In the AP (-38,-25,-12,\ldots), what is the first term greater than (300)?
Answer and explanation
Correct answer: 313
Here, the first term is \(a=-38\) and the common difference is \(d=13\). Thus, \(a_n=-38+13(n-1)=13n-51\). For \(a_n>300\), we get \(13n-51>300\), so \(n>27\). The least integer value is \(n=28\), and \(a_{28}=313\). Note that 300 is not itself a term of the AP, so 313 is the correct answer. Exam tip: for “greater than,” use \(>\) and then take the least possible integer value of \(n\).
Frequently asked questions
What is the correct answer to this question?
313
Why is this the correct answer?
Here, the first term is \(a=-38\) and the common difference is \(d=13\). Thus, \(a_n=-38+13(n-1)=13n-51\). For \(a_n>300\), we get \(13n-51>300\), so \(n>27\). The least integer value is \(n=28\), and \(a_{28}=313\). Note that 300 is not itself a term of the AP, so 313 is the correct answer. Exam tip: for “greater than,” use \(>\) and then take the least possible integer value of \(n\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
