A. संसाधनों की मात्रा स्थान और उपयोग समझने के लिए/To understand quantity location and use of resources
Step 1
Concept
Balanced planning is difficult without correct information. Exam tip: write the relation between survey and planning.
Step 2
Why this answer is correct
The correct answer is A. संसाधनों की मात्रा स्थान और उपयोग समझने के लिए / To understand quantity location and use of resources. Balanced planning is difficult without correct information. Exam tip: write the relation between survey and planning.
Step 3
Exam Tip
सही जानकारी के बिना संतुलित योजना कठिन होती है। परीक्षा में सर्वेक्षण और योजना का संबंध लिखें।
A. क्योंकि डेटा निर्णय अर्थव्यवस्था और नियंत्रण को प्रभावित करता है/Because data affects decisions economy and control
Step 1
Concept
In the digital age information and data become economic and social power. For exams see the relation between knowledge and power.
Step 2
Why this answer is correct
The correct answer is A. क्योंकि डेटा निर्णय अर्थव्यवस्था और नियंत्रण को प्रभावित करता है / Because data affects decisions economy and control. In the digital age information and data become economic and social power. For exams see the relation between knowledge and power.
Step 3
Exam Tip
डिजिटल युग में सूचना और डेटा आर्थिक और सामाजिक शक्ति बनते हैं। परीक्षा में ज्ञान और शक्ति का संबंध देखें।
Substituting ((2,8)) gives \(13\cdot2+4\cdot8=58\), not (52). Check every point in the equation before drawing the graph.
Step 2
Why this answer is correct
The correct answer is D. ((2,8)). Substituting ((2,8)) gives \(13\cdot2+4\cdot8=58\), not (52). Check every point in the equation before drawing the graph.
Step 3
Exam Tip
((2,8)) रखने पर \(13\cdot2+4\cdot8=58\), जो (52) नहीं है। ग्राफ बनाने से पहले हर बिंदु को समीकरण में जांचें।
Substituting ((-4,1)) makes (x+y=-3) and (2x-y=-9) both true. Substituting the intersection point in both equations is the fastest check.
Step 2
Why this answer is correct
The correct answer is A. (x+y=-3), (2x-y=-9). Substituting ((-4,1)) makes (x+y=-3) and (2x-y=-9) both true. Substituting the intersection point in both equations is the fastest check.
Step 3
Exam Tip
((-4,1)) रखने पर (x+y=-3) और (2x-y=-9) दोनों सही हैं। प्रतिच्छेद बिंदु को दोनों समीकरणों में रखना सबसे तेज जांच है।
Substituting ((4,3)) gives (2x+5y=31) but not (3x-y=7); the true common point is (\left\(\frac{66}{17},\frac{79}{17}\right\)). Verify in both equations before choosing.
Step 2
Why this answer is correct
The correct answer is A. ((4,3)). Substituting ((4,3)) gives (2x+5y=31) but not (3x-y=7); the true common point is (\left\(\frac{66}{17},\frac{79}{17}\right\)). Verify in both equations before choosing.
Step 3
Exam Tip
((4,3)) रखने पर (2x+5y=31) और (3x-y=9) नहीं; सही साझा बिंदु (\left\(\frac{66}{17},\frac{79}{17}\right\)) है। सही उत्तर चुनने से पहले दोनों समीकरणों में जांच करें।
Substituting ((4,3)) does not give (2x+5y=29), so it is not correct; the true solution is (\left\(\frac{64}{17},\frac{73}{17}\right\)). Check a point in both equations.
Step 2
Why this answer is correct
The correct answer is C. ((4,3)). Substituting ((4,3)) does not give (2x+5y=29), so it is not correct; the true solution is (\left\(\frac{64}{17},\frac{73}{17}\right\)). Check a point in both equations.
Step 3
Exam Tip
((4,3)) रखने पर (2x+5y=23) नहीं, इसलिए यह गलत होता; सही हल (\left\(\frac{64}{17},\frac{73}{17}\right\)) है। विकल्प जांचते समय दोनों समीकरणों में बिंदु रखना जरूरी है।
Substituting ((-1,6)) makes (2x+y=4) and (x-y=-7) both true. The intersection point must lie on both lines.
Step 2
Why this answer is correct
The correct answer is A. (2x+y=4), (x-y=-7). Substituting ((-1,6)) makes (2x+y=4) and (x-y=-7) both true. The intersection point must lie on both lines.
