुए और हर अगले सप्ताह (45) रुपये अधिक जमा हुए। (16) सप्ताहों में कुल कितनी राशि जमा होगी?
A fund receives (300) rupees in the first week and (45) rupees more each next week. What is the total amount in (16) weeks?
#ap
#word-problem
#fund
#total
A (9900)
B (10200)
C (10500)
D (10800)
Explanation opens after your attempt
Correct Answer
B. (10200)
Step 1
Concept
The deposits are \(300,345,390,\ldots\) and \(S_{16}=10200\). Exam tip: treat weekly deposits as AP terms.
Step 2
Why this answer is correct
The correct answer is B. (10200). The deposits are \(300,345,390,\ldots\) and \(S_{16}=10200\). Exam tip: treat weekly deposits as AP terms.
Step 3
Exam Tip
जमा राशि \(300,345,390,\ldots\) है और \(S_{16}=10200\)। परीक्षा में साप्ताहिक जमा को ए.पी. के पद मानें।
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एक फैक्टरी पहले दिन (300) इकाइयां बनाती है और हर अगले दिन (20) इकाइयां कम बनाती है। पहले (12) दिनों में कुल उत्पादन कितना होगा?
A factory makes (300) units on the first day and (20) fewer units each next day. What is the total production in the first (12) days?
#ap
#word-problem
#factory
#decreasing
A (2160)
B (2220)
C (2250)
D (2280)
Explanation opens after your attempt
Step 1
Concept
The production is the decreasing AP \(300,280,260,\ldots\) and \(S_{12}=2280\). Exam tip: treat a decrease as a negative common difference.
Step 2
Why this answer is correct
The correct answer is D. (2280). The production is the decreasing AP \(300,280,260,\ldots\) and \(S_{12}=2280\). Exam tip: treat a decrease as a negative common difference.
Step 3
Exam Tip
उत्पादन \(300,280,260,\ldots\) घटती समान्तर श्रेणी है और \(S_{12}=2280\)। परीक्षा में कमी को ऋणात्मक सार्व अंतर मानें।
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एक स्कूल बस पहले दिन (40) किलोमीटर चली और (5) दिनों में कुल (300) किलोमीटर चली। यदि दूरी हर दिन समान रूप से बढ़ी तो दैनिक वृद्धि कितनी थी?
A school bus travelled (40) km on the first day and (300) km in (5) days. If the distance increased equally each day then what was the daily increase?
#ap
#word-problem
#bus-distance
A (8)
B (10)
C (12)
D (15)
Explanation opens after your attempt
Step 1
Concept
Using \(S_5=300\) and (a=40) gives (d=10). Exam tip: daily increase can be found from total distance.
Step 2
Why this answer is correct
The correct answer is B. (10). Using \(S_5=300\) and (a=40) gives (d=10). Exam tip: daily increase can be found from total distance.
Step 3
Exam Tip
\(S_5=300\) और (a=40) रखने पर (d=10) मिलता है। परीक्षा में कुल दूरी से दैनिक वृद्धि निकाली जा सकती है।
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एक बैंक योजना में पहले महीने (300) रुपये जमा होते हैं और हर अगले महीने (100) रुपये अधिक जमा होते हैं। (6)वें महीने कितनी राशि जमा होगी?
In a bank plan (300) rupees are deposited in the first month and (100) rupees more each next month. How much is deposited in the (6)th month?
#ap
#word-problem
#deposit
A (700) रुपये / (700) rupees
B (800) रुपये / (800) rupees
C (900) रुपये / (900) rupees
D (1000) रुपये / (1000) rupees
Explanation opens after your attempt
Correct Answer
B. (800) रुपये / (800) rupees
Step 1
Concept
The deposits form an AP. (a_6=300+5(100)=800).
Step 2
Why this answer is correct
The correct answer is B. (800) रुपये / (800) rupees. The deposits form an AP. (a_6=300+5(100)=800).
Step 3
Exam Tip
जमा राशि समान्तर श्रेणी है। (a_6=300+5(100)=800)।
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एक गाड़ी की सर्विस लागत पहले वर्ष (1200) रुपये है और हर अगले वर्ष (300) रुपये बढ़ती है। (6)वें वर्ष लागत कितनी होगी?
The service cost of a vehicle is (1200) rupees in the first year and increases by (300) rupees each next year. What is the cost in the (6)th year?
#ap
#word-problem
#cost
A (2400) रुपये
B (2700) रुपये
C (3000) रुपये
D (3300) रुपये
Explanation opens after your attempt
Correct Answer
B. (2700) रुपये
Step 1
Concept
The cost forms an AP. (a_6=1200+5(300)=2700).
Step 2
Why this answer is correct
The correct answer is B. (2700) रुपये. The cost forms an AP. (a_6=1200+5(300)=2700).
