100 results found for "easy value" in Class 10.
यदि (x+y=13) और (x=9), तो (y) का सही मान चुनें।
If (x+y=13) and (x=9), choose the correct value of (y).
#linear equations
#substitution
#easy value
#easy
#class 10
A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
(9+y=13), so (y=4). After placing the given value, do simple subtraction.
Step 2
Why this answer is correct
The correct answer is C. (y=4). (9+y=13), so (y=4). After placing the given value, do simple subtraction.
Step 3
Exam Tip
(9+y=13), इसलिए (y=4)। दिए गए मान को रखने के बाद सरल घटाव करें।
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मान के अध्ययन में मध्यम मान की भूमिका क्या है?
What is the role of middle value in value study?
#middle value
#transition
#shading
A प्रकाश और छाया के बीच संक्रमण बनाना / Creating transition between light and shadow
B रंग का नाम बदलना / Changing colour name
C आकार मिटाना / Erasing shape
D कागज काटना / Cutting paper
Explanation opens after your attempt
Correct Answer
A. प्रकाश और छाया के बीच संक्रमण बनाना / Creating transition between light and shadow
Step 1
Concept
Middle value connects light and dark parts. Exam tip: connect mid value with transition.
Step 2
Why this answer is correct
The correct answer is A. प्रकाश और छाया के बीच संक्रमण बनाना / Creating transition between light and shadow. Middle value connects light and dark parts. Exam tip: connect mid value with transition.
Step 3
Exam Tip
मध्यम मान उजले और गहरे भागों को जोड़ता है। परीक्षा में mid value को transition से जोड़ें।
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यदि (x+2y=21) और (y=8), तो (x) का मान क्या होगा?
If (x+2y=21) and (y=8), what will be the value of (x)?
#linear equations
#substitution
#value of x
#easy
#class 10
A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
Putting (y=8) gives (x+16=21), so (x=5). Multiply first and then subtract.
Step 2
Why this answer is correct
The correct answer is C. (x=5). Putting (y=8) gives (x+16=21), so (x=5). Multiply first and then subtract.
Step 3
Exam Tip
(y=8) रखने पर (x+16=21), इसलिए (x=5)। पहले गुणा करें फिर घटाएं।
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समीकरणों (2x+5y=31) और (2x+y=15) से (y) का मान ज्ञात कीजिए।
Find the value of (y) from (2x+5y=31) and (2x+y=15).
#linear equations
#elimination
#value of y
#easy
#class 10
A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (4y=16), so (y=4). Subtract to remove equal (2x).
Step 2
Why this answer is correct
The correct answer is B. (y=4). Subtracting the second equation from the first gives (4y=16), so (y=4). Subtract to remove equal (2x).
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (4y=16), इसलिए (y=4)। समान (2x) को हटाने के लिए घटाएं।
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समीकरणों (5x+y=31) और (3x+y=19) से (x) का मान क्या है?
What is the value of (x) from (5x+y=31) and (3x+y=19)?
#linear equations
#elimination
#value of x
#easy
#class 10
A (x=6)
B (x=5)
C (x=4)
D (x=3)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (2x=12), so (x=6). Use elimination immediately on equal (y) terms.
Step 2
Why this answer is correct
The correct answer is A. (x=6). Subtracting the second equation from the first gives (2x=12), so (x=6). Use elimination immediately on equal (y) terms.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (2x=12), इसलिए (x=6)। समान (y) पदों पर विलोपन तुरंत करें।
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समीकरणों (4x-y=22) और (x-y=4) से (x) का मान ज्ञात कीजिए।
Find the value of (x) from (4x-y=22) and (x-y=4).
#linear equations
#elimination
#value of x
#easy
#class 10
A (x=6)
B (x=5)
C (x=4)
D (x=3)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (3x=18), so (x=6). Subtract to remove equal (-y) terms.
Step 2
Why this answer is correct
The correct answer is A. (x=6). Subtracting the second equation from the first gives (3x=18), so (x=6). Subtract to remove equal (-y) terms.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (3x=18), इसलिए (x=6)। समान (-y) हटाने के लिए घटाएं।
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यदि (x=14-3y) और (x+y=8), तो (y) का मान क्या है?
If (x=14-3y) and (x+y=8), what is the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
A (y=1)
B (y=2)
C (y=4)
D (y=3)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=14-3y) gives (14-2y=8), so (y=3). After substitution, keep variable terms on one side.
Step 2
Why this answer is correct
The correct answer is D. (y=3). Substituting (x=14-3y) gives (14-2y=8), so (y=3). After substitution, keep variable terms on one side.
Step 3
Exam Tip
(x=14-3y) रखने पर (14-2y=8), इसलिए (y=3)। प्रतिस्थापन के बाद चर वाले पद एक तरफ रखें।
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यदि (x-y=8) और (y=5), तो (x) का मान क्या है?
If (x-y=8) and (y=5), what is the value of (x)?
#linear equations
#substitution
#value of x
#easy
#class 10
A (x=13)
B (x=12)
C (x=11)
D (x=10)
Explanation opens after your attempt
Step 1
Concept
Putting (y=5) gives (x-5=8), so (x=13). Substitute the given value in the original equation.
Step 2
Why this answer is correct
The correct answer is A. (x=13). Putting (y=5) gives (x-5=8), so (x=13). Substitute the given value in the original equation.
Step 3
Exam Tip
(y=5) रखने पर (x-5=8), इसलिए (x=13)। दिए हुए मान को मूल समीकरण में रखें।
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समीकरणों (2x+3y=22) और (2x+y=12) से (y) का मान ज्ञात कीजिए।
Find the value of (y) from (2x+3y=22) and (2x+y=12).
#linear equations
#elimination
#value of y
#easy
#class 10
A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (2y=10), so (y=5). Eliminate the equal (2x) terms.
Step 2
Why this answer is correct
The correct answer is D. (y=5). Subtracting the second equation from the first gives (2y=10), so (y=5). Eliminate the equal (2x) terms.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (2y=10), इसलिए (y=5)। समान (2x) पदों को विलोपित करें।
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यदि (y=3x-2) और (x+y=18), तो (y) का मान क्या होगा?
If (y=3x-2) and (x+y=18), what will be the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
A (y=10)
B (y=11)
C (y=13)
D (y=15)
Explanation opens after your attempt
Step 1
Concept
Substituting (y=3x-2) gives (4x-2=18), so (x=5) and (y=13). Find (x) first, then use the expression for (y).
Step 2
Why this answer is correct
The correct answer is C. (y=13). Substituting (y=3x-2) gives (4x-2=18), so (x=5) and (y=13). Find (x) first, then use the expression for (y).
Step 3
Exam Tip
(y=3x-2) रखने पर (4x-2=18), इसलिए (x=5) और (y=13)। पहले (x) निकालें फिर (y) के रूप में रखें।
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यदि (x-2y=3) और (x+y=12), तो (y) का मान क्या है?
If (x-2y=3) and (x+y=12), what is the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=12-y) gives (12-y-2y=3), so (y=3). Simplify negative signs carefully in substitution.
Step 2
Why this answer is correct
The correct answer is B. (y=3). Substituting (x=12-y) gives (12-y-2y=3), so (y=3). Simplify negative signs carefully in substitution.
Step 3
Exam Tip
(x=12-y) रखने पर (12-y-2y=3), इसलिए (y=3)। प्रतिस्थापन में ऋण चिन्हों को ध्यान से सरल करें।
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समीकरणों (2x+y=17) और (2x-y=7) से (x) का मान ज्ञात कीजिए।
Find the value of (x) from (2x+y=17) and (2x-y=7).
#linear equations
#elimination
#value of x
#easy
#class 10
A (x=4)
B (x=5)
C (x=6)
D (x=7)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (4x=24), so (x=6). Add opposite (y) terms to eliminate them.
Step 2
Why this answer is correct
The correct answer is C. (x=6). Adding both equations gives (4x=24), so (x=6). Add opposite (y) terms to eliminate them.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (4x=24), इसलिए (x=6)। विपरीत (y) पदों को जोड़कर हटाएं।
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यदि (x+5y=32) और (x=7), तो (y) का मान क्या होगा?
If (x+5y=32) and (x=7), what will be the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
A (y=4)
B (y=5)
C (y=6)
D (y=7)
Explanation opens after your attempt
Step 1
Concept
Putting (x=7) gives (7+5y=32), so (y=5). After substituting the given value, divide carefully.
Step 2
Why this answer is correct
The correct answer is B. (y=5). Putting (x=7) gives (7+5y=32), so (y=5). After substituting the given value, divide carefully.