Step 3
Exam Tip
((-1,6)) रखने पर (2x+y=4) और (x-y=-7) दोनों सही हैं। प्रतिच्छेद बिंदु दोनों रेखाओं पर होना चाहिए।
B. केवल ((10,0)) और ((0,12)) रेखा पर हैं/Only ((10,0)) and ((0,12)) lie on the line
Step 1
Concept
((10,0)) and ((0,12)) satisfy the equation, but ((5,6)) does not give (60). Check points before drawing the graph.
Step 2
Why this answer is correct
The correct answer is B. केवल ((10,0)) और ((0,12)) रेखा पर हैं / Only ((10,0)) and ((0,12)) lie on the line. ((10,0)) and ((0,12)) satisfy the equation, but ((5,6)) does not give (60). Check points before drawing the graph.
Step 3
Exam Tip
((10,0)) और ((0,12)) समीकरण को संतुष्ट करते हैं, लेकिन ((5,6)) देने पर (60) नहीं मिलता। ग्राफ बनाने से पहले बिंदुओं की जांच करें।
Substituting (\left\(\frac{5}{2},-\frac{3}{2}\right\)) makes both \(2x+y=\frac{7}{2}\) and \(x-2y=\frac{11}{2}\) true. Check the intersection point in both equations.
Step 2
Why this answer is correct
The correct answer is A. \(2x+y=\frac{7}{2}\), \(x-2y=\frac{11}{2}\). Substituting (\left\(\frac{5}{2},-\frac{3}{2}\right\)) makes both \(2x+y=\frac{7}{2}\) and \(x-2y=\frac{11}{2}\) true. Check the intersection point in both equations.
Step 3
Exam Tip
(\left\(\frac{5}{2},-\frac{3}{2}\right\)) रखने पर \(2x+y=\frac{7}{2}\) और \(x-2y=\frac{11}{2}\) दोनों सत्य हैं। प्रतिच्छेद बिंदु को दोनों समीकरणों में जांचें।
Substituting ((0,4)) gives \(4\cdot0-9\cdot4=-36\), not (36). Check every point in the equation before drawing the graph.
Step 2
Why this answer is correct
The correct answer is D. ((0,4)). Substituting ((0,4)) gives \(4\cdot0-9\cdot4=-36\), not (36). Check every point in the equation before drawing the graph.
Step 3
Exam Tip
((0,4)) रखने पर \(4\cdot0-9\cdot4=-36\), जो (36) नहीं है। ग्राफ बनाने से पहले हर बिंदु को समीकरण में जांचें।
Substituting ((-2,-3)) makes (x+y=-5) and (2x-y=-1) both true. Substituting the intersection point in both equations is the fastest check.
Step 2
Why this answer is correct
The correct answer is A. (x+y=-5), (2x-y=-1). Substituting ((-2,-3)) makes (x+y=-5) and (2x-y=-1) both true. Substituting the intersection point in both equations is the fastest check.
Step 3
Exam Tip
((-2,-3)) रखने पर (x+y=-5) और (2x-y=-1) दोनों सही हैं। प्रतिच्छेद बिंदु को दोनों समीकरणों में रखना सबसे तेज जांच है।
Substituting ((3,5)) gives (3x+y=14) but (x-2y=-7), so it is not correct; the true common point is (\left\(\frac{23}{7},\frac{29}{7}\right\)). Detecting option errors is also important.
Step 2
Why this answer is correct
The correct answer is A. ((3,5)). Substituting ((3,5)) gives (3x+y=14) but (x-2y=-7), so it is not correct; the true common point is (\left\(\frac{23}{7},\frac{29}{7}\right\)). Detecting option errors is also important.
Step 3
Exam Tip
((3,5)) रखने पर (3x+y=14) और (x-2y=-7), इसलिए यह नहीं; सही साझा बिंदु (\left\(\frac{23}{7},\frac{29}{7}\right\)) है। विकल्पों की जांच में गलती पकड़ना भी महत्वपूर्ण है।
A. तीनों बिंदु रेखा पर हैं/All three points lie on the line
Step 1
Concept
Substituting all three points makes (5x+4y=40) true. In a graph, three correct points should lie on the same straight line.
