यदि \(x^2-15x+56=0\), तो (x=7) रखने पर बायां पक्ष क्या बनेगा?

If \(x^2-15x+56=0\), what will the left side become when (x=7)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

\(7^2-15\cdot7+56=49-105+56=0\). If the left side becomes (0), the given value is a root.

Step 2

Why this answer is correct

The correct answer is A. (0). \(7^2-15\cdot7+56=49-105+56=0\). If the left side becomes (0), the given value is a root.

Step 3

Exam Tip

\(7^2-15\cdot7+56=49-105+56=0\) है। बायां पक्ष (0) हो तो दिया मान मूल है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2-15x+56=0\), तो (x=7) रखने पर बायां पक्ष क्या बनेगा? / If \(x^2-15x+56=0\), what will the left side become when (x=7)?

Correct Answer: A. (0). Explanation: \(7^2-15\cdot7+56=49-105+56=0\) है। बायां पक्ष (0) हो तो दिया मान मूल है। / \(7^2-15\cdot7+56=49-105+56=0\). If the left side becomes (0), the given value is a root.

Which concept should I revise for this Mathematics MCQ?

\(7^2-15\cdot7+56=49-105+56=0\). If the left side becomes (0), the given value is a root.

What exam hint can help solve this Mathematics question?

\(7^2-15\cdot7+56=49-105+56=0\) है। बायां पक्ष (0) हो तो दिया मान मूल है।