Step 3
Exam Tip
लागत समान्तर श्रेणी है। (a_6=1200+5(300)=2700)।
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समांतर श्रेढ़ी \(300,287,274,\ldots\) के पहले (35) पदों का योग ज्ञात कीजिए।
Find the sum of the first (35) terms of the AP \(300,287,274,\ldots\).
#decreasing ap
#negative difference
#sum
A (2715)
B (2735)
C (2755)
D (2765)
Explanation opens after your attempt
Step 1
Concept
Here (d=-13), and \(S_{35}=2765\). Do not forget the negative sign of the common difference in a decreasing AP.
Step 2
Why this answer is correct
The correct answer is D. (2765). Here (d=-13), and \(S_{35}=2765\). Do not forget the negative sign of the common difference in a decreasing AP.
Step 3
Exam Tip
यहाँ (d=-13) है और \(S_{35}=2765\) आता है। घटती श्रेढ़ी में सार्व अंतर का ऋणात्मक चिह्न न भूलें।
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किसी समांतर श्रेढ़ी के पहले पद और (60)वें पद का योग (300) है। (21)वें पद से (40)वें पद तक का योग ज्ञात कीजिए।
The sum of the first term and the (60)th term of an AP is (300). Find the sum from the (21)st term to the (40)th term.
#symmetric terms
#range sum
#ap
A (2900)
B (2950)
C (3000)
D (3050)
Explanation opens after your attempt
Step 1
Concept
\(a_{21}+a_{40}=a_1+a_{60}=300\), so the sum of (20) terms is (3000). Sums of symmetric terms are equal in an AP.
Step 2
Why this answer is correct
The correct answer is C. (3000). \(a_{21}+a_{40}=a_1+a_{60}=300\), so the sum of (20) terms is (3000). Sums of symmetric terms are equal in an AP.
Step 3
Exam Tip
\(a_{21}+a_{40}=a_1+a_{60}=300\), इसलिए (20) पदों का योग (3000) है। सममित पदों का योग बराबर होता है।
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(300) से (1200) तक उन सभी संख्याओं का योग ज्ञात कीजिए जो (18) से विभाज्य हैं लेकिन (24) से विभाज्य नहीं हैं।
Find the sum of all numbers from (300) to (1200) that are divisible by (18) but not by (24).
#lcm
#divisible not divisible
#ap
A (27918)
B (28098)
C (28458)
D (28278)
Explanation opens after your attempt
Correct Answer
D. (28278)
Step 1
Concept
Subtracting the sum of multiples of (72) from the sum of multiples of (18) gives (28278). Use the least common multiple to remove overlap.
Step 2
Why this answer is correct
The correct answer is D. (28278). Subtracting the sum of multiples of (72) from the sum of multiples of (18) gives (28278). Use the least common multiple to remove overlap.
Step 3
Exam Tip
(18) के गुणजों के योग से (72) के गुणजों का योग घटाने पर (28278) मिलता है। overlap हटाने के लिए लघुत्तम समापवर्त्य लें।
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(300) से कम (25) के सभी तीन अंकों वाले गुणजों का योग कितना है?
What is the sum of all three-digit multiples of (25) less than (300)?
#three_digit_numbers
#multiples
#ap_sum
A (1500)
B (1525)
C (1550)
D (1575)
Explanation opens after your attempt
Step 1
Concept
The multiples are \(100,125,\ldots,275\), and there are (8) terms, so the sum is (1500). Decide the first and last terms according to the limit.
Step 2
Why this answer is correct
The correct answer is A. (1500). The multiples are \(100,125,\ldots,275\), and there are (8) terms, so the sum is (1500). Decide the first and last terms according to the limit.
Step 3
Exam Tip
गुणज \(100,125,\ldots,275\) हैं और (8) पद हैं, इसलिए योग (1500) है। सीमा के अनुसार पहला और अंतिम पद तय करें।
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(120) और (300) के बीच (9) से विभाज्य संख्याओं का योग ज्ञात कीजिए।
Find the sum of the numbers divisible by (9) between (120) and (300).
#divisibility
#range
#ap_sum
A (4210)
B (4220)
C (4230)
D (4240)
Explanation opens after your attempt
Step 1
Concept
The numbers are \(126,135,\ldots,297\), and there are (20) terms, so the sum is (4230). In boundary questions, choose the first and last terms carefully.
Step 2
Why this answer is correct
The correct answer is C. (4230). The numbers are \(126,135,\ldots,297\), and there are (20) terms, so the sum is (4230). In boundary questions, choose the first and last terms carefully.
Step 3
Exam Tip
संख्याएँ \(126,135,\ldots,297\) हैं और (20) पद हैं, इसलिए योग (4230) है। सीमा वाले प्रश्न में पहला और अंतिम पद सावधानी से चुनें।
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एक बचत योजना में जमा राशि \(150,225,300,\ldots\) रुपये है। पहले (10) महीनों की कुल बचत कितनी होगी?