Step 3
Exam Tip
(x=7) रखने पर (7+5y=32), इसलिए (y=5)। दिए हुए मान को रखने के बाद भाग दें।
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समीकरणों (4x+2y=30) और (4x-y=12) से (y) का मान क्या है?
What is the value of (y) from (4x+2y=30) and (4x-y=12)?
#linear equations
#elimination
#value of y
#easy
#class 10
A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (3y=18), so (y=6). Subtraction is correct to remove equal (4x).
Step 2
Why this answer is correct
The correct answer is D. (y=6). Subtracting the second equation from the first gives (3y=18), so (y=6). Subtraction is correct to remove equal (4x).
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (3y=18), इसलिए (y=6)। समान (4x) को हटाने के लिए घटाना सही है।
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यदि (y=x-3) और (2x+y=15), तो (x) का मान क्या है?
If (y=x-3) and (2x+y=15), what is the value of (x)?
#linear equations
#substitution
#value of x
#easy
#class 10
A (x=4)
B (x=5)
C (x=6)
D (x=7)
Explanation opens after your attempt
Step 1
Concept
Substituting (y=x-3) gives (3x-3=15), so (x=6). After substitution, solve the equation in one variable.
Step 2
Why this answer is correct
The correct answer is C. (x=6). Substituting (y=x-3) gives (3x-3=15), so (x=6). After substitution, solve the equation in one variable.
Step 3
Exam Tip
(y=x-3) रखने पर (3x-3=15), इसलिए (x=6)। प्रतिस्थापन के बाद समीकरण को एक चर में हल करें।
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यदि (x=9-y) और (3x+y=19), तो (y) का मान क्या होगा?
If (x=9-y) and (3x+y=19), what will be the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
A (y=4)
B (y=5)
C (y=6)
D (y=7)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=9-y) gives (27-3y+y=19), so (y=4). Be careful while simplifying negative terms.
Step 2
Why this answer is correct
The correct answer is A. (y=4). Substituting (x=9-y) gives (27-3y+y=19), so (y=4). Be careful while simplifying negative terms.
Step 3
Exam Tip
(x=9-y) रखने पर (27-3y+y=19), इसलिए (y=4)। ऋण पदों को सरल करते समय सावधानी रखें।
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यदि (3x-y=10) और (x+y=10), तो (x) का मान क्या है?
If (3x-y=10) and (x+y=10), what is the value of (x)?
#linear equations
#elimination
#value of x
#easy
#class 10
A (x=4)
B (x=5)
C (x=6)
D (x=7)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (4x=20), so (x=5). Add opposite (y) terms to eliminate them.
Step 2
Why this answer is correct
The correct answer is B. (x=5). Adding both equations gives (4x=20), so (x=5). Add opposite (y) terms to eliminate them.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (4x=20), इसलिए (x=5)। विपरीत (y) पदों को जोड़कर हटाएं।
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समीकरणों (2x+3y=21) और (x+y=8) में (y) का मान क्या होगा?
In (2x+3y=21) and (x+y=8), what will be the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Using (x=8-y) gives (16-2y+3y=21), so (y=5). It is useful to isolate (x) from the smaller equation.
Step 2
Why this answer is correct
The correct answer is C. (y=5). Using (x=8-y) gives (16-2y+3y=21), so (y=5). It is useful to isolate (x) from the smaller equation.
Step 3
Exam Tip
(x=8-y) रखने पर (16-2y+3y=21), इसलिए (y=5)। छोटे समीकरण से (x) अलग करना उपयोगी है।
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समीकरणों (5x+y=29) और (2x+y=14) से (x) का मान क्या है?
What is the value of (x) from (5x+y=29) and (2x+y=14)?
#linear equations
#elimination
#value of x
#easy
#class 10
A (x=4)
B (x=5)
C (x=6)
D (x=7)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (3x=15), so (x=5). If (y) terms are equal, subtraction is the correct method.
Step 2
Why this answer is correct
The correct answer is B. (x=5). Subtracting the second equation from the first gives (3x=15), so (x=5). If (y) terms are equal, subtraction is the correct method.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (3x=15), इसलिए (x=5)। समान (y) हो तो घटाना सही तरीका है।
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यदि (x-y=7) और (x+y=15), तो (y) का मान क्या होगा?
If (x-y=7) and (x+y=15), what will be the value of (y)?
#linear equations
#elimination
#value of y
#easy
#class 10
A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (2x=22), so (x=11) and (y=4). After finding one variable, substitute it in a simple equation.
Step 2
Why this answer is correct
The correct answer is B. (y=4). Adding both equations gives (2x=22), so (x=11) and (y=4). After finding one variable, substitute it in a simple equation.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (2x=22), इसलिए (x=11) और (y=4)। एक चर मिलने के बाद उसे सरल समीकरण में रखें।
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समीकरणों (3x+y=18) और (x+y=10) से (x) का मान ज्ञात कीजिए।
Find the value of (x) from (3x+y=18) and (x+y=10).
#linear equations
#elimination
#value of x
#easy
#class 10
A (x=1)
B (x=2)
C (x=3)
D (x=4)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (2x=8), so (x=4). Remove equal (y) terms by subtraction.
Step 2
Why this answer is correct
The correct answer is D. (x=4). Subtracting the second equation from the first gives (2x=8), so (x=4). Remove equal (y) terms by subtraction.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (2x=8), इसलिए (x=4)। समान (y) पदों को घटाकर हटाएं।
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यदि (x+y=14) और (x=6), तो (y) का मान क्या है?
If (x+y=14) and (x=6), what is the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
A (y=6)
B (y=7)
C (y=8)
D (y=9)
Explanation opens after your attempt
Step 1
Concept
Putting (x=6) gives (6+y=14), so (y=8). In substitution, place the given value directly.
Step 2
Why this answer is correct
The correct answer is C. (y=8). Putting (x=6) gives (6+y=14), so (y=8). In substitution, place the given value directly.
Step 3
Exam Tip
(x=6) रखने पर (6+y=14), इसलिए (y=8)। प्रतिस्थापन में दिया हुआ मान सीधे रखें।
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यदि (y=10-x) और (x=4), तो (y) का मान क्या है?
If (y=10-x) and (x=4), what is the value of (y)?
#linear equations
#substitution
#value
#easy
#class 10
A (y=4)
B (y=5)
C (y=7)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
(y=10-4=6). In substitution, place the given value in the correct position.
Step 2
Why this answer is correct
The correct answer is D. (y=6). (y=10-4=6). In substitution, place the given value in the correct position.
Step 3
Exam Tip
(y=10-4=6)। प्रतिस्थापन में दिए गए मान को सही स्थान पर रखें।
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समीकरणों (x+2y=17) और (y=6) से (x) का मान ज्ञात कीजिए।
Find the value of (x) from (x+2y=17) and (y=6).
#linear equations
#substitution
#value of x
#easy
#class 10
A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
Putting (y=6) gives (x+12=17), so (x=5). The given value quickly gives the other variable.
Step 2
Why this answer is correct
The correct answer is C. (x=5). Putting (y=6) gives (x+12=17), so (x=5). The given value quickly gives the other variable.
Step 3
Exam Tip
(y=6) रखने पर (x+12=17), इसलिए (x=5)। सीधे दिए गए मान से दूसरा चर जल्दी मिलता है।
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समीकरणों (4x+y=21) और (2x+y=11) से (x) का मान ज्ञात कीजिए।
Find the value of (x) from (4x+y=21) and (2x+y=11).
#linear equations
#elimination
#value of x
#easy
#class 10
A (x=2)
B (x=3)
C (x=4)
D (x=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (2x=10), so (x=5). Remove equal (y) terms by subtraction.
Step 2
Why this answer is correct
The correct answer is D. (x=5). Subtracting the second equation from the first gives (2x=10), so (x=5). Remove equal (y) terms by subtraction.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (2x=10), इसलिए (x=5)। समान (y) पदों को घटाकर हटाएं।
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समीकरणों (3x+2y=22) और (x=4) में (y) का मान क्या है?
In the equations (3x+2y=22) and (x=4), what is the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Putting (x=4) gives (12+2y=22), so (y=5). Substitute the given value directly and simplify.
Step 2
Why this answer is correct
The correct answer is C. (y=5). Putting (x=4) gives (12+2y=22), so (y=5). Substitute the given value directly and simplify.
Step 3
Exam Tip
(x=4) रखने पर (12+2y=22), इसलिए (y=5)। दिए हुए मान को सीधे रखकर समीकरण सरल करें।
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समीकरण (x+y=10) और (y=6) से (x) का मान क्या होगा?
From (x+y=10) and (y=6), what is the value of (x)?
