Which of the following is the correct factorised form for solving the equation \(6x^2-11x-10=0\)?
Answer and explanation
Correct answer: \((3x+2)(2x-5)=0\)
Expanding option A gives \((3x+2)(2x-5)=6x^2-15x+4x-10=6x^2-11x-10\), so it is the correct factorised form. In option B, the middle term becomes \(+11x\), making it incorrect. In an exam, verify factorisation by expanding the factors and comparing the result with the original polynomial.
Frequently asked questions
What is the correct answer to this question?
\((3x+2)(2x-5)=0\)
Why is this the correct answer?
Expanding option A gives \((3x+2)(2x-5)=6x^2-15x+4x-10=6x^2-11x-10\), so it is the correct factorised form. In option B, the middle term becomes \(+11x\), making it incorrect. In an exam, verify factorisation by expanding the factors and comparing the result with the original polynomial.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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