In a savings plan, the deposits are \(150,225,300,\ldots\) rupees. What is the total saving in the first (10) months?
#word_problem
#savings
#ap_sum
A (4750)
B (4875)
C (5000)
D (5125)
Explanation opens after your attempt
Step 1
Concept
The tenth deposit is (825) rupees, so the total is (S_{10}=\frac{10}{2}(150+825)=4875) rupees. Do not forget the unit in money problems.
Step 2
Why this answer is correct
The correct answer is B. (4875). The tenth deposit is (825) rupees, so the total is (S_{10}=\frac{10}{2}(150+825)=4875) rupees. Do not forget the unit in money problems.
Step 3
Exam Tip
दसवाँ जमा (825) रुपये है, इसलिए कुल (S_{10}=\frac{10}{2}(150+825)=4875) रुपये है। राशि वाले प्रश्न में इकाई न भूलें।
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एक बचत योजना में हर महीने जमा राशि \(200,250,300,\ldots\) रुपये है। पहले (8) महीनों की कुल राशि कितनी होगी?
In a savings plan, the monthly deposit is \(200,250,300,\ldots\) rupees. What is the total amount for the first (8) months?
#word_problem
#savings
#ap_sum
A (2900)
B (3000)
C (3100)
D (3200)
Explanation opens after your attempt
Step 1
Concept
Here (a=200), (d=50), and (n=8), so the total is (3000) rupees. In money questions, keep the unit in mind.
Step 2
Why this answer is correct
The correct answer is B. (3000). Here (a=200), (d=50), and (n=8), so the total is (3000) rupees. In money questions, keep the unit in mind.
Step 3
Exam Tip
यहाँ (a=200), (d=50), (n=8) है, इसलिए कुल (3000) रुपये होंगे। राशि वाले प्रश्न में इकाई भी लिखें।
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यदि \(a_n=15n-8\) है, तो \(a_{6k}-a_{2k}=300\) के लिए (k) क्या होगा?
If \(a_n=15n-8\), what is (k) for \(a_{6k}-a_{2k}=300\)?
#ap expert direct index
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
(a_{6k}-a_{2k}=(90k-8)-(30k-8)=60k). From (60k=300), (k=5).
Step 2
Why this answer is correct
The correct answer is B. (5). (a_{6k}-a_{2k}=(90k-8)-(30k-8)=60k). From (60k=300), (k=5).
Step 3
Exam Tip
(a_{6k}-a_{2k}=(90k-8)-(30k-8)=60k)। (60k=300) से (k=5)।
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एक समान्तर श्रेणी में \(a_4+a_{12}+a_{20}=300\) है। \(a_{12}\) का मान क्या होगा?
In an AP, \(a_4+a_{12}+a_{20}=300\). What is the value of \(a_{12}\)?
#ap expert average
A (90)
B (95)
C (100)
D (105)
Explanation opens after your attempt
Step 1
Concept
The three terms are equally spaced, so the middle term is the average. \(a_{12}=\frac{300}{3}=100\).
Step 2
Why this answer is correct
The correct answer is C. (100). The three terms are equally spaced, so the middle term is the average. \(a_{12}=\frac{300}{3}=100\).
Step 3
Exam Tip
तीनों पद समान दूरी पर हैं, इसलिए मध्य पद औसत होगा। \(a_{12}=\frac{300}{3}=100\)।
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समान्तर श्रेणी \(-38,-25,-12,\ldots\) में (300) से बड़ा पहला पद कौन-सा है?
In the AP \(-38,-25,-12,\ldots\), what is the first term greater than (300)?
#ap boundary negative start hard
A (300)
B (313)
C (326)
D (339)
Explanation opens after your attempt
Step 1
Concept
(a_n=-38+13(n-1)). The first term after (300) is (313).
Step 2
Why this answer is correct
The correct answer is B. (313). (a_n=-38+13(n-1)). The first term after (300) is (313).
Step 3
Exam Tip
(a_n=-38+13(n-1))। (300) के बाद आने वाला पहला पद (313) है।
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समान्तर श्रेणी \(11,19,27,\ldots\) में (300) से बड़ा पहला पद कौन-सा है?
What is the first term greater than (300) in the AP \(11,19,27,\ldots\)?
#ap-boundary-greater-hard
A (299)
B (307)
C (315)
D (323)
Explanation opens after your attempt
Step 1
Concept
(a_n=11+8(n-1)). The first term greater than (300) is (307) because the previous term is (299).
Step 2
Why this answer is correct
The correct answer is B. (307). (a_n=11+8(n-1)). The first term greater than (300) is (307) because the previous term is (299).
Step 3
Exam Tip
(a_n=11+8(n-1))। (300) से बड़ा पहला पद (307) है क्योंकि पिछला पद (299) है।
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समान्तर श्रेणी \(14,23,32,\ldots\) में (300) और (350) के बीच आने वाला सबसे बड़ा पद क्या है?