#linear equations
#substitution
#basic value
#easy
#class 10
A (x=2)
B (x=3)
C (x=4)
D (x=5)
Explanation opens after your attempt
Step 1
Concept
(x+6=10), so (x=4). In simple substitution, place the value directly.
Step 2
Why this answer is correct
The correct answer is C. (x=4). (x+6=10), so (x=4). In simple substitution, place the value directly.
Step 3
Exam Tip
(x+6=10), इसलिए (x=4)। सरल प्रतिस्थापन में मान सीधे रखें।
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यदि (2x+y=8) और (x=2), तो (y) का मान क्या होगा?
If (2x+y=8) and (x=2), what is the value of (y)?
#linear equations
#substitution
#value finding
#easy
#class 10
A (y=2)
B (y=4)
C (y=6)
D (y=8)
Explanation opens after your attempt
Step 1
Concept
Putting (x=2) gives (4+y=8), so (y=4). In exams, substitute the given value directly.
Step 2
Why this answer is correct
The correct answer is B. (y=4). Putting (x=2) gives (4+y=8), so (y=4). In exams, substitute the given value directly.
Step 3
Exam Tip
(x=2) रखने पर (4+y=8), इसलिए (y=4)। परीक्षा में दिए गए मान को सीधे समीकरण में रखें।
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समीकरणों (x=10-2y) और (x+y=7) में (y) का मान क्या होगा?
In (x=10-2y) and (x+y=7), what will be the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
A (y=1)
B (y=2)
C (y=3)
D (y=4)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=10-2y) gives (10-y=7), so (y=3). Combine like variable terms correctly.
Step 2
Why this answer is correct
The correct answer is C. (y=3). Substituting (x=10-2y) gives (10-y=7), so (y=3). Combine like variable terms correctly.
Step 3
Exam Tip
(x=10-2y) रखने पर (10-y=7), इसलिए (y=3)। समान चर वाले पदों को सही जोड़ें।
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यदि (3x-y=12) और (x+y=8), तो (x) का मान क्या है?
If (3x-y=12) and (x+y=8), what is the value of (x)?
#linear equations
#elimination
#value of x
#easy
#class 10
A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (4x=20), so (x=5). When (y) terms are opposite, addition is the fastest method.
Step 2
Why this answer is correct
The correct answer is C. (x=5). Adding both equations gives (4x=20), so (x=5). When (y) terms are opposite, addition is the fastest method.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (4x=20), इसलिए (x=5)। विपरीत (y) होने पर जोड़ना सबसे तेज तरीका है।
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यदि (x-y=5) और (y=2), तो (x) का मान क्या होगा?
If (x-y=5) and (y=2), what will be the value of (x)?
#linear equations
#substitution
#value of x
#easy
#class 10
A (x=5)
B (x=6)
C (x=7)
D (x=8)
Explanation opens after your attempt
Step 1
Concept
Putting (y=2) gives (x-2=5), so (x=7). Substitute the given value in the original equation.
Step 2
Why this answer is correct
The correct answer is C. (x=7). Putting (y=2) gives (x-2=5), so (x=7). Substitute the given value in the original equation.
Step 3
Exam Tip
(y=2) रखने पर (x-2=5), इसलिए (x=7)। दिए हुए मान को मूल समीकरण में रखें।
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समीकरणों (2x+3y=17) और (2x+y=9) से (y) का मान ज्ञात कीजिए।
Find the value of (y) from (2x+3y=17) and (2x+y=9).
#linear equations
#elimination
#value of y
#easy
#class 10
A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (2y=8), so (y=4). Eliminate the equal (2x) terms.
Step 2
Why this answer is correct
The correct answer is C. (y=4). Subtracting the second equation from the first gives (2y=8), so (y=4). Eliminate the equal (2x) terms.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (2y=8), इसलिए (y=4)। समान (2x) पदों को विलोपित करें।
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यदि (y=2x-1) और (x+y=8), तो (y) का मान क्या होगा?
If (y=2x-1) and (x+y=8), what will be the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Substitution gives (x+2x-1=8), so (x=3) and (y=5). Find (x) first, then use the expression for (y).
Step 2
Why this answer is correct
The correct answer is C. (y=5). Substitution gives (x+2x-1=8), so (x=3) and (y=5). Find (x) first, then use the expression for (y).
Step 3
Exam Tip
रखने पर (x+2x-1=8), इसलिए (x=3) और (y=5)। पहले (x) निकालें फिर (y) के सूत्र में रखें।
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समीकरणों (x-2y=1) और (x+y=10) में (y) का मान क्या है?
In the equations (x-2y=1) and (x+y=10), what is the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
From the second equation (x=10-y); substituting gives (10-y-2y=1), so (y=3). Watch brackets and signs in substitution.
Step 2
Why this answer is correct
The correct answer is B. (y=3). From the second equation (x=10-y); substituting gives (10-y-2y=1), so (y=3). Watch brackets and signs in substitution.
Step 3
Exam Tip
दूसरे से (x=10-y); रखने पर (10-y-2y=1), इसलिए (y=3)। प्रतिस्थापन में कोष्ठक और चिन्ह ध्यान रखें।
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यदि (2x+y=11) और (2x-y=5), तो (x) का मान क्या होगा?
If (2x+y=11) and (2x-y=5), what will be the value of (x)?
#linear equations
#elimination
#value of x
#easy
#class 10
A (x=2)
B (x=3)
C (x=4)
D (x=5)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (4x=16), so (x=4). Add opposite (y) terms to eliminate them.
Step 2
Why this answer is correct
The correct answer is C. (x=4). Adding both equations gives (4x=16), so (x=4). Add opposite (y) terms to eliminate them.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (4x=16), इसलिए (x=4)। विपरीत (y) पदों को जोड़कर हटाइए।
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समीकरणों (x+4y=18) और (x=2) से (y) का मान ज्ञात कीजिए।
Find the value of (y) from (x+4y=18) and (x=2).
#linear equations
#substitution
#value of y
#easy
#class 10
A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Putting (x=2) gives (2+4y=18), so (y=4). Do arithmetic carefully in simple substitution.
Step 2
Why this answer is correct
The correct answer is B. (y=4). Putting (x=2) gives (2+4y=18), so (y=4). Do arithmetic carefully in simple substitution.
Step 3
Exam Tip
(x=2) रखने पर (2+4y=18), इसलिए (y=4)। सरल प्रतिस्थापन में अंकगणित ध्यान से करें।
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यदि (3x+2y=16) और (3x-y=7), तो (y) का मान क्या है?
If (3x+2y=16) and (3x-y=7), what is the value of (y)?
#linear equations
#elimination
#value of y
#easy
#class 10
A (y=1)
B (y=2)
C (y=3)
D (y=4)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (3y=9), so (y=3). Subtract to remove the common (3x).
Step 2
Why this answer is correct
The correct answer is C. (y=3). Subtracting the second equation from the first gives (3y=9), so (y=3). Subtract to remove the common (3x).
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (3y=9), इसलिए (y=3)। समान (3x) को हटाने के लिए घटाइए।
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समीकरणों (y=x+4) और (2x+y=10) में (x) का मान क्या होगा?
In (y=x+4) and (2x+y=10), what will be the value of (x)?
#linear equations
#substitution
#value of x
#easy
#class 10
A (x=1)
B (x=2)
C (x=3)
D (x=4)
Explanation opens after your attempt
Step 1
Concept
Substituting (y=x+4) gives (3x+4=10), so (x=2). Combine like terms after substitution.
Step 2
Why this answer is correct
The correct answer is B. (x=2). Substituting (y=x+4) gives (3x+4=10), so (x=2). Combine like terms after substitution.
Step 3
Exam Tip
(y=x+4) रखने पर (3x+4=10), इसलिए (x=2)। प्रतिस्थापन के बाद समान पदों को जोड़ें।
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यदि (x+y=12) और (x=7), तो (y) का मान क्या है?
If (x+y=12) and (x=7), what is the value of (y)?
#linear equations
#substitution
#direct value
#easy
#class 10
A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Putting (x=7) gives (7+y=12), so (y=5). Use the given variable value directly.
Step 2
Why this answer is correct
The correct answer is C. (y=5). Putting (x=7) gives (7+y=12), so (y=5). Use the given variable value directly.
Step 3
Exam Tip
(x=7) रखने पर (7+y=12), इसलिए (y=5)। दिए हुए चर का मान सीधे प्रयोग करें।
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यदि (x=5-y) और (2x+y=8), तो (y) का मान क्या होगा?
