The service cost of a vehicle is (1200) rupees in the first year and increases by (300) rupees each next year. What is the cost in the (6)th year?
Answer and explanation
Correct answer: ₹2,700
The costs form an arithmetic progression (AP) with first term \(a=1200\) and common difference \(d=300\). The cost in the sixth year is \(a_6=a+(6-1)d=1200+5\times300=2700\) rupees. Choosing \(3000\) would mean adding the increase 6 times, but there are only 5 increases after the first year. Exam tip: Use \(a_n=a+(n-1)d\) for the \(n\)th term.
Frequently asked questions
What is the correct answer to this question?
₹2,700
Why is this the correct answer?
The costs form an arithmetic progression (AP) with first term \(a=1200\) and common difference \(d=300\). The cost in the sixth year is \(a_6=a+(6-1)d=1200+5\times300=2700\) rupees. Choosing \(3000\) would mean adding the increase 6 times, but there are only 5 increases after the first year. Exam tip: Use \(a_n=a+(n-1)d\) for the \(n\)th term.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Word problems based on APs.
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