In the AP \(14,23,32,\ldots\), what is the greatest term between (300) and (350)?
#ap-range-hard
A (329)
B (338)
C (347)
D (356)
Explanation opens after your attempt
Step 1
Concept
The terms are of the form (14+9(n-1)). The greatest suitable term less than (350) is (347).
Step 2
Why this answer is correct
The correct answer is C. (347). The terms are of the form (14+9(n-1)). The greatest suitable term less than (350) is (347).
Step 3
Exam Tip
पद (14+9(n-1)) के रूप में हैं। (350) से कम सबसे बड़ा उपयुक्त पद (347) है।
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(300) से बड़े (8) के गुणजों की समान्तर श्रेणी \(304,312,320,\ldots\) है। इसका (25)वां पद क्या होगा?
The AP of multiples of (8) greater than (300) is \(304,312,320,\ldots\). What is its (25)th term?
#ap
#multiples
#nth-term
#class10
A (496)
B (488)
C (492)
D (500)
Explanation opens after your attempt
Step 1
Concept
Here (a=304) and (d=8) so \(a_{25}=304+24\times8=496\). Choose the first correct multiple after the limit.
Step 2
Why this answer is correct
The correct answer is A. (496). Here (a=304) and (d=8) so \(a_{25}=304+24\times8=496\). Choose the first correct multiple after the limit.
Step 3
Exam Tip
यहां (a=304) और (d=8) है इसलिए \(a_{25}=304+24\times8=496\)। सीमा के बाद पहला सही गुणज चुनें।
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एक दुकान में दो वस्तुओं के लिए (5x+9y=300) और (15x+27y=900) समीकरण बनते हैं। हलों की संख्या क्या होगी?
In a shop, the equations for two items are (5x+9y=300) and (15x+27y=900). How many solutions will there be?
#linear equations
#hard
#word problem
#infinite solutions
A कोई हल नहीं / No solution
B एक अद्वितीय हल / One unique solution
C अनंत हल / Infinitely many solutions
D दो हल / Two solutions
Explanation opens after your attempt
Correct Answer
C. अनंत हल / Infinitely many solutions
Step 1
Concept
The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.
Step 3
Exam Tip
दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं।
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एक कलम की कीमत (p) और एक कॉपी की कीमत (q) है। यदि (3p+4q=260) और (5p+2q=300), तो (q) का मान क्या है?
The price of one pen is (p) and one notebook is (q). If (3p+4q=260) and (5p+2q=300), what is the value of (q)?
#linear equations
#word problem
#price
#expert
#class 10
A \(q=\frac{180}{7}\)
B \(q=\frac{190}{7}\)
C \(q=\frac{200}{7}\)
D \(q=\frac{210}{7}\)
Explanation opens after your attempt
Correct Answer
C. \(q=\frac{200}{7}\)
Step 1
Concept
Elimination gives \(p=\frac{340}{7}\). Substituting it in either equation gives \(q=\frac{200}{7}\).
Step 2
Why this answer is correct
The correct answer is C. \(q=\frac{200}{7}\). Elimination gives \(p=\frac{340}{7}\). Substituting it in either equation gives \(q=\frac{200}{7}\).
Step 3
Exam Tip
विलोपन से \(p=\frac{340}{7}\) मिलता है। इसे किसी एक समीकरण में रखने पर \(q=\frac{200}{7}\)।
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संख्या रेखा पर \( \sqrt{300}-\sqrt{147} \) का सरल और सही मान कौन सा है?
What is the simplified correct value of \( \sqrt{300}-\sqrt{147} \) on the number line?
#number-line
#radical-difference
#simplification
A \(3\sqrt{3}\)
B \(7\sqrt{3}\)
C \( \sqrt{153} \)
D \(17\sqrt{3}\)
Explanation opens after your attempt
Correct Answer
A. \(3\sqrt{3}\)
Step 1
Concept
\( \sqrt{300}=10\sqrt{3} \) and \( \sqrt{147}=7\sqrt{3} \), so the difference is \(3\sqrt{3}\). Simplify the radicals first.
Step 2
Why this answer is correct
The correct answer is A. \(3\sqrt{3}\). \( \sqrt{300}=10\sqrt{3} \) and \( \sqrt{147}=7\sqrt{3} \), so the difference is \(3\sqrt{3}\). Simplify the radicals first.
Step 3
Exam Tip
\( \sqrt{300}=10\sqrt{3} \) और \( \sqrt{147}=7\sqrt{3} \), इसलिए अंतर \(3\sqrt{3}\) है। पहले मूलों को सरल करें।
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\(\frac{\sqrt{300}+\sqrt{192}-\sqrt{108}}{\sqrt{3}}\) का मान क्या है?