If (x=5-y) and (2x+y=8), what will be the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
A (y=1)
B (y=2)
C (y=3)
D (y=4)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=5-y) gives (10-2y+y=8), so (y=2). Be careful while simplifying negative signs.
Step 2
Why this answer is correct
The correct answer is B. (y=2). Substituting (x=5-y) gives (10-2y+y=8), so (y=2). Be careful while simplifying negative signs.
Step 3
Exam Tip
(x=5-y) रखने पर (10-2y+y=8), इसलिए (y=2)। ऋण चिन्हों को सरल करते समय सावधानी रखें।
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समीकरणों (2x+y=9) और (x-y=3) में (y) का मान क्या है?
In the equations (2x+y=9) and (x-y=3), what is the value of (y)?
#linear equations
#elimination
#value of y
#easy
#class 10
A (y=1)
B (y=2)
C (y=3)
D (y=4)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (3x=12), so (x=4) and (y=1). Eliminate first, then find the other variable.
Step 2
Why this answer is correct
The correct answer is A. (y=1). Adding both equations gives (3x=12), so (x=4) and (y=1). Eliminate first, then find the other variable.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (3x=12), इसलिए (x=4) और (y=1)। पहले आसान विलोपन करें फिर दूसरा चर निकालें।
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यदि (x+y=6) और (3x-y=6), तो (x) का मान क्या होगा?
If (x+y=6) and (3x-y=6), what will be the value of (x)?
#linear equations
#elimination
#value of x
#easy
#class 10
A (x=1)
B (x=2)
C (x=3)
D (x=4)
Explanation opens after your attempt
Step 1
Concept
Adding the equations gives (4x=12), so (x=3). Remove (y) by adding when its signs are opposite.
Step 2
Why this answer is correct
The correct answer is C. (x=3). Adding the equations gives (4x=12), so (x=3). Remove (y) by adding when its signs are opposite.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (4x=12), इसलिए (x=3)। विपरीत चिन्ह वाले (y) को जोड़कर हटाइए।
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समीकरणों (4x+y=14) और (x+y=5) से (x) का मान ज्ञात कीजिए।
Find the value of (x) from (4x+y=14) and (x+y=5).
#linear equations
#elimination
#value of x
#easy
#class 10
A (x=2)
B (x=3)
C (x=4)
D (x=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (3x=9), so (x=3). Identify the common variable before subtracting.
Step 2
Why this answer is correct
The correct answer is B. (x=3). Subtracting the second equation from the first gives (3x=9), so (x=3). Identify the common variable before subtracting.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (3x=9), इसलिए (x=3)। घटाने से पहले समान चर को पहचानें।
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यदि (x=2y) और (x+y=9), तो (x) का मान क्या है?
If (x=2y) and (x+y=9), what is the value of (x)?
#linear equations
#substitution
#value of x
#easy
#class 10
A (x=3)
B (x=6)
C (x=9)
D (x=12)
Explanation opens after your attempt
Step 1
Concept
Using (x=2y) gives (2y+y=9), so (y=3) and (x=6). In substitution, form an equation in one variable.
Step 2
Why this answer is correct
The correct answer is B. (x=6). Using (x=2y) gives (2y+y=9), so (y=3) and (x=6). In substitution, form an equation in one variable.
Step 3
Exam Tip
(x=2y) रखने पर (2y+y=9), इसलिए (y=3) और (x=6)। प्रतिस्थापन में एक ही चर वाला समीकरण बनाइए।
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यदि (x-y=4) और (x+y=10), तो (y) का मान क्या होगा?
If (x-y=4) and (x+y=10), what will be the value of (y)?
#linear equations
#elimination
#value of y
#easy
#class 10
A (y=2)
B (y=3)
C (y=4)
D (y=7)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (2x=14), so (x=7) and (y=3). After finding one variable, substitute it in any equation.
Step 2
Why this answer is correct
The correct answer is B. (y=3). Adding both equations gives (2x=14), so (x=7) and (y=3). After finding one variable, substitute it in any equation.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (2x=14), इसलिए (x=7) और (y=3)। एक चर मिलने के बाद उसे किसी भी समीकरण में रखें।
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समीकरणों (3x+y=11) और (x+y=5) को विलोपन विधि से हल करने पर (x) का मान क्या है?
Using elimination method for (3x+y=11) and (x+y=5), what is the value of (x)?
#linear equations
#elimination
#value of x
#easy
#class 10
A (x=1)
B (x=2)
C (x=3)
D (x=4)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (2x=6), so (x=3). Subtract equal like terms when their signs are the same.
Step 2
Why this answer is correct
The correct answer is C. (x=3). Subtracting the second equation from the first gives (2x=6), so (x=3). Subtract equal like terms when their signs are the same.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (2x=6), इसलिए (x=3)। समान चिन्ह वाले समान चर को घटाना उपयोगी होता है।
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समीकरणों (2x+y=7) और (x=2) में (y) का मान क्या है?
In the equations (2x+y=7) and (x=2), what is the value of (y)?
#linear equations
#substitution
#value finding
#easy
#class 10
A (y=1)
B (y=2)
C (y=3)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Putting (x=2) gives (4+y=7), so (y=3). In substitution, place the given value directly.
Step 2
Why this answer is correct
The correct answer is C. (y=3). Putting (x=2) gives (4+y=7), so (y=3). In substitution, place the given value directly.
Step 3
Exam Tip
(x=2) रखने पर (4+y=7), इसलिए (y=3)। प्रतिस्थापन विधि में दिए मान को सीधे रखें।
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(p(x)=2x-2 -8) के लिए (p(2)) का मान क्या है?
For (p(x)=2x-2 -8), what is the value of (p(2))?
#polynomials
#value
#easy
#substitution
A (0)
B (2)
C (4)
D (8)
Explanation opens after your attempt
Step 1
Concept
(p(2)=2\cdot22 -8=8-8=0). Square first, then multiply.
Step 2
Why this answer is correct
The correct answer is A. (0). (p(2)=2\cdot22 -8=8-8=0). Square first, then multiply.
Step 3
Exam Tip
(p(2)=2\cdot22 -8=8-8=0) है। पहले वर्ग करें फिर गुणा करें।
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बहुपद \(x^3-1\) में (x=1) रखने पर मान क्या है?
What is the value of \(x^3-1\) when (x=1)?
#polynomials
#value
#zero
#easy
A (0)
B (1)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
\(1^3-1=0\). So (1) is also a zero of this polynomial.
Step 2
Why this answer is correct
The correct answer is A. (0). \(1^3-1=0\). So (1) is also a zero of this polynomial.
Step 3
Exam Tip
\(1^3-1=0\) है। इसलिए (1) इस बहुपद का शून्यक भी है।
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\(x^2+1\) में (x=1) रखने पर क्या मान मिलेगा?
What value is obtained by putting (x=1) in \(x^2+1\)?
#polynomials
#value
#easy
#substitution
A (0)
B (1)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
\(1^2+1=2\). Even for small values, calculate in the correct order.
Step 2
Why this answer is correct
The correct answer is C. (2). \(1^2+1=2\). Even for small values, calculate in the correct order.
Step 3
Exam Tip
\(1^2+1=2\) होता है। छोटे मानों पर भी सही क्रम से गणना करें।
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(p(x)=2x+3) में (p(2)) का मान क्या है?
If (p(x)=2x+3), what is the value of (p(2))?
#polynomials
#value
#easy
#substitution
A (5)
B (7)
C (9)
D (4)
Explanation opens after your attempt
Step 1
Concept
(p(2)=2\cdot2+3=7). Substitute the given number in place of (x).
Step 2
Why this answer is correct
The correct answer is B. (7). (p(2)=2\cdot2+3=7). Substitute the given number in place of (x).
Step 3
Exam Tip
(p(2)=2\cdot2+3=7) होता है। मान निकालते समय (x) की जगह दी गई संख्या रखें।
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यदि ग्राफ (x)-अक्ष को ((7,0)) पर काटता है, तो (p(7)) का मान क्या होगा?
If the graph cuts the (x)-axis at ((7,0)), what will be the value of (p(7))?
#p-value
#x-axis
#zeroes
#easy
A (0)
B (7)
C (-7)
D (1)
Explanation opens after your attempt
Step 1
Concept
On the (x)-axis, (y=0). Therefore at ((7,0)), (p(7)=0).
Step 2
Why this answer is correct
The correct answer is A. (0). On the (x)-axis, (y=0). Therefore at ((7,0)), (p(7)=0).
Step 3
Exam Tip
(x)-अक्ष पर (y=0) होता है। इसलिए ((7,0)) पर (p(7)=0) होगा।
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यदि (p(x)=2x+6), तो ग्राफ का (x)-अक्ष से कटाव किस (x)-मान पर होगा?
