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Class 10MathematicsQuadratic EquationsRoots of a Quadratic EquationHardLevel 33
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If \(x=2\) is a root of the equation \(kx^2-6x+4=0\), what is the value of \(k\)?

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Answer and explanation

Correct answer: 2

A root must satisfy the equation. Substituting \(x=2\), we get \(k(2)^2-6(2)+4=0\), so \(4k-12+4=0\). Hence \(4k=8\) and \(k=2\). Therefore, option B is correct. Exam tip: Substitute the given root directly into the quadratic equation to find the unknown coefficient.

Related tags

Quadratic EquationsRoots Of Quadratic EquationsRoot VerificationUnknown CoefficientSubstitution

Frequently asked questions

What is the correct answer to this question?

2

Why is this the correct answer?

A root must satisfy the equation. Substituting \(x=2\), we get \(k(2)^2-6(2)+4=0\), so \(4k-12+4=0\). Hence \(4k=8\) and \(k=2\). Therefore, option B is correct. Exam tip: Substitute the given root directly into the quadratic equation to find the unknown coefficient.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.

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