What is the value of \(\frac{\sqrt{300}+\sqrt{192}-\sqrt{108}}{\sqrt{3}}\)?
#radicals
#simplification
#real_numbers
A (8)
B (10)
C (12)
D (14)
Explanation opens after your attempt
Step 1
Concept
Here \(\sqrt{300}=10\sqrt{3}\), \(\sqrt{192}=8\sqrt{3}\), and \(\sqrt{108}=6\sqrt{3}\). The numerator is \(12\sqrt{3}\), so the value is (12).
Step 2
Why this answer is correct
The correct answer is C. (12). Here \(\sqrt{300}=10\sqrt{3}\), \(\sqrt{192}=8\sqrt{3}\), and \(\sqrt{108}=6\sqrt{3}\). The numerator is \(12\sqrt{3}\), so the value is (12).
Step 3
Exam Tip
\(\sqrt{300}=10\sqrt{3}\), \(\sqrt{192}=8\sqrt{3}\), और \(\sqrt{108}=6\sqrt{3}\)। अंश \(12\sqrt{3}\) है, इसलिए मान (12) है।
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एक बस (300) किमी जाती है। यदि चाल (10) किमी प्रति घंटा कम होती तो (1) घंटा अधिक लगता। वास्तविक चाल क्या है?
A bus travels (300) km. If its speed were (10) km per hour less, it would take (1) hour more. What is the actual speed?
#quadratic equations
#bus
#speed time distance
A (50) किमी प्रति घंटा / (50) km per hour
B (60) किमी प्रति घंटा / (60) km per hour
C (70) किमी प्रति घंटा / (70) km per hour
D (80) किमी प्रति घंटा / (80) km per hour
Explanation opens after your attempt
Correct Answer
B. (60) किमी प्रति घंटा / (60) km per hour
Step 1
Concept
Let the speed be (x). Then \(\frac{300}{x-10}-\frac{300}{x}=1\). This gives \(x^2-10x-3000=0\), so (x=60).
Step 2
Why this answer is correct
The correct answer is B. (60) किमी प्रति घंटा / (60) km per hour. Let the speed be (x). Then \(\frac{300}{x-10}-\frac{300}{x}=1\). This gives \(x^2-10x-3000=0\), so (x=60).
Step 3
Exam Tip
चाल (x) हो तो \(\frac{300}{x-10}-\frac{300}{x}=1\)। इससे \(x^2-10x-3000=0\) और (x=60) मिलता है।
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एक आयताकार पेज का क्षेत्रफल (300,सेमी\(^2) है और लंबाई चौड़ाई से (5\),सेमी) अधिक है। चौड़ाई क्या है?
A rectangular page has area (300,cm\(^2) and its length is (5\),cm) more than its breadth. What is the breadth?
#quadratic equations
#page area
#application
A (10,सेमी) / (10,cm)
B (12,सेमी) / (12,cm)
C (15,सेमी) / (15,cm)
D (20,सेमी) / (20,cm)
Explanation opens after your attempt
Correct Answer
C. (15,सेमी) / (15,cm)
Step 1
Concept
If breadth is (x), then (x(x+5)=300). This gives (x=15).
Step 2
Why this answer is correct
The correct answer is C. (15,सेमी) / (15,cm\(). If breadth is (x), then (x(x+5)=300). This gives (x=15).\)
Step 3
Exam Tip
यदि चौड़ाई (x) है तो (x(x+5)=300)। इससे (x=15) मिलता है।
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एक ट्रेन (300 km) दूरी तय करती है। यदि उसकी चाल (10 km/h) अधिक होती, तो समय (1 h) कम लगता। ट्रेन की वास्तविक चाल क्या थी?
A train covers a distance of (300 km). If its speed were (10 km/h) more, it would take (1 h) less. What was the actual speed of the train?
#quadratic equations
#speed time distance
#word problems
A \((40\text{ km\) / h})
B \((50\text{ km\) / h})
C \((60\text{ km\) / h})
D \((75\text{ km\) / h})
Explanation opens after your attempt
Correct Answer
B. \((50\text{ km\) / h})
Step 1
Concept
Let the actual speed be (x km/h\(), then (\frac{300}{x}-\frac{300}{x+10}=1). This gives (x^2+10x-3000=0), so the positive root is (x=50).\)
Step 2
Why this answer is correct
The correct answer is B. (50 km / h). Let the actual speed be (x km/h\(), then (\frac{300}{x}-\frac{300}{x+10}=1). This gives (x^2+10x-3000=0), so the positive root is (x=50).\)
Step 3
Exam Tip
वास्तविक चाल (x km/h) मानें, तब \(\frac{300}{x}-\frac{300}{x+10}=1\)। \(इससे (x^2+10x-3000=0), इसलिए धनात्मक मूल (x=50) है\)।
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एक आयताकार बगीचे की लंबाई चौड़ाई से (5 m) अधिक है और क्षेत्रफल \(300 m^2\) है। बगीचे की चौड़ाई क्या होगी?