If (p(x)=2x+6), at which (x)-value will the graph cut the (x)-axis?
#linear-polynomial
#graphical-zero
#value-test
#easy
A (-3)
B (3)
C (6)
D (-6)
Explanation opens after your attempt
Step 1
Concept
On the (x)-axis, (p(x)=0), so (2x+6=0) gives (x=-3). This is the graphical zero.
Step 2
Why this answer is correct
The correct answer is A. (-3). On the (x)-axis, (p(x)=0), so (2x+6=0) gives (x=-3). This is the graphical zero.
Step 3
Exam Tip
(x)-अक्ष पर (p(x)=0), इसलिए (2x+6=0) से (x=-3)। यही ग्राफीय शून्यक है।
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यदि (p(-3)=0), तो बहुपद का कौन-सा शून्यक है?
If (p(-3)=0), which value is a zero of the polynomial?
#zero-definition
#function-value
#negative-zero
#easy
A (-3)
B (3)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
The (x)-value for which (p(x)=0) is a zero. Hence (-3) is a zero of the polynomial.
Step 2
Why this answer is correct
The correct answer is A. (-3). The (x)-value for which (p(x)=0) is a zero. Hence (-3) is a zero of the polynomial.
Step 3
Exam Tip
जिस (x)-मान पर (p(x)=0) हो वही शून्यक होता है। इसलिए (-3) बहुपद का शून्यक है।
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यदि ग्राफ (x)-अक्ष को ((8,0)) पर काटता है, तो (p(8)) का मान क्या होगा?
If the graph cuts the (x)-axis at ((8,0)), what is the value of (p(8))?
#function-value
#x-axis
#zeroes
#easy
A (0)
B (8)
C (-8)
D (1)
Explanation opens after your attempt
Step 1
Concept
On the (x)-axis, (y=0). Therefore at ((8,0)), (p(8)=0).
Step 2
Why this answer is correct
The correct answer is A. (0). On the (x)-axis, (y=0). Therefore at ((8,0)), (p(8)=0).
Step 3
Exam Tip
(x)-अक्ष पर (y=0) होता है। इसलिए ((8,0)) पर (p(8)=0) होगा।
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समीकरणों (x+2y=14) और (x=4) में (y) कितना है?
In the equations (x+2y=14) and (x=4), what is (y)?
#linear equations
#substitution
#easy value
#easy
#class 10
A (y=4)
B (y=5)
C (y=6)
D (y=7)
Explanation opens after your attempt
Step 1
Concept
Putting (x=4) gives (4+2y=14), so (y=5). When one variable is given, substitute immediately.
Step 2
Why this answer is correct
The correct answer is B. (y=5). Putting (x=4) gives (4+2y=14), so (y=5). When one variable is given, substitute immediately.
Step 3
Exam Tip
(x=4) रखने पर (4+2y=14), इसलिए (y=5)। जब एक चर दिया हो तो प्रतिस्थापन तुरंत करें।
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यदि मान पट्टी में मध्य मान नहीं है तो छायांकन पर क्या असर होगा?
If a value scale has no middle values what effect will it have on shading?
#value scale
#middle value
#shading
A प्रकाश से छाया का संक्रमण कठोर लगेगा / Transition from light to shadow will look harsh
B छाया अधिक कोमल होगी / Shadow will become softer
C रंगत्व बढ़ेगा / Hue will increase
D बनावट वास्तविक होगी / Texture will become actual
Explanation opens after your attempt
Correct Answer
A. प्रकाश से छाया का संक्रमण कठोर लगेगा / Transition from light to shadow will look harsh
Step 1
Concept
Middle values create smooth transition. Exam tip: keep full range in value scale.
Step 2
Why this answer is correct
The correct answer is A. प्रकाश से छाया का संक्रमण कठोर लगेगा / Transition from light to shadow will look harsh. Middle values create smooth transition. Exam tip: keep full range in value scale.
Step 3
Exam Tip
मध्य मान smooth transition बनाते हैं। परीक्षा में value scale में full range रखें।
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छाया को अधिक गहरा दिखाने के लिए किस मान का उपयोग होगा?
Which value will be used to make shadow look darker?
#dark value
#shadow
#value
A हल्का मान / Light value
B गहरा मान / Dark value
C रंगत्व / Hue
D सकारात्मक स्थान / Positive space
Explanation opens after your attempt
Correct Answer
B. गहरा मान / Dark value
Step 1
Concept
Dark value increases the effect of shadow. Exam tip: connect shadow with dark value.
Step 2
Why this answer is correct
The correct answer is B. गहरा मान / Dark value. Dark value increases the effect of shadow. Exam tip: connect shadow with dark value.
Step 3
Exam Tip
गहरा मान छाया का प्रभाव बढ़ाता है। परीक्षा में shadow को dark value से जोड़ें।
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प्रकाश पड़ने वाले भाग को दिखाने के लिए कौन सा मान चाहिए?
Which value is needed to show the lighted part?
#light value
#highlight
#value
A गहरा मान / Dark value
B मध्यम अंधेरा / Medium dark
C हल्का मान / Light value
D काली रेखा / Black line
Explanation opens after your attempt
Correct Answer
C. हल्का मान / Light value
Step 1
Concept
Light value shows the lit part. Exam tip: connect highlight with light value.
Step 2
Why this answer is correct
The correct answer is C. हल्का मान / Light value. Light value shows the lit part. Exam tip: connect highlight with light value.
Step 3
Exam Tip
हल्का मान प्रकाश वाले भाग को दिखाता है। परीक्षा में प्रकाशित भाग को हल्का मान से जोड़ें।
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यदि (a=12), (d=5) और (n=6) हो तो \(a_n\) का मान क्या होगा?
If (a=12), (d=5), and (n=6), what is the value of \(a_n\)?
#ap
#nth-term
#easy
#class10
A (32)
B (35)
C (37)
D (42)
Explanation opens after your attempt
Step 1
Concept
(a_n=12+(6-1)\times5=37). Substituting values directly reduces mistakes.
Step 2
Why this answer is correct
The correct answer is C. (37). (a_n=12+(6-1)\times5=37). Substituting values directly reduces mistakes.
Step 3
Exam Tip
(a_n=12+(6-1)\times5=37)। सूत्र में सीधे मान रखने से गलती कम होती है।
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अनुक्रम \(11,14,17,20,\ldots\) में (a) का मान क्या है?
What is the value of (a) in the sequence \(11,14,17,20,\ldots\)?
#ap
#first term
#notation
#easy
A (3)
B (11)
C (14)
D (20)
Explanation opens after your attempt
Step 1
Concept
The first term is (11), so (a=11). For (a), look at the first term of the list.
Step 2
Why this answer is correct
The correct answer is B. (11). The first term is (11), so (a=11). For (a), look at the first term of the list.
Step 3
Exam Tip
पहला पद (11) है इसलिए (a=11) है। (a) के लिए सूची का पहला पद देखें।
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यदि (3x-2y=4) और (x=4), तो (y) का मान क्या है?
If (3x-2y=4) and (x=4), what is the value of (y)?
#linear equations
#substitution
#negative coefficient
#easy
#class 10
A (y=1)
B (y=2)
C (y=3)
D (y=4)
Explanation opens after your attempt
Step 1
Concept
Putting (x=4) gives (12-2y=4), so (y=4). Check signs while solving a term with a negative coefficient.
Step 2
Why this answer is correct
The correct answer is D. (y=4). Putting (x=4) gives (12-2y=4), so (y=4). Check signs while solving a term with a negative coefficient.
Step 3
Exam Tip
(x=4) रखने पर (12-2y=4), इसलिए (y=4)। ऋण गुणांक वाले पद को हल करते समय चिन्ह जांचें।
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दो संख्याओं (x) और (y) का योग (20) है और (y=8), तो (x) का मान क्या होगा?
The sum of two numbers (x) and (y) is (20), and (y=8). What will be the value of (x)?
#linear equations
#word problem
#substitution
#easy
#class 10
A (x=10)
B (x=12)
C (x=14)
D (x=16)
Explanation opens after your attempt
Step 1
Concept
Putting (y=8) in (x+y=20) gives (x=12). First write the equation clearly from the words.
Step 2
Why this answer is correct
The correct answer is B. (x=12). Putting (y=8) in (x+y=20) gives (x=12). First write the equation clearly from the words.
Step 3
Exam Tip
समीकरण (x+y=20) में (y=8) रखने पर (x=12)। शब्दों से बने समीकरण को पहले साफ लिखें।
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यदि (3x-y=18) और (x=7), तो (y) का मान क्या होगा?
