What is the value of (\frac{\sqrt{300}+\sqrt{192}-\sqrt{108}}{\sqrt{3}})?(\frac{\sqrt{300}+\sqrt{192}-\sqrt{108}}{\sqrt{3}}) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (12)(12)
Here (\sqrt{300}=10\sqrt{3}), (\sqrt{192}=8\sqrt{3}), and (\sqrt{108}=6\sqrt{3}). The numerator is (12\sqrt{3}), so the value is (12).(\sqrt{300}=10\sqrt{3}), (\sqrt{192}=8\sqrt{3}), और (\sqrt{108}=6\sqrt{3})। अंश (12\sqrt{3}) है, इसलिए मान (12) है।
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