Step 2
Why this answer is correct
The correct answer is A. तीनों बिंदु रेखा पर हैं / All three points lie on the line. Substituting all three points makes (5x+4y=40) true. In a graph, three correct points should lie on the same straight line.
Step 3
Exam Tip
तीनों बिंदु रखने पर (5x+4y=40) सत्य मिलता है। ग्राफ में तीन सही बिंदु एक ही सीधी रेखा पर आने चाहिए।
Substituting (\left\(-\frac{3}{2},4\right\)) makes both (2x+y=1) and \(x+2y=\frac{13}{2}\) true. The intersection point should be checked in both equations.
Step 2
Why this answer is correct
The correct answer is A. (2x+y=1), \(x+2y=\frac{13}{2}\). Substituting (\left\(-\frac{3}{2},4\right\)) makes both (2x+y=1) and \(x+2y=\frac{13}{2}\) true. The intersection point should be checked in both equations.
Step 3
Exam Tip
(\left\(-\frac{3}{2},4\right\)) रखने पर (2x+y=1) और \(x+2y=\frac{13}{2}\) दोनों सत्य हैं। प्रतिच्छेद बिंदु को दोनों समीकरणों में जांचना चाहिए।
Substituting ((-3,2)) makes (x+y=-1) and (2x-y=-8) true. Substituting the intersection point in both equations is the fastest check.
Step 2
Why this answer is correct
The correct answer is A. (x+y=-1), (2x-y=-8). Substituting ((-3,2)) makes (x+y=-1) and (2x-y=-8) true. Substituting the intersection point in both equations is the fastest check.
Step 3
Exam Tip
((-3,2)) रखने पर (x+y=-1) और (2x-y=-8) दोनों सही हैं। प्रतिच्छेद बिंदु को दोनों समीकरणों में रखना सबसे तेज जांच है।
B. केवल ((6,0)) और ((0,8)) रेखा पर हैं/Only ((6,0)) and ((0,8)) lie on the line
Step 1
Concept
((6,0)) and ((0,8)) satisfy the equation, but ((3,4)) does not give (24). Check points before plotting the graph.
Step 2
Why this answer is correct
The correct answer is B. केवल ((6,0)) और ((0,8)) रेखा पर हैं / Only ((6,0)) and ((0,8)) lie on the line. ((6,0)) and ((0,8)) satisfy the equation, but ((3,4)) does not give (24). Check points before plotting the graph.
Step 3
Exam Tip
((6,0)) और ((0,8)) समीकरण को संतुष्ट करते हैं, लेकिन ((3,4)) देने पर (24) नहीं मिलता। ग्राफ से पहले बिंदुओं की जांच करें।
Substituting (\left\(\frac{7}{2},-\frac{1}{2}\right\)) makes (x-y=4) and \(2x+y=\frac{13}{2}\) true. Check the point in both equations.
Step 2
Why this answer is correct
The correct answer is A. (x-y=4), \(2x+y=\frac{13}{2}\). Substituting (\left\(\frac{7}{2},-\frac{1}{2}\right\)) makes (x-y=4) and \(2x+y=\frac{13}{2}\) true. Check the point in both equations.
Step 3
Exam Tip
(\left\(\frac{7}{2},-\frac{1}{2}\right\)) रखने पर (x-y=4) और \(2x+y=\frac{13}{2}\) सत्य हैं। विकल्पों में बिंदु को दोनों समीकरणों में जांचें।
A. ((2,-3)) दोनों समीकरणों को संतुष्ट करता है/((2,-3)) satisfies both equations
Step 1
Concept
The intersection point always lies on both lines, so it satisfies both equations. A graphical solution can always be checked in both equations.
Step 2
Why this answer is correct
The correct answer is A. ((2,-3)) दोनों समीकरणों को संतुष्ट करता है / ((2,-3)) satisfies both equations. The intersection point always lies on both lines, so it satisfies both equations. A graphical solution can always be checked in both equations.
Step 3
Exam Tip
प्रतिच्छेद बिंदु हमेशा दोनों रेखाओं पर होता है, इसलिए वह दोनों समीकरणों को संतुष्ट करता है। ग्राफीय समाधान को हमेशा दोनों समीकरणों में जांच सकते हैं।
A. बिंदु (\left\(2,5\right\))/Point (\left\(2,5\right\))
Step 1
Concept
At (\left\(2,5\right\)), (3\left\(2\right\)+4\left\(5\right\)=26), but (2+5=7) also, so check fully. The correct non-common point is (\left\(4,\frac{7}{2}\right\)).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(2,5\right\)) / Point (\left\(2,5\right\)). At (\left\(2,5\right\)), (3\left\(2\right\)+4\left\(5\right\)=26), but (2+5=7) also, so check fully. The correct non-common point is (\left\(4,\frac{7}{2}\right\)).