If (3x-y=18) and (x=7), what will be the value of (y)?
#linear equations
#substitution
#negative variable
#easy
#class 10
A (y=1)
B (y=2)
C (y=3)
D (y=4)
Explanation opens after your attempt
Step 1
Concept
Putting (x=7) gives (21-y=18), so (y=3). Watch the signs while solving a negative variable.
Step 2
Why this answer is correct
The correct answer is C. (y=3). Putting (x=7) gives (21-y=18), so (y=3). Watch the signs while solving a negative variable.
Step 3
Exam Tip
(x=7) रखने पर (21-y=18), इसलिए (y=3)। ऋण चर को हल करते समय चिन्हों का ध्यान रखें।
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दो संख्याओं (x) और (y) का योग (18) है और (y=7), तो (x) का मान क्या है?
The sum of two numbers (x) and (y) is (18), and (y=7). What is the value of (x)?
#linear equations
#word problem
#substitution
#easy
#class 10
A (x=8)
B (x=9)
C (x=10)
D (x=11)
Explanation opens after your attempt
Step 1
Concept
Putting (y=7) in (x+y=18) gives (x=11). In word problems, form the equation first.
Step 2
Why this answer is correct
The correct answer is D. (x=11). Putting (y=7) in (x+y=18) gives (x=11). In word problems, form the equation first.
Step 3
Exam Tip
समीकरण (x+y=18) में (y=7) रखने पर (x=11)। शब्द प्रश्न में पहले समीकरण बनाएं।
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समीकरणों (6x-y=23) और (2x-y=7) से (x) का मान ज्ञात कीजिए।
Find the value of (x) from (6x-y=23) and (2x-y=7).
#linear equations
#elimination
#subtract equations
#easy
#class 10
A (x=2)
B (x=3)
C (x=4)
D (x=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (4x=16), so (x=4). Equal (-y) terms can be removed by subtraction.
Step 2
Why this answer is correct
The correct answer is C. (x=4). Subtracting the second equation from the first gives (4x=16), so (x=4). Equal (-y) terms can be removed by subtraction.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (4x=16), इसलिए (x=4)। समान (-y) पदों को घटाकर हटाया जा सकता है।
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यदि (x-3y=1) और (y=2), तो (x) का मान क्या है?
If (x-3y=1) and (y=2), what is the value of (x)?
#linear equations
#substitution
#find x
#easy
#class 10
A (x=5)
B (x=6)
C (x=8)
D (x=7)
Explanation opens after your attempt
Step 1
Concept
(x-6=1), so (x=7). After substitution, move the constant term to the other side.
Step 2
Why this answer is correct
The correct answer is D. (x=7). (x-6=1), so (x=7). After substitution, move the constant term to the other side.
Step 3
Exam Tip
(x-6=1), इसलिए (x=7)। प्रतिस्थापन के बाद स्थिर पद को दूसरी तरफ ले जाएँ।
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यदि (2x-3y=1) और (x=5), तो (y) का मान क्या है?
If (2x-3y=1) and (x=5), what is the value of (y)?
#linear equations
#substitution
#negative term
#easy
#class 10
A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Putting (x=5) gives (10-3y=1), so (y=3). Watch the signs while solving a negative term.
Step 2
Why this answer is correct
The correct answer is A. (y=3). Putting (x=5) gives (10-3y=1), so (y=3). Watch the signs while solving a negative term.
Step 3
Exam Tip
(x=5) रखने पर (10-3y=1), इसलिए (y=3)। ऋण पद को हल करते समय चिन्हों का ध्यान रखें।
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यदि (3x+2y=17) और (x=3), तो (y) का मान क्या है?
If (3x+2y=17) and (x=3), what is the value of (y)?
#linear equations
#substitution
#two step
#easy
#class 10
A (y=2)
B (y=4)
C (y=6)
D (y=8)
Explanation opens after your attempt
Step 1
Concept
(9+2y=17), so (2y=8) and (y=4). Multiply first and then divide.
Step 2
Why this answer is correct
The correct answer is B. (y=4). (9+2y=17), so (2y=8) and (y=4). Multiply first and then divide.
Step 3
Exam Tip
(9+2y=17), इसलिए (2y=8) और (y=4)। पहले गुणा करें फिर भाग दें।
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यदि (x-y=6) और (y=2), तो (x) का मान क्या होगा?
If (x-y=6) and (y=2), what is the value of (x)?
#linear equations
#substitution
#minus equation
#easy
#class 10
A (x=6)
B (x=7)
C (x=8)
D (x=9)
Explanation opens after your attempt
Step 1
Concept
(x-2=6), so (x=8). Put (y) with the correct sign in a subtraction equation.
Step 2
Why this answer is correct
The correct answer is C. (x=8). (x-2=6), so (x=8). Put (y) with the correct sign in a subtraction equation.
Step 3
Exam Tip
(x-2=6), इसलिए (x=8)। घटाव समीकरण में (y) को सही चिह्न के साथ रखें।
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विलोपन विधि से (x+4y=17) और (x+y=8) को घटाने पर (y) का मान क्या मिलेगा?
Using elimination, what value of (y) is obtained by subtracting (x+y=8) from (x+4y=17)?
#linear equations
#elimination
#subtract
#easy
#class 10
A (y=2)
B (y=4)
C (y=3)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting gives (3y=9), so (y=3). Remove equal (x) terms to get (y) directly.
Step 2
Why this answer is correct
The correct answer is C. (y=3). Subtracting gives (3y=9), so (y=3). Remove equal (x) terms to get (y) directly.
Step 3
Exam Tip
घटाने पर (3y=9), इसलिए (y=3)। समान (x) पदों को हटाकर सीधे (y) निकालें।
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समीकरण (x-y=2) और (x=6) में (y) का मान क्या है?
In (x-y=2) and (x=6), what is the value of (y)?
#linear equations
#substitution
#negative term
#easy
#class 10
A (y=2)
B (y=4)
C (y=6)
D (y=8)
Explanation opens after your attempt
Step 1
Concept
(6-y=2), so (y=4). Do not rush when solving a term with a negative sign.
Step 2
Why this answer is correct
The correct answer is B. (y=4). (6-y=2), so (y=4). Do not rush when solving a term with a negative sign.
Step 3
Exam Tip
(6-y=2), इसलिए (y=4)। ऋण वाले पद को हल करते समय जल्दबाजी न करें।
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यदि (2x-y=5) और (x=4), तो (y) का मान ज्ञात करें।
If (2x-y=5) and (x=4), find the value of (y).
#linear equations
#substitution
#minus sign
#easy
#class 10
A (y=1)
B (y=3)
C (y=5)
D (y=7)
Explanation opens after your attempt
Step 1
Concept
(8-y=5), so (y=3). When there is a minus sign, balance both sides carefully.
Step 2
Why this answer is correct
The correct answer is B. (y=3). (8-y=5), so (y=3). When there is a minus sign, balance both sides carefully.
Step 3
Exam Tip
(8-y=5), इसलिए (y=3)। समीकरण में ऋण चिह्न हो तो दोनों पक्षों को ध्यान से संतुलित करें।
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समीकरण (x+2y=12) और (x=4) के लिए (y) का मान चुनें।
For the equations (x+2y=12) and (x=4), choose the value of (y).
#linear equations
#substitution
#one variable
#easy
#class 10
A (y=2)
B (y=4)
C (y=6)
D (y=8)
Explanation opens after your attempt
Step 1
Concept
(4+2y=12), so (2y=8) and (y=4). Apply the same operation on both sides.
Step 2
Why this answer is correct
The correct answer is B. (y=4). (4+2y=12), so (2y=8) and (y=4). Apply the same operation on both sides.
Step 3
Exam Tip
(4+2y=12), इसलिए (2y=8) और (y=4)। परीक्षा में दोनों तरफ बराबर क्रिया करें।
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यदि (x+y=9) और (y=4), तो (x) का मान क्या है?
If (x+y=9) and (y=4), what is the value of (x)?
#linear equations
#substitution
#basic
#easy
#class 10
A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
Putting (y=4) gives (x+4=9), so (x=5). After substitution, use simple subtraction carefully.
Step 2
Why this answer is correct
The correct answer is C. (x=5). Putting (y=4) gives (x+4=9), so (x=5). After substitution, use simple subtraction carefully.
Step 3
Exam Tip
(y=4) रखने पर (x+4=9), इसलिए (x=5)। परीक्षा में प्रतिस्थापन के बाद सरल घटाव करें।
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यदि (2x-y=8) और (x=5), तो (y) का मान क्या है?
