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Which point lies on both lines \(3x+y=14\) and \(x-2y=-5\)?
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Answer and explanation
Correct answer: ((3,5))
Substituting ((3,5)) gives \(3x+y=14\) but \(x-2y=-7\), so it is not correct; the true common point is \(\left(\frac{23}{7},\frac{29}{7}\right)\). Detecting option errors is also important.
Frequently asked questions
What is the correct answer to this question?
((3,5))
Why is this the correct answer?
Substituting ((3,5)) gives \(3x+y=14\) but \(x-2y=-7\), so it is not correct; the true common point is \(\left(\frac{23}{7},\frac{29}{7}\right)\). Detecting option errors is also important.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Graphical method of finding solutions..
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