Step 3
Exam Tip
(\left\(2,5\right\)) पर (3\left\(2\right\)+4\left\(5\right\)=26), लेकिन (2+5=7) भी है, इसलिए जाँच पूरी करें। सही अलग बिंदु (\left\(4,\frac{7}{2}\right\)) है।
A. बिंदु (\left\(1,5\right\))/Point (\left\(1,5\right\))
Step 1
Concept
At (\left\(1,5\right\)), (2\left\(1\right\)+5\left\(5\right\)=27), but (1+5=6). To be a common solution, both equations must be true.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(1,5\right\)) / Point (\left\(1,5\right\)). At (\left\(1,5\right\)), (2\left\(1\right\)+5\left\(5\right\)=27), but (1+5=6). To be a common solution, both equations must be true.
Step 3
Exam Tip
(\left\(1,5\right\)) पर (2\left\(1\right\)+5\left\(5\right\)=27), लेकिन (1+5=6)। सामान्य हल बनने के लिए दोनों समीकरण सत्य होने चाहिए।
B. बिंदु (\left\(3,6\right\))/Point (\left\(3,6\right\))
Step 1
Concept
At (\left\(3,6\right\)), (2\left\(3\right\)+3\left\(6\right\)=24), but (3+6=9). For a common solution, both equations must be true.
Step 2
Why this answer is correct
The correct answer is B. बिंदु (\left\(3,6\right\)) / Point (\left\(3,6\right\)). At (\left\(3,6\right\)), (2\left\(3\right\)+3\left\(6\right\)=24), but (3+6=9). For a common solution, both equations must be true.
Step 3
Exam Tip
(\left\(3,6\right\)) पर (2\left\(3\right\)+3\left\(6\right\)=24), लेकिन (3+6=9)। सामान्य हल के लिए दोनों समीकरण सत्य होने चाहिए।
B. बिंदु (\left\(3,2\right\))/Point (\left\(3,2\right\))
Step 1
Concept
At (\left\(3,2\right\)), (3-2\left\(2\right\)=-1), so it is not correct. The correct solution is (\left\(\frac{18}{7},\frac{23}{7}\right\)).
Step 2
Why this answer is correct
The correct answer is B. बिंदु (\left\(3,2\right\)) / Point (\left\(3,2\right\)). At (\left\(3,2\right\)), (3-2\left\(2\right\)=-1), so it is not correct. The correct solution is (\left\(\frac{18}{7},\frac{23}{7}\right\)).
Step 3
Exam Tip
(\left\(3,2\right\)) पर (3-2\left\(2\right\)=-1) है इसलिए यह नहीं है। सही हल (\left\(\frac{18}{7},\frac{23}{7}\right\)) है।
B. बिंदु (\left\(4,3\right\))/Point (\left\(4,3\right\))
Step 1
Concept
At (\left\(4,3\right\)), (4+3\left\(3\right\)=13), so check options carefully. The correct intersection is (\left\(\frac{24}{7},\frac{27}{7}\right\)).
Step 2
Why this answer is correct
The correct answer is B. बिंदु (\left\(4,3\right\)) / Point (\left\(4,3\right\)). At (\left\(4,3\right\)), (4+3\left\(3\right\)=13), so check options carefully. The correct intersection is (\left\(\frac{24}{7},\frac{27}{7}\right\)).
Step 3
Exam Tip
(\left\(4,3\right\)) पर (4+3\left\(3\right\)=13) नहीं है इसलिए विकल्प जाँचें। सही प्रतिच्छेद (\left\(\frac{24}{7},\frac{27}{7}\right\)) है।
Substituting ( (4,3) ) gives (4(4)-3=13), so checking is necessary. The correct solution is ( \left\(\frac{18}{5},\frac{17}{5}\right\) ).
Step 2
Why this answer is correct
The correct answer is C. ( (4,3) ). Substituting ( (4,3) ) gives (4(4)-3=13), so checking is necessary. The correct solution is ( \left\(\frac{18}{5},\frac{17}{5}\right\) ).