The length of a rectangular garden is (5 m) more than its breadth and its area is (300 m\(^2). What is the breadth of the garden\)?
#quadratic equations
#word problems
#area
A (15 m)
B (20 m)
C (25 m)
D (30 m)
Explanation opens after your attempt
Step 1
Concept
Let the breadth be (x m\(), so (x(x+5)=300), giving (x=15). In exams, reject the negative dimension.\)
Step 2
Why this answer is correct
The correct answer is A. (15 m). Let the breadth be (x m\(), so (x(x+5)=300), giving (x=15). In exams, reject the negative dimension.\)
Step 3
Exam Tip
मान लें चौड़ाई (x m) है, तब (x(x+5)=300), इसलिए (x=15)। परीक्षा में ऋणात्मक माप को अस्वीकार करें।
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एक व्यक्ति (300) किलोमीटर यात्रा करता है। गति (10) किलोमीटर प्रति घंटा कम करने पर समय (1) घंटा बढ़ जाता है। मूल गति क्या है?
A person travels (300) kilometres. If the speed is reduced by (10) kilometres per hour, the time increases by (1) hour. What is the original speed?
#quadratic-equations
#word-problems
#speed-change
A (60)
B (50)
C (40)
D (30)
Explanation opens after your attempt
Step 1
Concept
Let the original speed be (x), then \(\frac{300}{x-10}-\frac{300}{x}=1\). Solving gives (x=60).
Step 2
Why this answer is correct
The correct answer is A. (60). Let the original speed be (x), then \(\frac{300}{x-10}-\frac{300}{x}=1\). Solving gives (x=60).
Step 3
Exam Tip
मूल गति (x) हो, तो \(\frac{300}{x-10}-\frac{300}{x}=1\)। हल करने पर (x=60) मिलता है।
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एक आयताकार कमरे का क्षेत्रफल (300) है और लंबाई चौड़ाई से (10) अधिक है। कमरे की चौड़ाई क्या है?
A rectangular room has area (300) and length (10) more than breadth. What is the breadth of the room?
#quadratic-equations
#word-problems
#room-area
A (15)
B (20)
C (25)
D (10)
Explanation opens after your attempt
Step 1
Concept
If the breadth is (x), then (x(x+10)=300). This gives (x=15).
Step 2
Why this answer is correct
The correct answer is A. (15). If the breadth is (x), then (x(x+10)=300). This gives (x=15).
Step 3
Exam Tip
यदि चौड़ाई (x) है, तो (x(x+10)=300)। इससे (x=15) मिलता है।
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एक ट्रेन (300) किलोमीटर दूरी तय करती है। गति (10) किलोमीटर प्रति घंटा बढ़ाने पर समय (1) घंटा कम हो जाता है। मूल गति क्या है?
A train covers (300) kilometres. If its speed is increased by (10) kilometres per hour, the time decreases by (1) hour. What is the original speed?
#quadratic-equations
#word-problems
#speed-time
A (50)
B (60)
C (40)
D (30)
Explanation opens after your attempt
Step 1
Concept
Let the original speed be (x), then \(\frac{300}{x}-\frac{300}{x+10}=1\). This gives (x=50).
Step 2
Why this answer is correct
The correct answer is A. (50). Let the original speed be (x), then \(\frac{300}{x}-\frac{300}{x+10}=1\). This gives (x=50).
Step 3
Exam Tip
मूल गति (x) हो, तो \(\frac{300}{x}-\frac{300}{x+10}=1\)। इससे (x=50) मिलता है।
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एक आयताकार चित्र की लंबाई चौड़ाई से (13) सेमी अधिक है और क्षेत्रफल (300) वर्ग सेमी है। लंबाई क्या है?
A rectangular picture has length (13) cm more than its breadth and area (300) square cm. What is its length?
#quadratic equations
#rectangle
#picture
A (12) सेमी / (12) cm
B (20) सेमी / (20) cm
C (25) सेमी / (25) cm
D (30) सेमी / (30) cm
Explanation opens after your attempt
Correct Answer
C. (25) सेमी / (25) cm
Step 1
Concept
(x(x+13)=300) gives breadth (12) and length (25). Choose the answer according to the part asked.
Step 2
Why this answer is correct
The correct answer is C. (25) सेमी / (25) cm. (x(x+13)=300) gives breadth (12) and length (25). Choose the answer according to the part asked.
Step 3
Exam Tip
(x(x+13)=300) से चौड़ाई (12) और लंबाई (25) मिलती है। उत्तर पूछे गए भाग के अनुसार चुनें।
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कौन सा विकल्प \(\sqrt{300}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{300}\)?
