Which factorised form of the equation \(7x^2-19x-6=0\) is correct for solving it?
Answer and explanation
Correct answer: \((7x+2)(x-3)=0\)
Expanding option A gives \((7x+2)(x-3)=7x^2-21x+2x-6=7x^2-19x-6\), so it is the correct factorised form. Option B produces a middle term of \(+19x\), while options C and D produce \(-11x\) and \(+11x\), respectively. Exam tip: always expand the factors to verify the middle term and constant term.
Frequently asked questions
What is the correct answer to this question?
\((7x+2)(x-3)=0\)
Why is this the correct answer?
Expanding option A gives \((7x+2)(x-3)=7x^2-21x+2x-6=7x^2-19x-6\), so it is the correct factorised form. Option B produces a middle term of \(+19x\), while options C and D produce \(-11x\) and \(+11x\), respectively. Exam tip: always expand the factors to verify the middle term and constant term.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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