Step 3
Exam Tip
( (4,3) ) रखने पर (4(4)-3=13) नहीं है, इसलिए जाँच जरूरी है। सही हल ( \left\(\frac{18}{5},\frac{17}{5}\right\) ) है।
Putting ( (3,2) ) gives (2(3)+3(2)=12), so it is not correct. The correct solution is ( \(\frac{21}{5},\frac{16}{5}\) ), so recalculation is needed in such options.
Step 2
Why this answer is correct
The correct answer is A. ( (3,2) ). Putting ( (3,2) ) gives (2(3)+3(2)=12), so it is not correct. The correct solution is ( \(\frac{21}{5},\frac{16}{5}\) ), so recalculation is needed in such options.
Step 3
Exam Tip
( (3,2) ) रखने पर (2(3)+3(2)=12) है, इसलिए यह भी सही नहीं है। सही हल ( \( \frac{21}{5},\frac{16}{5}\) ) होता है, अतः ऐसे विकल्पों में पुनः गणना जरूरी है।
At ( (5,1) ), (5+1=6) and (5-1=4). To check a solution substitute the point in both equations.
Step 2
Why this answer is correct
The correct answer is B. (x+y=6) और (x-y=4) / (x+y=6) and (x-y=4). At ( (5,1) ), (5+1=6) and (5-1=4). To check a solution substitute the point in both equations.
Step 3
Exam Tip
( (5,1) ) पर (5+1=6) और (5-1=4)। हल जाँचने के लिए दिए बिंदु को दोनों समीकरणों में रखें।
(5x-2-18x+9=(5x-3)(x-3)), so the roots are \(\frac{3}{5}\) and (3). In exams, verify the answer quickly by factorisation.
Step 2
Why this answer is correct
The correct answer is A. \(x=3,\frac{3}{5}\). (5x-2-18x+9=(5x-3)(x-3)), so the roots are \(\frac{3}{5}\) and (3). In exams, verify the answer quickly by factorisation.
Step 3
Exam Tip
(5x-2-18x+9=(5x-3)(x-3)), इसलिए मूल \(\frac{3}{5}\) और (3) हैं। परीक्षा में गुणनखंड विधि से उत्तर जल्दी जांचें।
(3x-2-10x+3=(3x-1)(x-3)), so the roots are \(\frac{1}{3}\) and (3). In exams, you may verify by completing square or factoring.
Step 2
Why this answer is correct
The correct answer is A. \(x=3,\frac{1}{3}\). (3x-2-10x+3=(3x-1)(x-3)), so the roots are \(\frac{1}{3}\) and (3). In exams, you may verify by completing square or factoring.
Step 3
Exam Tip
(3x-2-10x+3=(3x-1)(x-3)), इसलिए मूल \(\frac{1}{3}\) और (3) हैं। परीक्षा में पूर्ण वर्ग या गुणनखंड दोनों से जांच सकते हैं।
The sum of these roots is \(\frac{5t+3}{4}\), and the product is (\frac{t(t+3)}{4}). These match \(-\frac{b}{a}\) and \(\frac{c}{a}\) of the given equation.
Step 2
Why this answer is correct
The correct answer is A. हर (t) के लिए / For every (t). The sum of these roots is \(\frac{5t+3}{4}\), and the product is (\frac{t(t+3)}{4}). These match \(-\frac{b}{a}\) and \(\frac{c}{a}\) of the given equation.
Step 3
Exam Tip
इन जड़ों का योग \(\frac{5t+3}{4}\) और गुणनफल (\frac{t(t+3)}{4}) है। ये दिए गए समीकरण के \(-\frac{b}{a}\) और \(\frac{c}{a}\) से मेल खाते हैं।
Putting (x=8) gives (64-8(a+8)+8a=0). Hence (8) is always one root and the other root is (a).
Step 2
Why this answer is correct
The correct answer is A. (8) हमेशा एक जड़ है / (8) is always one root. Putting (x=8) gives (64-8(a+8)+8a=0). Hence (8) is always one root and the other root is (a).
Step 3
Exam Tip
(x=8) रखने पर (64-8(a+8)+8a=0) मिलता है। इसलिए (8) हमेशा एक जड़ है और दूसरी जड़ (a) है।
The sum of these two roots is \(\frac{4t+2}{3}\), and the product is (\frac{t(t+2)}{3}). These match \(-\frac{b}{a}\) and \(\frac{c}{a}\) of the given equation.