#surds
#simplification
#square-root
A \(10\sqrt{3}\)
B \(30\sqrt{10}\)
C \(5\sqrt{12}\)
D \(3\sqrt{100}\)
Explanation opens after your attempt
Correct Answer
A. \(10\sqrt{3}\)
Step 1
Concept
\(\sqrt{300}=\sqrt{100\times3}=10\sqrt{3}\). Take out the greatest perfect square.
Step 2
Why this answer is correct
The correct answer is A. \(10\sqrt{3}\). \(\sqrt{300}=\sqrt{100\times3}=10\sqrt{3}\). Take out the greatest perfect square.
Step 3
Exam Tip
\(\sqrt{300}=\sqrt{100\times3}=10\sqrt{3}\) है। सबसे बड़ा पूर्ण वर्ग बाहर निकालें।
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\(\frac{75}{300}\) के लिए सही विकल्प चुनिए।
Choose the correct option for \(\frac{75}{300}\).
#common error
#reduced form
#terminating decimals
A समाप्त दशमलव क्योंकि यह \(\frac{1}{4}\) के बराबर है / Terminating decimal because it equals \(\frac{1}{4}\)
B असमाप्त आवर्ती क्योंकि (300) में (3) है / Non-terminating recurring because (300) has (3)
C अपरिमेय संख्या / Irrational number
D असमाप्त अनावर्ती / Non-terminating non-recurring
Explanation opens after your attempt
Correct Answer
A. समाप्त दशमलव क्योंकि यह \(\frac{1}{4}\) के बराबर है / Terminating decimal because it equals \(\frac{1}{4}\)
Step 1
Concept
\(\frac{75}{300}=\frac{1}{4}\).
Step 2
Why this answer is correct
The reduced denominator is \(4=2^2\), so the decimal terminates.
Step 3
Exam Tip
Apply the rule to the reduced denominator, not the original one. चरण 1: \(\frac{75}{300}=\frac{1}{4}\) है। चरण 2: सरलतम हर \(4=2^2\) है, इसलिए दशमलव समाप्त होगा। चरण 3: मूल हर के बजाय घटे हुए हर पर नियम लगाइए।
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यदि (120), (180) और (300) का महत्तम समापवर्तक निकाला जाए, तो उसमें (2) की घात क्या होगी?
If the HCF of (120), (180), and (300) is found, what will be the power of (2) in it?
#real-numbers
#hcf
#prime-power
A (0)
B (1)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
Compare the powers of (2).
Step 2
Why this answer is correct
\(120=2^3\times3\times5\), \(180=2^2\times3^2\times5\), and \(300=2^2\times3\times5^2\), so the smallest power is (2).
Step 3
Exam Tip
HCF uses the smallest power. चरण 1: (2) की घातों की तुलना करें। चरण 2: \(120=2^3\times3\times5\), \(180=2^2\times3^2\times5\), \(300=2^2\times3\times5^2\), इसलिए सबसे छोटी घात (2) है। चरण 3: महत्तम समापवर्तक में छोटी घात आती है।
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\(\sqrt{75}+\sqrt{300}-\sqrt{48}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{75}+\sqrt{300}-\sqrt{48}\)?
#real-numbers
#radical-expression
#simplification
A \(9\sqrt{3}\)
B \(11\sqrt{3}\)
C \(7\sqrt{3}\)
D \(\sqrt{327}\)
Explanation opens after your attempt
Correct Answer
B. \(11\sqrt{3}\)
Step 1
Concept
\(\sqrt{75}=5\sqrt{3}\), \(\sqrt{300}=10\sqrt{3}\), and \(\sqrt{48}=4\sqrt{3}\).
Step 2
Why this answer is correct
\(5\sqrt{3}+10\sqrt{3}-4\sqrt{3}=11\sqrt{3}\).
Step 3
Exam Tip
Simplify all radicals before addition and subtraction. चरण 1: \(\sqrt{75}=5\sqrt{3}\), \(\sqrt{300}=10\sqrt{3}\), और \(\sqrt{48}=4\sqrt{3}\)। चरण 2: \(5\sqrt{3}+10\sqrt{3}-4\sqrt{3}=11\sqrt{3}\)। चरण 3: जोड़ और घटाव से पहले सभी वर्गमूलों को सरल करें।
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\(\sqrt{300}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{300}\)?
#real-numbers
#sqrt300
#radical-simplification
A \(10\sqrt{3}\)
B \(3\sqrt{10}\)
C \(30\sqrt{10}\)
D \(100\sqrt{3}\)
Explanation opens after your attempt
Correct Answer
A. \(10\sqrt{3}\)
Step 1
Concept
Write \(300=100 \times 3\).
Step 2
Why this answer is correct
\(\sqrt{300}=\sqrt{100 \times 3}=10\sqrt{3}\).