If (2x-y=8) and (x=5), what is the value of (y)?
#linear equations
#substitution
#negative variable
#easy
#class 10
A (y=1)
B (y=2)
C (y=3)
D (y=4)
Explanation opens after your attempt
Step 1
Concept
Putting (x=5) gives (10-y=8), so (y=2). Change the sign correctly when moving a negative variable.
Step 2
Why this answer is correct
The correct answer is B. (y=2). Putting (x=5) gives (10-y=8), so (y=2). Change the sign correctly when moving a negative variable.
Step 3
Exam Tip
(x=5) रखने पर (10-y=8), इसलिए (y=2)। ऋण चर को दूसरी तरफ ले जाते समय चिन्ह बदलें।
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यदि (3x+y=19) और (x+y=9), तो (x+y) का मान क्या है?
If (3x+y=19) and (x+y=9), what is the value of (x+y)?
#linear equations
#direct observation
#easy
#class 10
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
The second equation directly states (x+y=9). In exams, read the given equations carefully.
Step 2
Why this answer is correct
The correct answer is B. (9). The second equation directly states (x+y=9). In exams, read the given equations carefully.
Step 3
Exam Tip
दूसरा समीकरण सीधे (x+y=9) बताता है। परीक्षा में दिए हुए समीकरण को भी ध्यान से पढ़ें।
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यदि (4x+2y=20) और (x+y=7), तो (x) का मान क्या है?
If (4x+2y=20) and (x+y=7), what is the value of (x)?
#linear equations
#elimination
#simplify first
#easy
#class 10
A (x=1)
B (x=2)
C (x=3)
D (x=4)
Explanation opens after your attempt
Step 1
Concept
The first equation becomes (2x+y=10); subtracting (x+y=7) gives (x=3). Divide by common factors first.
Step 2
Why this answer is correct
The correct answer is C. (x=3). The first equation becomes (2x+y=10); subtracting (x+y=7) gives (x=3). Divide by common factors first.
Step 3
Exam Tip
पहला समीकरण (2x+y=10) बनता है; इससे (x+y=7) घटाने पर (x=3)। पहले सामान्य गुणनखंड से भाग दें।
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समीकरणों (5x-y=9) और (2x-y=3) से (x) का मान ज्ञात कीजिए।
Find the value of (x) from (5x-y=9) and (2x-y=3).
#linear equations
#elimination
#subtract equations
#easy
#class 10
A (x=1)
B (x=2)
C (x=3)
D (x=4)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (3x=6), so (x=2). Equal (y) terms can be removed by subtraction.
Step 2
Why this answer is correct
The correct answer is B. (x=2). Subtracting the second equation from the first gives (3x=6), so (x=2). Equal (y) terms can be removed by subtraction.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (3x=6), इसलिए (x=2)। समान (y) पदों को घटाकर हटाया जा सकता है।
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यदि दो रेखाएँ ( (5,2) ) पर कटती हैं, तो (y) का मान क्या होगा?
If two lines intersect at ( (5,2) ), what will be the value of (y)?
#linear equations
#coordinates
#solution from graph
#easy
A (2)
B (5)
C (7)
D (0)
Explanation opens after your attempt
Step 1
Concept
In the point ( (5,2) ), the second coordinate is (y). Therefore, (y=2).
Step 2
Why this answer is correct
The correct answer is A. (2). In the point ( (5,2) ), the second coordinate is (y). Therefore, (y=2).
Step 3
Exam Tip
बिंदु ( (5,2) ) में दूसरा निर्देशांक (y) होता है। इसलिए (y=2)।
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यदि दो रेखाएँ ( (1,2) ) पर मिलती हैं, तो (x) का मान क्या है?
If two lines meet at ( (1,2) ), what is the value of (x)?
#linear equations
#coordinates
#graph reading
#easy
A (1)
B (2)
C (3)
D (0)
Explanation opens after your attempt
Step 1
Concept
In the point ( (1,2) ), the first coordinate is (x). Therefore, (x=1).
Step 2
Why this answer is correct
The correct answer is A. (1). In the point ( (1,2) ), the first coordinate is (x). Therefore, (x=1).
Step 3
Exam Tip
बिंदु ( (1,2) ) में पहला निर्देशांक (x) होता है। इसलिए (x=1)।
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समीकरण (3x+y=9) के लिए (x=2) होने पर (y) का मान क्या है?
For (3x+y=9), what is the value of (y) when (x=2)?
#linear equations
#table of values
#graph plotting
#easy
A (3)
B (6)
C (9)
D (1)
Explanation opens after your attempt
Step 1
Concept
(3(2)+y=9), so (6+y=9) and (y=3). While making a table, choose simple (x)-values.
Step 2
Why this answer is correct
The correct answer is A. (3). (3(2)+y=9), so (6+y=9) and (y=3). While making a table, choose simple (x)-values.
Step 3
Exam Tip
(3(2)+y=9), इसलिए (6+y=9) और (y=3)। तालिका बनाते समय ऐसे सरल (x) मान चुनें।
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रेखा (x+2y=8) पर (y=0) रखने पर (x) का मान क्या होगा?
For the line (x+2y=8), what is the value of (x) when (y=0)?
#linear equations
#x intercept
#graphical method
#easy
A (8)
B (4)
C (2)
D (0)
Explanation opens after your attempt
Step 1
Concept
Putting (y=0) gives (x+2(0)=8), so (x=8). Finding intercepts helps in drawing the graph.
Step 2
Why this answer is correct
The correct answer is A. (8). Putting (y=0) gives (x+2(0)=8), so (x=8). Finding intercepts helps in drawing the graph.
Step 3
Exam Tip
(y=0) रखने पर (x+2(0)=8), इसलिए (x=8)। अक्ष-अवरोध निकालना ग्राफ बनाने में सहायक होता है।
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रेखा (2x+y=6) पर (x=0) रखने पर (y) का मान क्या होगा?
For the line (2x+y=6), what is the value of (y) when (x=0)?
#linear equations
#table values
#graph plotting
#easy
A (6)
B (3)
C (2)
D (0)
Explanation opens after your attempt
Step 1
Concept
Putting (x=0) gives (2(0)+y=6), so (y=6). For drawing a graph, first find such easy values.
Step 2
Why this answer is correct
The correct answer is A. (6). Putting (x=0) gives (2(0)+y=6), so (y=6). For drawing a graph, first find such easy values.
Step 3
Exam Tip
(x=0) रखने पर (2(0)+y=6), इसलिए (y=6)। ग्राफ बनाने के लिए ऐसे आसान मान पहले निकालें।
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यदि (f(x)=x-2 +4x), तो (f(-4)) का मान क्या है?
If (f(x)=x-2 +4x), what is the value of (f(-4))?
#substitution
#zero-of-polynomial
#easy
A (0)
B (4)
C (-4)
D (16)
Explanation opens after your attempt
Step 1
Concept
(f(-4)=(-4)2 +4(-4)=16-16=0). Pay attention to signs while substituting negative values.
Step 2
Why this answer is correct
The correct answer is A. (0). (f(-4)=(-4)2 +4(-4)=16-16=0). Pay attention to signs while substituting negative values.
Step 3
Exam Tip
(f(-4)=(-4)2 +4(-4)=16-16=0) है। ऋणात्मक मान रखते समय चिह्नों पर ध्यान दें।
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बहुपद \(x^2-9\) का कौन सा मान शून्यक है?
Which value is a zero of the polynomial \(x^2-9\)?
#polynomials
#zero
#quadratic
#easy
A (2)
B (3)
C (4)
D (9)
Explanation opens after your attempt
Step 1
Concept
\(3^2-9=0\), so (3) is a zero. Substituting options is an easy method.
Step 2
Why this answer is correct
The correct answer is B. (3). \(3^2-9=0\), so (3) is a zero. Substituting options is an easy method.
Step 3
Exam Tip
\(3^2-9=0\), इसलिए (3) शून्यक है। विकल्पों को रखकर जांचना आसान तरीका है।
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कौन सा मान (p(x)=x+4) का शून्यक है?
Which value is a zero of (p(x)=x+4)?
#polynomials
#zero
#linear
#easy
A (4)
B (-4)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
(p(-4)=-4+4=0), so (-4) is the zero. For (x+a), the zero is (-a).
Step 2
Why this answer is correct
The correct answer is B. (-4). (p(-4)=-4+4=0), so (-4) is the zero. For (x+a), the zero is (-a).
Step 3
Exam Tip
(p(-4)=-4+4=0), इसलिए (-4) शून्यक है। रैखिक बहुपद (x+a) का शून्यक (-a) होता है।
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समीकरण \(x^2-3x+2=0\) के लिए (D) का मान क्या है?