Step 2
Why this answer is correct
The correct answer is C. हर (t) पर / For every (t). The sum of these two roots is \(\frac{4t+2}{3}\), and the product is (\frac{t(t+2)}{3}). These match \(-\frac{b}{a}\) and \(\frac{c}{a}\) of the given equation.
Step 3
Exam Tip
इन दोनों जड़ों का योग \(\frac{4t+2}{3}\) और गुणनफल (\frac{t(t+2)}{3}) है। ये दिए गए समीकरण के \(-\frac{b}{a}\) और \(\frac{c}{a}\) से मेल खाते हैं।
Putting (x=6) gives (36-6(a+6)+6a=0). Hence (6) is always one root and the other root is (a).
Step 2
Why this answer is correct
The correct answer is B. (6) हमेशा जड़ है / (6) is always a root. Putting (x=6) gives (36-6(a+6)+6a=0). Hence (6) is always one root and the other root is (a).
Step 3
Exam Tip
(x=6) रखने पर (36-6(a+6)+6a=0) मिलता है। इसलिए (6) हमेशा एक जड़ है और दूसरी जड़ (a) है।
The sum is \(\frac{3t+1}{2}\) and the product is (\frac{t(t+1)}{2}). These match \(-\frac{b}{a}\) and \(\frac{c}{a}\) for every (t).
Step 2
Why this answer is correct
The correct answer is A. हर (t) के लिए / For every (t). The sum is \(\frac{3t+1}{2}\) and the product is (\frac{t(t+1)}{2}). These match \(-\frac{b}{a}\) and \(\frac{c}{a}\) for every (t).
Step 3
Exam Tip
इन जड़ों का योग \(\frac{3t+1}{2}\) और गुणनफल (\frac{t(t+1)}{2}) है। ये दिए गए समीकरण के \(-\frac{b}{a}\) और \(\frac{c}{a}\) से हर (t) पर मेल खाते हैं।
Putting (x=4) gives (16-4(a+4)+4a=0). Hence (4) is always one root and the other root is (a).
Step 2
Why this answer is correct
The correct answer is A. (4) हमेशा एक जड़ है / (4) is always a root. Putting (x=4) gives (16-4(a+4)+4a=0). Hence (4) is always one root and the other root is (a).
Step 3
Exam Tip
(x=4) रखने पर (16-4(a+4)+4a=0) मिलता है। अतः (4) हमेशा एक जड़ है और दूसरी जड़ (a) होती है।
Putting (x=3) gives (9-3(a+3)+3a=0). Hence (3) is always one root, and the other root is (a).
Step 2
Why this answer is correct
The correct answer is A. (3) हमेशा एक जड़ है / (3) is always a root. Putting (x=3) gives (9-3(a+3)+3a=0). Hence (3) is always one root, and the other root is (a).
Step 3
Exam Tip
(x=3) रखने पर (9-3(a+3)+3a=0) मिलता है। इसलिए (3) हमेशा एक जड़ है और दूसरी जड़ (a) होती है।
Since (p\(1+\sqrt{3}\)=0), \(1+\sqrt{3}\) is a zero. To prove a number is a zero, show that the polynomial value is (0).
Step 2
Why this answer is correct
The correct answer is A. यह (p(x)) का शून्यक है / It is a zero of (p(x)). Since (p\(1+\sqrt{3}\)=0), \(1+\sqrt{3}\) is a zero. To prove a number is a zero, show that the polynomial value is (0).
Step 3
Exam Tip
(p\(1+\sqrt{3}\)=0), इसलिए \(1+\sqrt{3}\) शून्यक है। किसी संख्या को शून्यक सिद्ध करने के लिए बहुपद का मान (0) दिखाएँ।
The National Mission on Cultural Mapping was launched in 2017. Link it with documentation of artists and cultural resources.
Step 2
Why this answer is correct
The correct answer is C. 2017 / 2017. The National Mission on Cultural Mapping was launched in 2017. Link it with documentation of artists and cultural resources.
Step 3
Exam Tip
राष्ट्रीय सांस्कृतिक मानचित्रण मिशन 2017 में शुरू हुआ था। इसे कलाकारों और सांस्कृतिक संसाधनों के दस्तावेजीकरण से जोड़ें।