Step 3
Exam Tip
When you see a perfect square like (100), take it outside as (10). चरण 1: \(300=100 \times 3\) लिखें। चरण 2: \(\sqrt{300}=\sqrt{100 \times 3}=10\sqrt{3}\)। चरण 3: (100) जैसा पूर्ण वर्ग दिखे तो उसे बाहर (10) के रूप में निकालें।
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यदि दो संख्याओं का गुणनफल (2700) और लघुत्तम समापवर्त्य (300) है, तो उनका महत्तम समापवर्तक क्या होगा?
If the product of two numbers is (2700) and their LCM is (300), what will be their HCF?
#real-numbers
#hcf
#hcf-lcm-relation
A (6)
B (9)
C (12)
D (15)
Explanation opens after your attempt
Step 1
Concept
For two numbers, product (=) HCF \(\times\) LCM.
Step 2
Why this answer is correct
HCF \(=\frac{2700}{300}=9\).
Step 3
Exam Tip
You can check the answer using \(9\times300=2700\). चरण 1: दो संख्याओं के लिए गुणनफल (=) महत्तम समापवर्तक \(\times\) लघुत्तम समापवर्त्य। चरण 2: महत्तम समापवर्तक \(=\frac{2700}{300}=9\)। चरण 3: उत्तर को \(9\times300=2700\) से जांच सकते हैं।
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ओकिनावा में नागरिक मृत्यु और सैन्य प्रतिरोध ने युद्ध समाप्ति निर्णयों को किस तरह प्रभावित किया?
How did civilian deaths and military resistance at Okinawa affect war-ending decisions?
#world history
#world wars
#okinawa
#war ending
A उन्होंने जापान पर अंतिम आक्रमण की संभावित लागत को बहुत गंभीर दिखाया / They showed the possible cost of a final invasion of Japan as very serious
B उन्होंने जापान को पहले ही मित्र राष्ट्र बना दिया / They had already made Japan an Ally
C उन्होंने जर्मनी को प्रशांत में विजेता बनाया / They made Germany the Pacific victor
D उन्होंने संयुक्त राष्ट्र सेना भेजी / They sent a UN army
Explanation opens after your attempt
Correct Answer
A. उन्होंने जापान पर अंतिम आक्रमण की संभावित लागत को बहुत गंभीर दिखाया / They showed the possible cost of a final invasion of Japan as very serious
Step 1
Concept
Okinawa showed the human and military cost of the final war phase. For exams study causes of surrender with context.
Step 2
Why this answer is correct
The correct answer is A. उन्होंने जापान पर अंतिम आक्रमण की संभावित लागत को बहुत गंभीर दिखाया / They showed the possible cost of a final invasion of Japan as very serious. Okinawa showed the human and military cost of the final war phase. For exams study causes of surrender with context.
Step 3
Exam Tip
ओकिनावा ने अंतिम युद्ध चरण की मानवीय और सैन्य लागत दिखाई। परीक्षा में आत्मसमर्पण के कारणों को संदर्भ सहित पढ़ें।
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एक विद्यार्थी पहले महीने (40) पेज पढ़ता है और हर अगले महीने (20) पेज अधिक पढ़ता है। किस महीने वह (300) पेज पढ़ेगा?
A student reads (40) pages in the first month and (20) pages more each next month. In which month will the student read (300) pages?
#ap
#word-problem
#reading
#target-month
A (11)
B (12)
C (13)
D (14)
Explanation opens after your attempt
Step 1
Concept
From (40+(n-1)20=300), (n=14). Exam tip: set the target amount equal to \(a_n\).
Step 2
Why this answer is correct
The correct answer is D. (14). From (40+(n-1)20=300), (n=14). Exam tip: set the target amount equal to \(a_n\).
Step 3
Exam Tip
(40+(n-1)20=300) से (n=14) मिलता है। परीक्षा में लक्ष्य मात्रा को \(a_n\) के बराबर रखें।
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एक वस्तु की कीमत (₹x) है। (₹5) कम कीमत पर खरीदी जाए तो (₹300) में (3) वस्तुएँ अधिक मिलती हैं। मूल कीमत क्या है?
The price of an article is (₹x). If it is bought at (₹5) less, (3) more articles can be bought for (₹300). What is the original price?
#quadratic equations
#price quantity
#shopping
A (₹20)
B (₹25)
C (₹30)
D (₹35)
Explanation opens after your attempt
Step 1
Concept
Let original price be (x), then \(\frac{300}{x-5}-\frac{300}{x}=3\). This gives \(x^2-5x-500=0\), so (x=25).
Step 2
Why this answer is correct
The correct answer is B. (₹25). Let original price be (x), then \(\frac{300}{x-5}-\frac{300}{x}=3\). This gives \(x^2-5x-500=0\), so (x=25).
Step 3
Exam Tip
मूल कीमत (x) हो, तो \(\frac{300}{x-5}-\frac{300}{x}=3\)। इससे \(x^2-5x-500=0\), इसलिए (x=25)।
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