What is the value of (D) for the equation \(x^2-3x+2=0\)?
#quadratic equations
#discriminant
#easy numerical
A (1)
B (5)
C (0)
D (-1)
Explanation opens after your attempt
Step 1
Concept
Here (D=(-3)2 -4(1)(2)=1). Hence (D) is a positive perfect square.
Step 2
Why this answer is correct
The correct answer is A. (1). Here (D=(-3)2 -4(1)(2)=1). Hence (D) is a positive perfect square.
Step 3
Exam Tip
यहाँ (D=(-3)2 -4(1)(2)=1) है। इसलिए (D) धनात्मक पूर्ण वर्ग है।
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रेखा (y=3x-12) का (x)-अक्ष से कटाव किस (x)-मान पर होगा?
At which (x)-value will the line (y=3x-12) cut the (x)-axis?
#linear-polynomial
#x-intercept
#zero
#easy
A (4)
B (-4)
C (12)
D (3)
Explanation opens after your attempt
Step 1
Concept
On the (x)-axis, (y=0), so (3x-12=0) gives (x=4). This is the zero.
Step 2
Why this answer is correct
The correct answer is A. (4). On the (x)-axis, (y=0), so (3x-12=0) gives (x=4). This is the zero.
Step 3
Exam Tip
(x)-अक्ष पर (y=0), इसलिए (3x-12=0) से (x=4) मिलता है। यही शून्यक है।
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यदि ग्राफ (x)-अक्ष को ((-4,0)) पर काटता है, तो कौन-सा मान बहुपद को शून्य बनाता है?
If a graph cuts the (x)-axis at ((-4,0)), which value makes the polynomial zero?
#negative-x-intercept
#zeroes
#graph
#easy
A (-4)
B (4)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
The (x)-coordinate of the intersection point is (-4). Therefore the polynomial value is (0) at (x=-4).
Step 2
Why this answer is correct
The correct answer is A. (-4). The (x)-coordinate of the intersection point is (-4). Therefore the polynomial value is (0) at (x=-4).
Step 3
Exam Tip
कटाव बिंदु का (x)-निर्देशांक (-4) है। इसलिए (x=-4) पर बहुपद का मान (0) होगा।
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यदि \(m=3^2\times5^2\), तो (m) का मान क्या है?
If \(m=3^2\times5^2\), what is the value of (m)?
#evaluate-factorisation
#powers
#easy
A 225
B 150
C 300
D 450
Explanation opens after your attempt
Step 1
Concept
\(3^2=9\) and \(5^2=25\).
Step 2
Why this answer is correct
\(9\times25=225\).
Step 3
Exam Tip
Simplify both powers first. चरण 1: \(3^2=9\) और \(5^2=25\) हैं। चरण 2: \(9\times25=225\)। चरण 3: दोनों घातों को पहले सरल करें।
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यदि \(n=2^3\times3\times7\), तो (n) का मान क्या है?
If \(n=2^3\times3\times7\), what is the value of (n)?
#evaluate-factorisation
#powers
#easy
A 168
B 84
C 126
D 336
Explanation opens after your attempt
Step 1
Concept
\(2^3=8\).
Step 2
Why this answer is correct
\(8\times3\times7=168\).
Step 3
Exam Tip
Multiply to get the number from prime factorisation. चरण 1: \(2^3=8\) है। चरण 2: \(8\times3\times7=168\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए गुणा करें।
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यदि \(675=3^a\times5^2\), तो (a) का मान क्या है?
If \(675=3^a\times5^2\), what is the value of (a)?
#exponent-comparison
#prime-factorisation
#easy
A 3
B 2
C 4
D 5
Explanation opens after your attempt
Step 1
Concept
\(675=27\times25\).
Step 2
Why this answer is correct
\(27=3^3\) and \(25=5^2\), so \(675=3^3\times5^2\).
Step 3
Exam Tip
Comparing gives (a=3). चरण 1: \(675=27\times25\) है। चरण 2: \(27=3^3\) और \(25=5^2\), इसलिए \(675=3^3\times5^2\)। चरण 3: तुलना करने पर (a=3) है।
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यदि \(600=2^a\times3\times5^2\), तो (a) का मान क्या है?
If \(600=2^a\times3\times5^2\), what is the value of (a)?
#exponent-comparison
#prime-factorisation
#easy
A 3
B 2
C 4
D 5
Explanation opens after your attempt
Step 1
Concept
The prime factorisation of 600 is \(2^3\times3\times5^2\).
Step 2
Why this answer is correct
In the given form, the power of 2 is (a).
Step 3
Exam Tip
Comparing gives (a=3). चरण 1: 600 का अभाज्य गुणनखंडन \(2^3\times3\times5^2\) है। चरण 2: दिए गए रूप में 2 की घात (a) है। चरण 3: तुलना करने पर (a=3) मिलता है।
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यदि \(m=3^2\times5\times7\), तो (m) का मान क्या है?
If \(m=3^2\times5\times7\), what is the value of (m)?
#evaluate-factorisation
#powers
#easy
A 315
B 210
C 175
D 420
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^2=9\).
Step 2
Why this answer is correct
\(9\times5\times7=315\).
Step 3
Exam Tip
Simplify the factor with a power first. चरण 1: \(3^2=9\) निकालें। चरण 2: \(9\times5\times7=315\)। चरण 3: घात वाले गुणनखंड को पहले सरल करें।
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यदि \(n=2^4\times3\times5\), तो (n) का मान क्या है?
If \(n=2^4\times3\times5\), what is the value of (n)?
#evaluate-factorisation
#powers
#easy
A 240
B 120
C 180
D 300
Explanation opens after your attempt
Step 1
Concept
\(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times5=240\).
Step 3
Exam Tip
Multiply to get the number from prime form. चरण 1: \(2^4=16\) है। चरण 2: \(16\times3\times5=240\)। चरण 3: अभाज्य रूप से संख्या पाने के लिए गुणा करें।
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यदि \(150=2\times3\times5^b\), तो (b) का मान क्या है?
If \(150=2\times3\times5^b\), what is the value of (b)?
#exponent-comparison
#prime-factorisation
#easy
A 2
B 1
C 3
D 4
Explanation opens after your attempt
Step 1
Concept
The prime factorisation of 150 is \(2\times3\times5^2\).
Step 2
Why this answer is correct
In the given form, the power of 5 is (b).
Step 3
Exam Tip
Comparing gives (b=2). चरण 1: 150 का अभाज्य गुणनखंडन \(2\times3\times5^2\) है। चरण 2: दिए गए रूप में 5 की घात (b) है। चरण 3: तुलना करने पर (b=2) है।
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यदि \(132=2^a\times3\times11\), तो (a) का मान क्या है?
If \(132=2^a\times3\times11\), what is the value of (a)?
#exponent-comparison
#prime-factorisation
#easy
A 2
B 1
C 3
D 4
Explanation opens after your attempt
Step 1
Concept
The prime factorisation of 132 is \(2^2\times3\times11\).
Step 2
Why this answer is correct
In the given form, the power of 2 is (a).
Step 3
Exam Tip
Comparing gives (a=2). चरण 1: 132 का अभाज्य गुणनखंडन \(2^2\times3\times11\) है। चरण 2: दिए गए रूप में 2 की घात (a) है। चरण 3: तुलना करने पर (a=2) मिलता है।
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यदि \(m=3^2\times7\), तो (m) का मान क्या है?
If \(m=3^2\times7\), what is the value of (m)?
#evaluate-factorisation
#powers
#easy
A 63
B 42
C 72
D 84
Explanation opens after your attempt
Step 1
Concept
\(3^2=9\).
Step 2
Why this answer is correct
\(9\times7=63\).
Step 3
Exam Tip
In an expression with powers, evaluate the power first. चरण 1: \(3^2=9\) है। चरण 2: \(9\times7=63\)। चरण 3: घात वाले रूप में पहले घात का मान निकालें।
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यदि \(n=2^3\times5\), तो (n) का मान क्या है?
If \(n=2^3\times5\), what is the value of (n)?
#evaluate-factorisation
#powers
#easy
A 40
B 30
C 20
D 50
Explanation opens after your attempt
Step 1
Concept
\(2^3=8\).
Step 2
Why this answer is correct
\(8\times5=40\).
Step 3
Exam Tip
Multiply the factors to convert prime factorisation into the number. चरण 1: \(2^3=8\) है। चरण 2: \(8\times5=40\)। चरण 3: अभाज्य गुणनखंडन को संख्या में बदलने के लिए गुणा करें।
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